Find the Exact Value 11-3*2+2^3+90÷6

$11 - 3 \cdot 2 + 2^{3} + 90 \div 6$

Find the common denominator.

Write $11$ as a fraction with denominator $1$ .

$\frac{11}{1} - 3 \cdot 2 + 2^{3} + 90 \div 6$

Multiply $\frac{11}{1}$ by $\frac{6}{6}$ .

$\frac{11}{1} \cdot \frac{6}{6} - 3 \cdot 2 + 2^{3} + 90 \div 6$

Multiply $\frac{11}{1}$ by $\frac{6}{6}$ .

$\frac{11 \cdot 6}{6} - 3 \cdot 2 + 2^{3} + 90 \div 6$

Write $- 3 \cdot 2$ as a fraction with denominator $1$ .

$\frac{11 \cdot 6}{6} + \frac{- 3 \cdot 2}{1} + 2^{3} + 90 \div 6$

Multiply $\frac{- 3 \cdot 2}{1}$ by $\frac{6}{6}$ .

$\frac{11 \cdot 6}{6} + \frac{- 3 \cdot 2}{1} \cdot \frac{6}{6} + 2^{3} + 90 \div 6$

Multiply $\frac{- 3 \cdot 2}{1}$ by $\frac{6}{6}$ .

$\frac{11 \cdot 6}{6} + \frac{- 3 \cdot 2 \cdot 6}{6} + 2^{3} + 90 \div 6$

Write $2^{3}$ as a fraction with denominator $1$ .

$\frac{11 \cdot 6}{6} + \frac{- 3 \cdot 2 \cdot 6}{6} + \frac{2^{3}}{1} + 90 \div 6$

Multiply $\frac{2^{3}}{1}$ by $\frac{6}{6}$ .

$\frac{11 \cdot 6}{6} + \frac{- 3 \cdot 2 \cdot 6}{6} + \frac{2^{3}}{1} \cdot \frac{6}{6} + 90 \div 6$

Multiply $\frac{2^{3}}{1}$ by $\frac{6}{6}$ .

$\frac{11 \cdot 6}{6} + \frac{- 3 \cdot 2 \cdot 6}{6} + \frac{2^{3} \cdot 6}{6} + 90 \div 6$

Combine the numerators over the common denominator.

$\frac{11 \cdot 6 - 3 \cdot 2 \cdot 6 + 2^{3} \cdot 6 + 90}{6}$

Simplify each term.

Multiply $11$ by $6$ .

$\frac{66 - 3 \cdot 2 \cdot 6 + 2^{3} \cdot 6 + 90}{6}$

Multiply $- 3$ by $2$ .

$\frac{66 - 6 \cdot 6 + 2^{3} \cdot 6 + 90}{6}$

Multiply $- 6$ by $6$ .

$\frac{66 - 36 + 2^{3} \cdot 6 + 90}{6}$

Raise $2$ to the power of $3$ .

$\frac{66 - 36 + 8 \cdot 6 + 90}{6}$

Multiply $8$ by $6$ .

$\frac{66 - 36 + 48 + 90}{6}$

Simplify the expression.

Subtract $36$ from $66$ .

$\frac{30 + 48 + 90}{6}$

Add $30$ and $48$ .

$\frac{78 + 90}{6}$

Add $78$ and $90$ .

$\frac{168}{6}$

Divide $168$ by $6$ .

$28$