Find the Exact Value (2tan(pi/12))/(1-tan(pi/12)^2)

$\frac{2 \tan (\frac{π}{12})}{1 - \tan^{2} (\frac{π}{12})}$

The exact value of $\tan (\frac{π}{12})$ is $2 - \sqrt{3}$ .

Split $\frac{π}{12}$ into two angles where the values of the six trigonometric functions are known.

$\frac{2 \tan (\frac{π}{4} - \frac{π}{6})}{1 - \tan^{2} (\frac{π}{12})}$

Apply the difference of angles identity.

$\frac{2 \frac{\tan (\frac{π}{4}) - \tan (\frac{π}{6})}{1 + \tan (\frac{π}{4}) \tan (\frac{π}{6})}}{1 - \tan^{2} (\frac{π}{12})}$

The exact value of $\tan (\frac{π}{4})$ is $1$ .

$\frac{2 \frac{1 - \tan (\frac{π}{6})}{1 + \tan (\frac{π}{4}) \tan (\frac{π}{6})}}{1 - \tan^{2} (\frac{π}{12})}$

The exact value of $\tan (\frac{π}{6})$ is $\frac{\sqrt{3}}{3}$ .

$\frac{2 \frac{1 - \frac{\sqrt{3}}{3}}{1 + \tan (\frac{π}{4}) \tan (\frac{π}{6})}}{1 - \tan^{2} (\frac{π}{12})}$

The exact value of $\tan (\frac{π}{4})$ is $1$ .

$\frac{2 \frac{1 - \frac{\sqrt{3}}{3}}{1 + 1 \tan (\frac{π}{6})}}{1 - \tan^{2} (\frac{π}{12})}$

The exact value of $\tan (\frac{π}{6})$ is $\frac{\sqrt{3}}{3}$ .

$\frac{2 \frac{1 - \frac{\sqrt{3}}{3}}{1 + 1 \frac{\sqrt{3}}{3}}}{1 - \tan^{2} (\frac{π}{12})}$

Simplify $\frac{1 - \frac{\sqrt{3}}{3}}{1 + 1 \frac{\sqrt{3}}{3}}$ .

Multiply the numerator and denominator of the complex fraction by $3$ .

Multiply $\frac{1 - \frac{\sqrt{3}}{3}}{1 + 1 \frac{\sqrt{3}}{3}}$ by $\frac{3}{3}$ .

$\frac{2 (\frac{3}{3} \cdot \frac{1 - \frac{\sqrt{3}}{3}}{1 + 1 \frac{\sqrt{3}}{3}})}{1 - \tan^{2} (\frac{π}{12})}$

Combine.

$\frac{2 \frac{3 (1 - \frac{\sqrt{3}}{3})}{3 (1 + 1 \frac{\sqrt{3}}{3})}}{1 - \tan^{2} (\frac{π}{12})}$

Apply the distributive property.

$\frac{2 \frac{3 \cdot 1 + 3 (- \frac{\sqrt{3}}{3})}{3 \cdot 1 + 3 (1 \frac{\sqrt{3}}{3})}}{1 - \tan^{2} (\frac{π}{12})}$

Cancel the common factor of $3$ .

Move the leading negative in $- \frac{\sqrt{3}}{3}$ into the numerator.

$\frac{2 \frac{3 \cdot 1 + 3 \frac{- \sqrt{3}}{3}}{3 \cdot 1 + 3 (1 \frac{\sqrt{3}}{3})}}{1 - \tan^{2} (\frac{π}{12})}$

Cancel the common factor.

$\frac{2 \frac{3 \cdot 1 + 3 \frac{- \sqrt{3}}{3}}{3 \cdot 1 + 3 (1 \frac{\sqrt{3}}{3})}}{1 - \tan^{2} (\frac{π}{12})}$

Rewrite the expression.

$\frac{2 \frac{3 \cdot 1 - \sqrt{3}}{3 \cdot 1 + 3 (1 \frac{\sqrt{3}}{3})}}{1 - \tan^{2} (\frac{π}{12})}$

Multiply $3$ by $1$ .

$\frac{2 \frac{3 - \sqrt{3}}{3 \cdot 1 + 3 \cdot 1 \frac{\sqrt{3}}{3}}}{1 - \tan^{2} (\frac{π}{12})}$

Simplify the denominator.

Multiply $3$ by $1$ .

$\frac{2 \frac{3 - \sqrt{3}}{3 + 3 \cdot 1 \frac{\sqrt{3}}{3}}}{1 - \tan^{2} (\frac{π}{12})}$

Cancel the common factor of $3$ .

Factor $3$ out of $3 \cdot 1$ .

$\frac{2 \frac{3 - \sqrt{3}}{3 + 3 (1) \frac{\sqrt{3}}{3}}}{1 - \tan^{2} (\frac{π}{12})}$

Cancel the common factor.

$\frac{2 \frac{3 - \sqrt{3}}{3 + 3 \cdot 1 \frac{\sqrt{3}}{3}}}{1 - \tan^{2} (\frac{π}{12})}$

Rewrite the expression.

$\frac{2 \frac{3 - \sqrt{3}}{3 + \sqrt{3}}}{1 - \tan^{2} (\frac{π}{12})}$

Multiply $\frac{3 - \sqrt{3}}{3 + \sqrt{3}}$ by $\frac{3 - \sqrt{3}}{3 - \sqrt{3}}$ .

$\frac{2 (\frac{3 - \sqrt{3}}{3 + \sqrt{3}} \cdot \frac{3 - \sqrt{3}}{3 - \sqrt{3}})}{1 - \tan^{2} (\frac{π}{12})}$

Multiply $\frac{3 - \sqrt{3}}{3 + \sqrt{3}}$ by $\frac{3 - \sqrt{3}}{3 - \sqrt{3}}$ .

$\frac{2 \frac{(3 - \sqrt{3}) (3 - \sqrt{3})}{(3 + \sqrt{3}) (3 - \sqrt{3})}}{1 - \tan^{2} (\frac{π}{12})}$

Expand the denominator using the FOIL method.

$\frac{2 \frac{(3 - \sqrt{3}) (3 - \sqrt{3})}{9 - 3 \sqrt{3} + \sqrt{3} \cdot 3 - {\sqrt{3}}^{2}}}{1 - \tan^{2} (\frac{π}{12})}$

Simplify.

$\frac{2 \frac{(3 - \sqrt{3}) (3 - \sqrt{3})}{6}}{1 - \tan^{2} (\frac{π}{12})}$

Simplify the numerator.

Raise $3 - \sqrt{3}$ to the power of $1$ .

$\frac{2 \frac{{(3 - \sqrt{3})}^{1} (3 - \sqrt{3})}{6}}{1 - \tan^{2} (\frac{π}{12})}$

Raise $3 - \sqrt{3}$ to the power of $1$ .

$\frac{2 \frac{{(3 - \sqrt{3})}^{1} {(3 - \sqrt{3})}^{1}}{6}}{1 - \tan^{2} (\frac{π}{12})}$

Use the power rule $a^{m} a^{n} = a^{m + n}$ to combine exponents.

