Find the Exact Value 10-4÷2+3*4-1

$10 - 4 \div 2 + 3 \times 4 - 1$

Step 1

Find the common denominator.

Write $10$ as a fraction with denominator $1$ .

$\frac{10}{1} - 4 \div 2 + 3 \times 4 - 1$

Multiply $\frac{10}{1}$ by $\frac{2}{2}$ .

$\frac{10}{1} \cdot \frac{2}{2} - 4 \div 2 + 3 \times 4 - 1$

Multiply $\frac{10}{1}$ by $\frac{2}{2}$ .

$\frac{10 \cdot 2}{2} - 4 \div 2 + 3 \times 4 - 1$

Write $3 \times 4$ as a fraction with denominator $1$ .

$\frac{10 \cdot 2}{2} - 4 \div 2 + \frac{3 \times 4}{1} - 1$

Multiply $\frac{3 \times 4}{1}$ by $\frac{2}{2}$ .

$\frac{10 \cdot 2}{2} - 4 \div 2 + \frac{3 \times 4}{1} \cdot \frac{2}{2} - 1$

Multiply $\frac{3 \times 4}{1}$ by $\frac{2}{2}$ .

$\frac{10 \cdot 2}{2} - 4 \div 2 + \frac{3 \times 4 \cdot 2}{2} - 1$

Write $- 1$ as a fraction with denominator $1$ .

$\frac{10 \cdot 2}{2} - 4 \div 2 + \frac{3 \times 4 \cdot 2}{2} + \frac{- 1}{1}$

Multiply $\frac{- 1}{1}$ by $\frac{2}{2}$ .

$\frac{10 \cdot 2}{2} - 4 \div 2 + \frac{3 \times 4 \cdot 2}{2} + \frac{- 1}{1} \cdot \frac{2}{2}$

Multiply $\frac{- 1}{1}$ by $\frac{2}{2}$ .

$\frac{10 \cdot 2}{2} - 4 \div 2 + \frac{3 \times 4 \cdot 2}{2} + \frac{- 1 \cdot 2}{2}$

Step 2

Combine the numerators over the common denominator.

$\frac{10 \cdot 2 - 4 + 3 \times 4 \cdot 2 - 1 \cdot 2}{2}$

Step 3

Simplify each term.

Multiply $10$ by $2$ .

$\frac{20 - 4 + 3 \times 4 \cdot 2 - 1 \cdot 2}{2}$

Multiply $3 \times 4 \cdot 2$ .

Multiply $3$ by $4$ .

$\frac{20 - 4 + 12 \cdot 2 - 1 \cdot 2}{2}$

Multiply $12$ by $2$ .

$\frac{20 - 4 + 24 - 1 \cdot 2}{2}$

Multiply $- 1$ by $2$ .

$\frac{20 - 4 + 24 - 2}{2}$

Step 4

Simplify the expression.

Subtract $4$ from $20$ .

$\frac{16 + 24 - 2}{2}$

Add $16$ and $24$ .

$\frac{40 - 2}{2}$

Subtract $2$ from $40$ .

$\frac{38}{2}$

Divide $38$ by $2$ .

$19$