Find the Exact Value (-2^3)^-2

${(- 2^{3})}^{- 2}$

Step 1

Raise $2$ to the power of $3$ .

${(- 1 \cdot 8)}^{- 2}$

Step 2

Multiply $- 1$ by $8$ .

${(- 8)}^{- 2}$

Step 3

Rewrite the expression using the negative exponent rule $b^{- n} = \frac{1}{b^{n}}$ .

$\frac{1}{{(- 8)}^{2}}$

Step 4

Raise $- 8$ to the power of $2$ .

$\frac{1}{64}$

Step 5

The result can be shown in multiple forms.

Exact Form:

$\frac{1}{64}$

Decimal Form:

$0.015625$