$\frac{2 \frac{{(3 - \sqrt{3})}^{1 + 1}}{6}}{1 - \tan^{2} (\frac{π}{12})}$

Add $1$ and $1$ .

$\frac{2 \frac{{(3 - \sqrt{3})}^{2}}{6}}{1 - \tan^{2} (\frac{π}{12})}$

Rewrite ${(3 - \sqrt{3})}^{2}$ as $(3 - \sqrt{3}) (3 - \sqrt{3})$ .

$\frac{2 \frac{(3 - \sqrt{3}) (3 - \sqrt{3})}{6}}{1 - \tan^{2} (\frac{π}{12})}$

Expand $(3 - \sqrt{3}) (3 - \sqrt{3})$ using the FOIL Method.

Apply the distributive property.

$\frac{2 \frac{3 (3 - \sqrt{3}) - \sqrt{3} (3 - \sqrt{3})}{6}}{1 - \tan^{2} (\frac{π}{12})}$

Apply the distributive property.

$\frac{2 \frac{3 \cdot 3 + 3 (- \sqrt{3}) - \sqrt{3} (3 - \sqrt{3})}{6}}{1 - \tan^{2} (\frac{π}{12})}$

Apply the distributive property.

$\frac{2 \frac{3 \cdot 3 + 3 (- \sqrt{3}) - \sqrt{3} \cdot 3 - \sqrt{3} (- \sqrt{3})}{6}}{1 - \tan^{2} (\frac{π}{12})}$

Simplify and combine like terms.

Simplify each term.

Multiply $3$ by $3$ .

$\frac{2 \frac{9 + 3 (- \sqrt{3}) - \sqrt{3} \cdot 3 - \sqrt{3} (- \sqrt{3})}{6}}{1 - \tan^{2} (\frac{π}{12})}$

Multiply $- 1$ by $3$ .

$\frac{2 \frac{9 - 3 \sqrt{3} - \sqrt{3} \cdot 3 - \sqrt{3} (- \sqrt{3})}{6}}{1 - \tan^{2} (\frac{π}{12})}$

Multiply $3$ by $- 1$ .

$\frac{2 \frac{9 - 3 \sqrt{3} - 3 \sqrt{3} - \sqrt{3} (- \sqrt{3})}{6}}{1 - \tan^{2} (\frac{π}{12})}$

Multiply $- \sqrt{3} (- \sqrt{3})$ .

Multiply $- 1$ by $- 1$ .

$\frac{2 \frac{9 - 3 \sqrt{3} - 3 \sqrt{3} + 1 \sqrt{3} \sqrt{3}}{6}}{1 - \tan^{2} (\frac{π}{12})}$

Multiply $\sqrt{3}$ by $1$ .

$\frac{2 \frac{9 - 3 \sqrt{3} - 3 \sqrt{3} + \sqrt{3} \sqrt{3}}{6}}{1 - \tan^{2} (\frac{π}{12})}$

Raise $\sqrt{3}$ to the power of $1$ .

$\frac{2 \frac{9 - 3 \sqrt{3} - 3 \sqrt{3} + {\sqrt{3}}^{1} \sqrt{3}}{6}}{1 - \tan^{2} (\frac{π}{12})}$

Raise $\sqrt{3}$ to the power of $1$ .

$\frac{2 \frac{9 - 3 \sqrt{3} - 3 \sqrt{3} + {\sqrt{3}}^{1} {\sqrt{3}}^{1}}{6}}{1 - \tan^{2} (\frac{π}{12})}$

Use the power rule $a^{m} a^{n} = a^{m + n}$ to combine exponents.

$\frac{2 \frac{9 - 3 \sqrt{3} - 3 \sqrt{3} + {\sqrt{3}}^{1 + 1}}{6}}{1 - \tan^{2} (\frac{π}{12})}$

Add $1$ and $1$ .

$\frac{2 \frac{9 - 3 \sqrt{3} - 3 \sqrt{3} + {\sqrt{3}}^{2}}{6}}{1 - \tan^{2} (\frac{π}{12})}$

Rewrite ${\sqrt{3}}^{2}$ as $3$ .

Use $\sqrt[n]{a^{x}} = a^{\frac{x}{n}}$ to rewrite $\sqrt{3}$ as $3^{\frac{1}{2}}$ .

$\frac{2 \frac{9 - 3 \sqrt{3} - 3 \sqrt{3} + {(3^{\frac{1}{2}})}^{2}}{6}}{1 - \tan^{2} (\frac{π}{12})}$

Apply the power rule and multiply exponents, ${(a^{m})}^{n} = a^{m n}$ .

$\frac{2 \frac{9 - 3 \sqrt{3} - 3 \sqrt{3} + 3^{\frac{1}{2} \cdot 2}}{6}}{1 - \tan^{2} (\frac{π}{12})}$

Combine $\frac{1}{2}$ and $2$ .

$\frac{2 \frac{9 - 3 \sqrt{3} - 3 \sqrt{3} + 3^{\frac{2}{2}}}{6}}{1 - \tan^{2} (\frac{π}{12})}$

Cancel the common factor of $2$ .

Cancel the common factor.

$\frac{2 \frac{9 - 3 \sqrt{3} - 3 \sqrt{3} + 3^{\frac{2}{2}}}{6}}{1 - \tan^{2} (\frac{π}{12})}$

Rewrite the expression.

$\frac{2 \frac{9 - 3 \sqrt{3} - 3 \sqrt{3} + 3^{1}}{6}}{1 - \tan^{2} (\frac{π}{12})}$

Evaluate the exponent.

$\frac{2 \frac{9 - 3 \sqrt{3} - 3 \sqrt{3} + 3}{6}}{1 - \tan^{2} (\frac{π}{12})}$

Add $9$ and $3$ .

$\frac{2 \frac{12 - 3 \sqrt{3} - 3 \sqrt{3}}{6}}{1 - \tan^{2} (\frac{π}{12})}$

Subtract $3 \sqrt{3}$ from $- 3 \sqrt{3}$ .

$\frac{2 \frac{12 - 6 \sqrt{3}}{6}}{1 - \tan^{2} (\frac{π}{12})}$

Cancel the common factor of $12 - 6 \sqrt{3}$ and $6$ .

Factor $6$ out of $12$ .

$\frac{2 \frac{6 \cdot 2 - 6 \sqrt{3}}{6}}{1 - \tan^{2} (\frac{π}{12})}$

Factor $6$ out of $- 6 \sqrt{3}$ .

$\frac{2 \frac{6 \cdot 2 + 6 (- \sqrt{3})}{6}}{1 - \tan^{2} (\frac{π}{12})}$

Factor $6$ out of $6 (2) + 6 (- \sqrt{3})$ .

$\frac{2 \frac{6 (2 - \sqrt{3})}{6}}{1 - \tan^{2} (\frac{π}{12})}$

Cancel the common factors.

Factor $6$ out of $6$ .

