Find the Exact Value 2^3-3÷3+4

$2^{3} - 3 \div 3 + 4$

Step 1

Find the common denominator.

Write $2^{3}$ as a fraction with denominator $1$ .

$\frac{2^{3}}{1} - 3 \div 3 + 4$

Multiply $\frac{2^{3}}{1}$ by $\frac{3}{3}$ .

$\frac{2^{3}}{1} \cdot \frac{3}{3} - 3 \div 3 + 4$

Multiply $\frac{2^{3}}{1}$ by $\frac{3}{3}$ .

$\frac{2^{3} \cdot 3}{3} - 3 \div 3 + 4$

Write $4$ as a fraction with denominator $1$ .

$\frac{2^{3} \cdot 3}{3} - 3 \div 3 + \frac{4}{1}$

Multiply $\frac{4}{1}$ by $\frac{3}{3}$ .

$\frac{2^{3} \cdot 3}{3} - 3 \div 3 + \frac{4}{1} \cdot \frac{3}{3}$

Multiply $\frac{4}{1}$ by $\frac{3}{3}$ .

$\frac{2^{3} \cdot 3}{3} - 3 \div 3 + \frac{4 \cdot 3}{3}$

Step 2

Combine the numerators over the common denominator.

$\frac{2^{3} \cdot 3 - 3 + 4 \cdot 3}{3}$

Step 3

Simplify each term.

Raise $2$ to the power of $3$ .

$\frac{8 \cdot 3 - 3 + 4 \cdot 3}{3}$

Multiply $8$ by $3$ .

$\frac{24 - 3 + 4 \cdot 3}{3}$

Multiply $4$ by $3$ .

$\frac{24 - 3 + 12}{3}$

Step 4

Simplify the expression.

Subtract $3$ from $24$ .

$\frac{21 + 12}{3}$

Add $21$ and $12$ .

$\frac{33}{3}$

Divide $33$ by $3$ .

$11$