Find the Exact Value 10^22((-10-1)^2)/11+202

$10^{2} \times 2 \frac{{(- 10 - 1)}^{2}}{11} + 20 \times 2$

Step 1

Simplify each term.

Simplify the numerator.

Subtract $1$ from $- 10$ .

$10^{2} \times 2 \frac{{(- 11)}^{2}}{11} + 20 \times 2$

Raise $- 11$ to the power of $2$ .

$10^{2} \times 2 \frac{121}{11} + 20 \times 2$

Raise $10$ to the power of $2$ .

$100 \times 2 \frac{121}{11} + 20 \times 2$

Multiply $100$ by $2$ .

$200 (\frac{121}{11}) + 20 \times 2$

Divide $121$ by $11$ .

$200 \cdot 11 + 20 \times 2$

Multiply $200$ by $11$ .

$2200 + 20 \times 2$

Multiply $20$ by $2$ .

$2200 + 40$

Step 2

Add $2200$ and $40$ .

$2240$

Find the Exact Value 10^2*2((-10-1)^2)/11+20*2