$\frac{2 \frac{6 (2 - \sqrt{3})}{6 (1)}}{1 - \tan^{2} (\frac{π}{12})}$

Cancel the common factor.

$\frac{2 \frac{6 (2 - \sqrt{3})}{6 \cdot 1}}{1 - \tan^{2} (\frac{π}{12})}$

Rewrite the expression.

$\frac{2 \frac{2 - \sqrt{3}}{1}}{1 - \tan^{2} (\frac{π}{12})}$

Divide $2 - \sqrt{3}$ by $1$ .

$\frac{2 (2 - \sqrt{3})}{1 - \tan^{2} (\frac{π}{12})}$

Simplify the denominator.

Rewrite $1$ as $1^{2}$ .

$\frac{2 (2 - \sqrt{3})}{1^{2} - \tan^{2} (\frac{π}{12})}$

Since both terms are perfect squares, factor using the difference of squares formula, $a^{2} - b^{2} = (a + b) (a - b)$ where $a = 1$ and $b = \tan (\frac{π}{12})$ .

$\frac{2 (2 - \sqrt{3})}{(1 + \tan (\frac{π}{12})) (1 - \tan (\frac{π}{12}))}$

Simplify.

The exact value of $\tan (\frac{π}{12})$ is $2 - \sqrt{3}$ .

Split $\frac{π}{12}$ into two angles where the values of the six trigonometric functions are known.

$\frac{2 (2 - \sqrt{3})}{(1 + \tan (\frac{π}{4} - \frac{π}{6})) (1 - \tan (\frac{π}{12}))}$

Apply the difference of angles identity.

$\frac{2 (2 - \sqrt{3})}{(1 + \frac{\tan (\frac{π}{4}) - \tan (\frac{π}{6})}{1 + \tan (\frac{π}{4}) \tan (\frac{π}{6})}) (1 - \tan (\frac{π}{12}))}$

The exact value of $\tan (\frac{π}{4})$ is $1$ .

$\frac{2 (2 - \sqrt{3})}{(1 + \frac{1 - \tan (\frac{π}{6})}{1 + \tan (\frac{π}{4}) \tan (\frac{π}{6})}) (1 - \tan (\frac{π}{12}))}$

The exact value of $\tan (\frac{π}{6})$ is $\frac{\sqrt{3}}{3}$ .

$\frac{2 (2 - \sqrt{3})}{(1 + \frac{1 - \frac{\sqrt{3}}{3}}{1 + \tan (\frac{π}{4}) \tan (\frac{π}{6})}) (1 - \tan (\frac{π}{12}))}$

The exact value of $\tan (\frac{π}{4})$ is $1$ .

$\frac{2 (2 - \sqrt{3})}{(1 + \frac{1 - \frac{\sqrt{3}}{3}}{1 + 1 \tan (\frac{π}{6})}) (1 - \tan (\frac{π}{12}))}$

The exact value of $\tan (\frac{π}{6})$ is $\frac{\sqrt{3}}{3}$ .

$\frac{2 (2 - \sqrt{3})}{(1 + \frac{1 - \frac{\sqrt{3}}{3}}{1 + 1 \frac{\sqrt{3}}{3}}) (1 - \tan (\frac{π}{12}))}$

Simplify $\frac{1 - \frac{\sqrt{3}}{3}}{1 + 1 \frac{\sqrt{3}}{3}}$ .

Multiply the numerator and denominator of the complex fraction by $3$ .

Multiply $\frac{1 - \frac{\sqrt{3}}{3}}{1 + 1 \frac{\sqrt{3}}{3}}$ by $\frac{3}{3}$ .

$\frac{2 (2 - \sqrt{3})}{(1 + \frac{3}{3} \cdot \frac{1 - \frac{\sqrt{3}}{3}}{1 + 1 \frac{\sqrt{3}}{3}}) (1 - \tan (\frac{π}{12}))}$

Combine.

$\frac{2 (2 - \sqrt{3})}{(1 + \frac{3 (1 - \frac{\sqrt{3}}{3})}{3 (1 + 1 \frac{\sqrt{3}}{3})}) (1 - \tan (\frac{π}{12}))}$

Apply the distributive property.

$\frac{2 (2 - \sqrt{3})}{(1 + \frac{3 \cdot 1 + 3 (- \frac{\sqrt{3}}{3})}{3 \cdot 1 + 3 (1 \frac{\sqrt{3}}{3})}) (1 - \tan (\frac{π}{12}))}$

Cancel the common factor of $3$ .

Move the leading negative in $- \frac{\sqrt{3}}{3}$ into the numerator.

$\frac{2 (2 - \sqrt{3})}{(1 + \frac{3 \cdot 1 + 3 \frac{- \sqrt{3}}{3}}{3 \cdot 1 + 3 (1 \frac{\sqrt{3}}{3})}) (1 - \tan (\frac{π}{12}))}$

Cancel the common factor.

$\frac{2 (2 - \sqrt{3})}{(1 + \frac{3 \cdot 1 + 3 \frac{- \sqrt{3}}{3}}{3 \cdot 1 + 3 (1 \frac{\sqrt{3}}{3})}) (1 - \tan (\frac{π}{12}))}$

Rewrite the expression.

$\frac{2 (2 - \sqrt{3})}{(1 + \frac{3 \cdot 1 - \sqrt{3}}{3 \cdot 1 + 3 (1 \frac{\sqrt{3}}{3})}) (1 - \tan (\frac{π}{12}))}$

Multiply $3$ by $1$ .

$\frac{2 (2 - \sqrt{3})}{(1 + \frac{3 - \sqrt{3}}{3 \cdot 1 + 3 \cdot 1 \frac{\sqrt{3}}{3}}) (1 - \tan (\frac{π}{12}))}$

Simplify the denominator.

Multiply $3$ by $1$ .

$\frac{2 (2 - \sqrt{3})}{(1 + \frac{3 - \sqrt{3}}{3 + 3 \cdot 1 \frac{\sqrt{3}}{3}}) (1 - \tan (\frac{π}{12}))}$

Cancel the common factor of $3$ .

Factor $3$ out of $3 \cdot 1$ .

$\frac{2 (2 - \sqrt{3})}{(1 + \frac{3 - \sqrt{3}}{3 + 3 (1) \frac{\sqrt{3}}{3}}) (1 - \tan (\frac{π}{12}))}$

Cancel the common factor.

$\frac{2 (2 - \sqrt{3})}{(1 + \frac{3 - \sqrt{3}}{3 + 3 \cdot 1 \frac{\sqrt{3}}{3}}) (1 - \tan (\frac{π}{12}))}$

Rewrite the expression.

$\frac{2 (2 - \sqrt{3})}{(1 + \frac{3 - \sqrt{3}}{3 + \sqrt{3}}) (1 - \tan (\frac{π}{12}))}$

Multiply $\frac{3 - \sqrt{3}}{3 + \sqrt{3}}$ by $\frac{3 - \sqrt{3}}{3 - \sqrt{3}}$ .

$\frac{2 (2 - \sqrt{3})}{(1 + \frac{3 - \sqrt{3}}{3 + \sqrt{3}} \cdot \frac{3 - \sqrt{3}}{3 - \sqrt{3}}) (1 - \tan (\frac{π}{12}))}$

Multiply $\frac{3 - \sqrt{3}}{3 + \sqrt{3}}$ by $\frac{3 - \sqrt{3}}{3 - \sqrt{3}}$ .

$\frac{2 (2 - \sqrt{3})}{(1 + \frac{(3 - \sqrt{3}) (3 - \sqrt{3})}{(3 + \sqrt{3}) (3 - \sqrt{3})}) (1 - \tan (\frac{π}{12}))}$

Expand the denominator using the FOIL method.

$\frac{2 (2 - \sqrt{3})}{(1 + \frac{(3 - \sqrt{3}) (3 - \sqrt{3})}{9 - 3 \sqrt{3} + \sqrt{3} \cdot 3 - {\sqrt{3}}^{2}}) (1 - \tan (\frac{π}{12}))}$

Simplify.

$\frac{2 (2 - \sqrt{3})}{(1 + \frac{(3 - \sqrt{3}) (3 - \sqrt{3})}{6}) (1 - \tan (\frac{π}{12}))}$

Simplify the numerator.

Raise $3 - \sqrt{3}$ to the power of $1$ .

$\frac{2 (2 - \sqrt{3})}{(1 + \frac{{(3 - \sqrt{3})}^{1} (3 - \sqrt{3})}{6}) (1 - \tan (\frac{π}{12}))}$

Raise $3 - \sqrt{3}$ to the power of $1$ .

$\frac{2 (2 - \sqrt{3})}{(1 + \frac{{(3 - \sqrt{3})}^{1} {(3 - \sqrt{3})}^{1}}{6}) (1 - \tan (\frac{π}{12}))}$

Use the power rule $a^{m} a^{n} = a^{m + n}$ to combine exponents.

$\frac{2 (2 - \sqrt{3})}{(1 + \frac{{(3 - \sqrt{3})}^{1 + 1}}{6}) (1 - \tan (\frac{π}{12}))}$

Add $1$ and $1$ .

$\frac{2 (2 - \sqrt{3})}{(1 + \frac{{(3 - \sqrt{3})}^{2}}{6}) (1 - \tan (\frac{π}{12}))}$

Rewrite ${(3 - \sqrt{3})}^{2}$ as $(3 - \sqrt{3}) (3 - \sqrt{3})$ .

$\frac{2 (2 - \sqrt{3})}{(1 + \frac{(3 - \sqrt{3}) (3 - \sqrt{3})}{6}) (1 - \tan (\frac{π}{12}))}$

Expand $(3 - \sqrt{3}) (3 - \sqrt{3})$ using the FOIL Method.

Apply the distributive property.

$\frac{2 (2 - \sqrt{3})}{(1 + \frac{3 (3 - \sqrt{3}) - \sqrt{3} (3 - \sqrt{3})}{6}) (1 - \tan (\frac{π}{12}))}$

Apply the distributive property.

$\frac{2 (2 - \sqrt{3})}{(1 + \frac{3 \cdot 3 + 3 (- \sqrt{3}) - \sqrt{3} (3 - \sqrt{3})}{6}) (1 - \tan (\frac{π}{12}))}$

Apply the distributive property.

$\frac{2 (2 - \sqrt{3})}{(1 + \frac{3 \cdot 3 + 3 (- \sqrt{3}) - \sqrt{3} \cdot 3 - \sqrt{3} (- \sqrt{3})}{6}) (1 - \tan (\frac{π}{12}))}$

Simplify and combine like terms.

Simplify each term.

Multiply $3$ by $3$ .

$\frac{2 (2 - \sqrt{3})}{(1 + \frac{9 + 3 (- \sqrt{3}) - \sqrt{3} \cdot 3 - \sqrt{3} (- \sqrt{3})}{6}) (1 - \tan (\frac{π}{12}))}$

Multiply $- 1$ by $3$ .

$\frac{2 (2 - \sqrt{3})}{(1 + \frac{9 - 3 \sqrt{3} - \sqrt{3} \cdot 3 - \sqrt{3} (- \sqrt{3})}{6}) (1 - \tan (\frac{π}{12}))}$

Multiply $3$ by $- 1$ .

$\frac{2 (2 - \sqrt{3})}{(1 + \frac{9 - 3 \sqrt{3} - 3 \sqrt{3} - \sqrt{3} (- \sqrt{3})}{6}) (1 - \tan (\frac{π}{12}))}$

Multiply $- \sqrt{3} (- \sqrt{3})$ .

Multiply $- 1$ by $- 1$ .

$\frac{2 (2 - \sqrt{3})}{(1 + \frac{9 - 3 \sqrt{3} - 3 \sqrt{3} + 1 \sqrt{3} \sqrt{3}}{6}) (1 - \tan (\frac{π}{12}))}$

Multiply $\sqrt{3}$ by $1$ .

$\frac{2 (2 - \sqrt{3})}{(1 + \frac{9 - 3 \sqrt{3} - 3 \sqrt{3} + \sqrt{3} \sqrt{3}}{6}) (1 - \tan (\frac{π}{12}))}$

Raise $\sqrt{3}$ to the power of $1$ .

$\frac{2 (2 - \sqrt{3})}{(1 + \frac{9 - 3 \sqrt{3} - 3 \sqrt{3} + {\sqrt{3}}^{1} \sqrt{3}}{6}) (1 - \tan (\frac{π}{12}))}$

Raise $\sqrt{3}$ to the power of $1$ .

$\frac{2 (2 - \sqrt{3})}{(1 + \frac{9 - 3 \sqrt{3} - 3 \sqrt{3} + {\sqrt{3}}^{1} {\sqrt{3}}^{1}}{6}) (1 - \tan (\frac{π}{12}))}$

Use the power rule $a^{m} a^{n} = a^{m + n}$ to combine exponents.

$\frac{2 (2 - \sqrt{3})}{(1 + \frac{9 - 3 \sqrt{3} - 3 \sqrt{3} + {\sqrt{3}}^{1 + 1}}{6}) (1 - \tan (\frac{π}{12}))}$

Add $1$ and $1$ .

$\frac{2 (2 - \sqrt{3})}{(1 + \frac{9 - 3 \sqrt{3} - 3 \sqrt{3} + {\sqrt{3}}^{2}}{6}) (1 - \tan (\frac{π}{12}))}$

Rewrite ${\sqrt{3}}^{2}$ as $3$ .

Use $\sqrt[n]{a^{x}} = a^{\frac{x}{n}}$ to rewrite $\sqrt{3}$ as $3^{\frac{1}{2}}$ .

$\frac{2 (2 - \sqrt{3})}{(1 + \frac{9 - 3 \sqrt{3} - 3 \sqrt{3} + {(3^{\frac{1}{2}})}^{2}}{6}) (1 - \tan (\frac{π}{12}))}$

Apply the power rule and multiply exponents, ${(a^{m})}^{n} = a^{m n}$ .

$\frac{2 (2 - \sqrt{3})}{(1 + \frac{9 - 3 \sqrt{3} - 3 \sqrt{3} + 3^{\frac{1}{2} \cdot 2}}{6}) (1 - \tan (\frac{π}{12}))}$

Combine $\frac{1}{2}$ and $2$ .

$\frac{2 (2 - \sqrt{3})}{(1 + \frac{9 - 3 \sqrt{3} - 3 \sqrt{3} + 3^{\frac{2}{2}}}{6}) (1 - \tan (\frac{π}{12}))}$

Cancel the common factor of $2$ .

Cancel the common factor.

$\frac{2 (2 - \sqrt{3})}{(1 + \frac{9 - 3 \sqrt{3} - 3 \sqrt{3} + 3^{\frac{2}{2}}}{6}) (1 - \tan (\frac{π}{12}))}$

Rewrite the expression.

$\frac{2 (2 - \sqrt{3})}{(1 + \frac{9 - 3 \sqrt{3} - 3 \sqrt{3} + 3^{1}}{6}) (1 - \tan (\frac{π}{12}))}$

Evaluate the exponent.

$\frac{2 (2 - \sqrt{3})}{(1 + \frac{9 - 3 \sqrt{3} - 3 \sqrt{3} + 3}{6}) (1 - \tan (\frac{π}{12}))}$

Add $9$ and $3$ .

$\frac{2 (2 - \sqrt{3})}{(1 + \frac{12 - 3 \sqrt{3} - 3 \sqrt{3}}{6}) (1 - \tan (\frac{π}{12}))}$

Subtract $3 \sqrt{3}$ from $- 3 \sqrt{3}$ .

$\frac{2 (2 - \sqrt{3})}{(1 + \frac{12 - 6 \sqrt{3}}{6}) (1 - \tan (\frac{π}{12}))}$

Cancel the common factor of $12 - 6 \sqrt{3}$ and $6$ .

Factor $6$ out of $12$ .

$\frac{2 (2 - \sqrt{3})}{(1 + \frac{6 \cdot 2 - 6 \sqrt{3}}{6}) (1 - \tan (\frac{π}{12}))}$

Factor $6$ out of $- 6 \sqrt{3}$ .

$\frac{2 (2 - \sqrt{3})}{(1 + \frac{6 \cdot 2 + 6 (- \sqrt{3})}{6}) (1 - \tan (\frac{π}{12}))}$

Factor $6$ out of $6 (2) + 6 (- \sqrt{3})$ .

$\frac{2 (2 - \sqrt{3})}{(1 + \frac{6 (2 - \sqrt{3})}{6}) (1 - \tan (\frac{π}{12}))}$

Cancel the common factors.

Factor $6$ out of $6$ .

$\frac{2 (2 - \sqrt{3})}{(1 + \frac{6 (2 - \sqrt{3})}{6 (1)}) (1 - \tan (\frac{π}{12}))}$

Cancel the common factor.

$\frac{2 (2 - \sqrt{3})}{(1 + \frac{6 (2 - \sqrt{3})}{6 \cdot 1}) (1 - \tan (\frac{π}{12}))}$

Rewrite the expression.

$\frac{2 (2 - \sqrt{3})}{(1 + \frac{2 - \sqrt{3}}{1}) (1 - \tan (\frac{π}{12}))}$

Divide $2 - \sqrt{3}$ by $1$ .

$\frac{2 (2 - \sqrt{3})}{(1 + 2 - \sqrt{3}) (1 - \tan (\frac{π}{12}))}$

Add $1$ and $2$ .

$\frac{2 (2 - \sqrt{3})}{(3 - \sqrt{3}) (1 - \tan (\frac{π}{12}))}$

The exact value of $\tan (\frac{π}{12})$ is $2 - \sqrt{3}$ .

Split $\frac{π}{12}$ into two angles where the values of the six trigonometric functions are known.

$\frac{2 (2 - \sqrt{3})}{(3 - \sqrt{3}) (1 - \tan (\frac{π}{4} - \frac{π}{6}))}$

Apply the difference of angles identity.

$\frac{2 (2 - \sqrt{3})}{(3 - \sqrt{3}) (1 - \frac{\tan (\frac{π}{4}) - \tan (\frac{π}{6})}{1 + \tan (\frac{π}{4}) \tan (\frac{π}{6})})}$

The exact value of $\tan (\frac{π}{4})$ is $1$ .

$\frac{2 (2 - \sqrt{3})}{(3 - \sqrt{3}) (1 - \frac{1 - \tan (\frac{π}{6})}{1 + \tan (\frac{π}{4}) \tan (\frac{π}{6})})}$

The exact value of $\tan (\frac{π}{6})$ is $\frac{\sqrt{3}}{3}$ .

$\frac{2 (2 - \sqrt{3})}{(3 - \sqrt{3}) (1 - \frac{1 - \frac{\sqrt{3}}{3}}{1 + \tan (\frac{π}{4}) \tan (\frac{π}{6})})}$

The exact value of $\tan (\frac{π}{4})$ is $1$ .

$\frac{2 (2 - \sqrt{3})}{(3 - \sqrt{3}) (1 - \frac{1 - \frac{\sqrt{3}}{3}}{1 + 1 \tan (\frac{π}{6})})}$

The exact value of $\tan (\frac{π}{6})$ is $\frac{\sqrt{3}}{3}$ .

$\frac{2 (2 - \sqrt{3})}{(3 - \sqrt{3}) (1 - \frac{1 - \frac{\sqrt{3}}{3}}{1 + 1 \frac{\sqrt{3}}{3}})}$

Simplify $\frac{1 - \frac{\sqrt{3}}{3}}{1 + 1 \frac{\sqrt{3}}{3}}$ .

Multiply the numerator and denominator of the complex fraction by $3$ .

Multiply $\frac{1 - \frac{\sqrt{3}}{3}}{1 + 1 \frac{\sqrt{3}}{3}}$ by $\frac{3}{3}$ .

$\frac{2 (2 - \sqrt{3})}{(3 - \sqrt{3}) (1 - (\frac{3}{3} \cdot \frac{1 - \frac{\sqrt{3}}{3}}{1 + 1 \frac{\sqrt{3}}{3}}))}$

Combine.

$\frac{2 (2 - \sqrt{3})}{(3 - \sqrt{3}) (1 - \frac{3 (1 - \frac{\sqrt{3}}{3})}{3 (1 + 1 \frac{\sqrt{3}}{3})})}$

Apply the distributive property.

$\frac{2 (2 - \sqrt{3})}{(3 - \sqrt{3}) (1 - \frac{3 \cdot 1 + 3 (- \frac{\sqrt{3}}{3})}{3 \cdot 1 + 3 (1 \frac{\sqrt{3}}{3})})}$

Cancel the common factor of $3$ .

Move the leading negative in $- \frac{\sqrt{3}}{3}$ into the numerator.

$\frac{2 (2 - \sqrt{3})}{(3 - \sqrt{3}) (1 - \frac{3 \cdot 1 + 3 \frac{- \sqrt{3}}{3}}{3 \cdot 1 + 3 (1 \frac{\sqrt{3}}{3})})}$

Cancel the common factor.

$\frac{2 (2 - \sqrt{3})}{(3 - \sqrt{3}) (1 - \frac{3 \cdot 1 + 3 \frac{- \sqrt{3}}{3}}{3 \cdot 1 + 3 (1 \frac{\sqrt{3}}{3})})}$

Rewrite the expression.

$\frac{2 (2 - \sqrt{3})}{(3 - \sqrt{3}) (1 - \frac{3 \cdot 1 - \sqrt{3}}{3 \cdot 1 + 3 (1 \frac{\sqrt{3}}{3})})}$

Multiply $3$ by $1$ .

$\frac{2 (2 - \sqrt{3})}{(3 - \sqrt{3}) (1 - \frac{3 - \sqrt{3}}{3 \cdot 1 + 3 \cdot 1 \frac{\sqrt{3}}{3}})}$

Simplify the denominator.

Multiply $3$ by $1$ .

$\frac{2 (2 - \sqrt{3})}{(3 - \sqrt{3}) (1 - \frac{3 - \sqrt{3}}{3 + 3 \cdot 1 \frac{\sqrt{3}}{3}})}$

Cancel the common factor of $3$ .

Factor $3$ out of $3 \cdot 1$ .

$\frac{2 (2 - \sqrt{3})}{(3 - \sqrt{3}) (1 - \frac{3 - \sqrt{3}}{3 + 3 (1) \frac{\sqrt{3}}{3}})}$

Cancel the common factor.

$\frac{2 (2 - \sqrt{3})}{(3 - \sqrt{3}) (1 - \frac{3 - \sqrt{3}}{3 + 3 \cdot 1 \frac{\sqrt{3}}{3}})}$

Rewrite the expression.

$\frac{2 (2 - \sqrt{3})}{(3 - \sqrt{3}) (1 - \frac{3 - \sqrt{3}}{3 + \sqrt{3}})}$

Multiply $\frac{3 - \sqrt{3}}{3 + \sqrt{3}}$ by $\frac{3 - \sqrt{3}}{3 - \sqrt{3}}$ .

$\frac{2 (2 - \sqrt{3})}{(3 - \sqrt{3}) (1 - (\frac{3 - \sqrt{3}}{3 + \sqrt{3}} \cdot \frac{3 - \sqrt{3}}{3 - \sqrt{3}}))}$

Multiply $\frac{3 - \sqrt{3}}{3 + \sqrt{3}}$ by $\frac{3 - \sqrt{3}}{3 - \sqrt{3}}$ .

$\frac{2 (2 - \sqrt{3})}{(3 - \sqrt{3}) (1 - \frac{(3 - \sqrt{3}) (3 - \sqrt{3})}{(3 + \sqrt{3}) (3 - \sqrt{3})})}$

Expand the denominator using the FOIL method.

$\frac{2 (2 - \sqrt{3})}{(3 - \sqrt{3}) (1 - \frac{(3 - \sqrt{3}) (3 - \sqrt{3})}{9 - 3 \sqrt{3} + \sqrt{3} \cdot 3 - {\sqrt{3}}^{2}})}$

Simplify.

$\frac{2 (2 - \sqrt{3})}{(3 - \sqrt{3}) (1 - \frac{(3 - \sqrt{3}) (3 - \sqrt{3})}{6})}$

Simplify the numerator.

Raise $3 - \sqrt{3}$ to the power of $1$ .

$\frac{2 (2 - \sqrt{3})}{(3 - \sqrt{3}) (1 - \frac{{(3 - \sqrt{3})}^{1} (3 - \sqrt{3})}{6})}$

Raise $3 - \sqrt{3}$ to the power of $1$ .

$\frac{2 (2 - \sqrt{3})}{(3 - \sqrt{3}) (1 - \frac{{(3 - \sqrt{3})}^{1} {(3 - \sqrt{3})}^{1}}{6})}$

Use the power rule $a^{m} a^{n} = a^{m + n}$ to combine exponents.

$\frac{2 (2 - \sqrt{3})}{(3 - \sqrt{3}) (1 - \frac{{(3 - \sqrt{3})}^{1 + 1}}{6})}$

Add $1$ and $1$ .

$\frac{2 (2 - \sqrt{3})}{(3 - \sqrt{3}) (1 - \frac{{(3 - \sqrt{3})}^{2}}{6})}$

Rewrite ${(3 - \sqrt{3})}^{2}$ as $(3 - \sqrt{3}) (3 - \sqrt{3})$ .

$\frac{2 (2 - \sqrt{3})}{(3 - \sqrt{3}) (1 - \frac{(3 - \sqrt{3}) (3 - \sqrt{3})}{6})}$

Expand $(3 - \sqrt{3}) (3 - \sqrt{3})$ using the FOIL Method.

Apply the distributive property.

$\frac{2 (2 - \sqrt{3})}{(3 - \sqrt{3}) (1 - \frac{3 (3 - \sqrt{3}) - \sqrt{3} (3 - \sqrt{3})}{6})}$

Apply the distributive property.

$\frac{2 (2 - \sqrt{3})}{(3 - \sqrt{3}) (1 - \frac{3 \cdot 3 + 3 (- \sqrt{3}) - \sqrt{3} (3 - \sqrt{3})}{6})}$

Apply the distributive property.

$\frac{2 (2 - \sqrt{3})}{(3 - \sqrt{3}) (1 - \frac{3 \cdot 3 + 3 (- \sqrt{3}) - \sqrt{3} \cdot 3 - \sqrt{3} (- \sqrt{3})}{6})}$

Simplify and combine like terms.

Simplify each term.

Multiply $3$ by $3$ .

$\frac{2 (2 - \sqrt{3})}{(3 - \sqrt{3}) (1 - \frac{9 + 3 (- \sqrt{3}) - \sqrt{3} \cdot 3 - \sqrt{3} (- \sqrt{3})}{6})}$

Multiply $- 1$ by $3$ .

$\frac{2 (2 - \sqrt{3})}{(3 - \sqrt{3}) (1 - \frac{9 - 3 \sqrt{3} - \sqrt{3} \cdot 3 - \sqrt{3} (- \sqrt{3})}{6})}$

Multiply $3$ by $- 1$ .

$\frac{2 (2 - \sqrt{3})}{(3 - \sqrt{3}) (1 - \frac{9 - 3 \sqrt{3} - 3 \sqrt{3} - \sqrt{3} (- \sqrt{3})}{6})}$

Multiply $- \sqrt{3} (- \sqrt{3})$ .

Multiply $- 1$ by $- 1$ .

$\frac{2 (2 - \sqrt{3})}{(3 - \sqrt{3}) (1 - \frac{9 - 3 \sqrt{3} - 3 \sqrt{3} + 1 \sqrt{3} \sqrt{3}}{6})}$

Multiply $\sqrt{3}$ by $1$ .

$\frac{2 (2 - \sqrt{3})}{(3 - \sqrt{3}) (1 - \frac{9 - 3 \sqrt{3} - 3 \sqrt{3} + \sqrt{3} \sqrt{3}}{6})}$

Raise $\sqrt{3}$ to the power of $1$ .

$\frac{2 (2 - \sqrt{3})}{(3 - \sqrt{3}) (1 - \frac{9 - 3 \sqrt{3} - 3 \sqrt{3} + {\sqrt{3}}^{1} \sqrt{3}}{6})}$

Raise $\sqrt{3}$ to the power of $1$ .

$\frac{2 (2 - \sqrt{3})}{(3 - \sqrt{3}) (1 - \frac{9 - 3 \sqrt{3} - 3 \sqrt{3} + {\sqrt{3}}^{1} {\sqrt{3}}^{1}}{6})}$

Use the power rule $a^{m} a^{n} = a^{m + n}$ to combine exponents.

$\frac{2 (2 - \sqrt{3})}{(3 - \sqrt{3}) (1 - \frac{9 - 3 \sqrt{3} - 3 \sqrt{3} + {\sqrt{3}}^{1 + 1}}{6})}$

Add $1$ and $1$ .

$\frac{2 (2 - \sqrt{3})}{(3 - \sqrt{3}) (1 - \frac{9 - 3 \sqrt{3} - 3 \sqrt{3} + {\sqrt{3}}^{2}}{6})}$

Rewrite ${\sqrt{3}}^{2}$ as $3$ .

Use $\sqrt[n]{a^{x}} = a^{\frac{x}{n}}$ to rewrite $\sqrt{3}$ as $3^{\frac{1}{2}}$ .

$\frac{2 (2 - \sqrt{3})}{(3 - \sqrt{3}) (1 - \frac{9 - 3 \sqrt{3} - 3 \sqrt{3} + {(3^{\frac{1}{2}})}^{2}}{6})}$

Apply the power rule and multiply exponents, ${(a^{m})}^{n} = a^{m n}$ .

$\frac{2 (2 - \sqrt{3})}{(3 - \sqrt{3}) (1 - \frac{9 - 3 \sqrt{3} - 3 \sqrt{3} + 3^{\frac{1}{2} \cdot 2}}{6})}$

Combine $\frac{1}{2}$ and $2$ .

$\frac{2 (2 - \sqrt{3})}{(3 - \sqrt{3}) (1 - \frac{9 - 3 \sqrt{3} - 3 \sqrt{3} + 3^{\frac{2}{2}}}{6})}$

Cancel the common factor of $2$ .

Cancel the common factor.

$\frac{2 (2 - \sqrt{3})}{(3 - \sqrt{3}) (1 - \frac{9 - 3 \sqrt{3} - 3 \sqrt{3} + 3^{\frac{2}{2}}}{6})}$

Rewrite the expression.

$\frac{2 (2 - \sqrt{3})}{(3 - \sqrt{3}) (1 - \frac{9 - 3 \sqrt{3} - 3 \sqrt{3} + 3^{1}}{6})}$

Evaluate the exponent.

$\frac{2 (2 - \sqrt{3})}{(3 - \sqrt{3}) (1 - \frac{9 - 3 \sqrt{3} - 3 \sqrt{3} + 3}{6})}$

Add $9$ and $3$ .

$\frac{2 (2 - \sqrt{3})}{(3 - \sqrt{3}) (1 - \frac{12 - 3 \sqrt{3} - 3 \sqrt{3}}{6})}$

Subtract $3 \sqrt{3}$ from $- 3 \sqrt{3}$ .

$\frac{2 (2 - \sqrt{3})}{(3 - \sqrt{3}) (1 - \frac{12 - 6 \sqrt{3}}{6})}$

Cancel the common factor of $12 - 6 \sqrt{3}$ and $6$ .

Factor $6$ out of $12$ .

$\frac{2 (2 - \sqrt{3})}{(3 - \sqrt{3}) (1 - \frac{6 \cdot 2 - 6 \sqrt{3}}{6})}$

Factor $6$ out of $- 6 \sqrt{3}$ .

$\frac{2 (2 - \sqrt{3})}{(3 - \sqrt{3}) (1 - \frac{6 \cdot 2 + 6 (- \sqrt{3})}{6})}$

Factor $6$ out of $6 (2) + 6 (- \sqrt{3})$ .

$\frac{2 (2 - \sqrt{3})}{(3 - \sqrt{3}) (1 - \frac{6 (2 - \sqrt{3})}{6})}$

Cancel the common factors.

Factor $6$ out of $6$ .

$\frac{2 (2 - \sqrt{3})}{(3 - \sqrt{3}) (1 - \frac{6 (2 - \sqrt{3})}{6 (1)})}$

Cancel the common factor.

$\frac{2 (2 - \sqrt{3})}{(3 - \sqrt{3}) (1 - \frac{6 (2 - \sqrt{3})}{6 \cdot 1})}$

Rewrite the expression.

$\frac{2 (2 - \sqrt{3})}{(3 - \sqrt{3}) (1 - \frac{2 - \sqrt{3}}{1})}$

Divide $2 - \sqrt{3}$ by $1$ .

$\frac{2 (2 - \sqrt{3})}{(3 - \sqrt{3}) (1 - (2 - \sqrt{3}))}$

Apply the distributive property.

$\frac{2 (2 - \sqrt{3})}{(3 - \sqrt{3}) (1 - 1 \cdot 2 - - \sqrt{3})}$

Multiply $- 1$ by $2$ .

$\frac{2 (2 - \sqrt{3})}{(3 - \sqrt{3}) (1 - 2 - - \sqrt{3})}$

Multiply $- - \sqrt{3}$ .

Multiply $- 1$ by $- 1$ .

$\frac{2 (2 - \sqrt{3})}{(3 - \sqrt{3}) (1 - 2 + 1 \sqrt{3})}$

Multiply $\sqrt{3}$ by $1$ .

$\frac{2 (2 - \sqrt{3})}{(3 - \sqrt{3}) (1 - 2 + \sqrt{3})}$

Subtract $2$ from $1$ .

$\frac{2 (2 - \sqrt{3})}{(3 - \sqrt{3}) (- 1 + \sqrt{3})}$

Expand $(3 - \sqrt{3}) (- 1 + \sqrt{3})$ using the FOIL Method.

Apply the distributive property.

$\frac{2 (2 - \sqrt{3})}{3 (- 1 + \sqrt{3}) - \sqrt{3} (- 1 + \sqrt{3})}$

Apply the distributive property.

$\frac{2 (2 - \sqrt{3})}{3 \cdot - 1 + 3 \sqrt{3} - \sqrt{3} (- 1 + \sqrt{3})}$

Apply the distributive property.

$\frac{2 (2 - \sqrt{3})}{3 \cdot - 1 + 3 \sqrt{3} - \sqrt{3} \cdot - 1 - \sqrt{3} \sqrt{3}}$

Simplify and combine like terms.

Simplify each term.

Multiply $3$ by $- 1$ .

$\frac{2 (2 - \sqrt{3})}{- 3 + 3 \sqrt{3} - \sqrt{3} \cdot - 1 - \sqrt{3} \sqrt{3}}$

Multiply $- \sqrt{3} \cdot - 1$ .

Multiply $- 1$ by $- 1$ .

$\frac{2 (2 - \sqrt{3})}{- 3 + 3 \sqrt{3} + 1 \sqrt{3} - \sqrt{3} \sqrt{3}}$

Multiply $\sqrt{3}$ by $1$ .

$\frac{2 (2 - \sqrt{3})}{- 3 + 3 \sqrt{3} + \sqrt{3} - \sqrt{3} \sqrt{3}}$

Multiply $- \sqrt{3} \sqrt{3}$ .

Raise $\sqrt{3}$ to the power of $1$ .

$\frac{2 (2 - \sqrt{3})}{- 3 + 3 \sqrt{3} + \sqrt{3} - ({\sqrt{3}}^{1} \sqrt{3})}$

Raise $\sqrt{3}$ to the power of $1$ .

$\frac{2 (2 - \sqrt{3})}{- 3 + 3 \sqrt{3} + \sqrt{3} - ({\sqrt{3}}^{1} {\sqrt{3}}^{1})}$

Use the power rule $a^{m} a^{n} = a^{m + n}$ to combine exponents.

$\frac{2 (2 - \sqrt{3})}{- 3 + 3 \sqrt{3} + \sqrt{3} - {\sqrt{3}}^{1 + 1}}$

Add $1$ and $1$ .

$\frac{2 (2 - \sqrt{3})}{- 3 + 3 \sqrt{3} + \sqrt{3} - {\sqrt{3}}^{2}}$

Rewrite ${\sqrt{3}}^{2}$ as $3$ .

Use $\sqrt[n]{a^{x}} = a^{\frac{x}{n}}$ to rewrite $\sqrt{3}$ as $3^{\frac{1}{2}}$ .

$\frac{2 (2 - \sqrt{3})}{- 3 + 3 \sqrt{3} + \sqrt{3} - {(3^{\frac{1}{2}})}^{2}}$

Apply the power rule and multiply exponents, ${(a^{m})}^{n} = a^{m n}$ .

$\frac{2 (2 - \sqrt{3})}{- 3 + 3 \sqrt{3} + \sqrt{3} - 3^{\frac{1}{2} \cdot 2}}$

Combine $\frac{1}{2}$ and $2$ .

$\frac{2 (2 - \sqrt{3})}{- 3 + 3 \sqrt{3} + \sqrt{3} - 3^{\frac{2}{2}}}$

Cancel the common factor of $2$ .

Cancel the common factor.

$\frac{2 (2 - \sqrt{3})}{- 3 + 3 \sqrt{3} + \sqrt{3} - 3^{\frac{2}{2}}}$

Rewrite the expression.

$\frac{2 (2 - \sqrt{3})}{- 3 + 3 \sqrt{3} + \sqrt{3} - 3^{1}}$

Evaluate the exponent.

$\frac{2 (2 - \sqrt{3})}{- 3 + 3 \sqrt{3} + \sqrt{3} - 1 \cdot 3}$

Multiply $- 1$ by $3$ .

$\frac{2 (2 - \sqrt{3})}{- 3 + 3 \sqrt{3} + \sqrt{3} - 3}$

Subtract $3$ from $- 3$ .

$\frac{2 (2 - \sqrt{3})}{- 6 + 3 \sqrt{3} + \sqrt{3}}$

Add $3 \sqrt{3}$ and $\sqrt{3}$ .

$\frac{2 (2 - \sqrt{3})}{- 6 + 4 \sqrt{3}}$

Cancel the common factors.

Factor $2$ out of $- 6$ .

$\frac{2 (2 - \sqrt{3})}{2 (- 3) + 4 \sqrt{3}}$

Factor $2$ out of $4 \sqrt{3}$ .

$\frac{2 (2 - \sqrt{3})}{2 (- 3) + 2 (2 \sqrt{3})}$

Factor $2$ out of $2 (- 3) + 2 (2 \sqrt{3})$ .

$\frac{2 (2 - \sqrt{3})}{2 (- 3 + 2 \sqrt{3})}$

Cancel the common factor.

$\frac{2 (2 - \sqrt{3})}{2 (- 3 + 2 \sqrt{3})}$

Rewrite the expression.

$\frac{2 - \sqrt{3}}{- 3 + 2 \sqrt{3}}$

Multiply $\frac{2 - \sqrt{3}}{- 3 + 2 \sqrt{3}}$ by $\frac{- 3 - 2 \sqrt{3}}{- 3 - 2 \sqrt{3}}$ .

$\frac{2 - \sqrt{3}}{- 3 + 2 \sqrt{3}} \cdot \frac{- 3 - 2 \sqrt{3}}{- 3 - 2 \sqrt{3}}$

Combine fractions.

Multiply $\frac{2 - \sqrt{3}}{- 3 + 2 \sqrt{3}}$ by $\frac{- 3 - 2 \sqrt{3}}{- 3 - 2 \sqrt{3}}$ .

$\frac{(2 - \sqrt{3}) (- 3 - 2 \sqrt{3})}{(- 3 + 2 \sqrt{3}) (- 3 - 2 \sqrt{3})}$

Expand the denominator using the FOIL method.

$\frac{(2 - \sqrt{3}) (- 3 - 2 \sqrt{3})}{9 + 6 \sqrt{3} - 6 \sqrt{3} - 4 {\sqrt{3}}^{2}}$

Simplify.

$\frac{(2 - \sqrt{3}) (- 3 - 2 \sqrt{3})}{- 3}$

Simplify the numerator.

Expand $(2 - \sqrt{3}) (- 3 - 2 \sqrt{3})$ using the FOIL Method.

Apply the distributive property.

$\frac{2 (- 3 - 2 \sqrt{3}) - \sqrt{3} (- 3 - 2 \sqrt{3})}{- 3}$

Apply the distributive property.

$\frac{2 \cdot - 3 + 2 (- 2 \sqrt{3}) - \sqrt{3} (- 3 - 2 \sqrt{3})}{- 3}$

Apply the distributive property.

$\frac{2 \cdot - 3 + 2 (- 2 \sqrt{3}) - \sqrt{3} \cdot - 3 - \sqrt{3} (- 2 \sqrt{3})}{- 3}$

Simplify and combine like terms.

Simplify each term.

Multiply $2$ by $- 3$ .

$\frac{- 6 + 2 (- 2 \sqrt{3}) - \sqrt{3} \cdot - 3 - \sqrt{3} (- 2 \sqrt{3})}{- 3}$

Multiply $- 2$ by $2$ .

$\frac{- 6 - 4 \sqrt{3} - \sqrt{3} \cdot - 3 - \sqrt{3} (- 2 \sqrt{3})}{- 3}$

Multiply $- 3$ by $- 1$ .

$\frac{- 6 - 4 \sqrt{3} + 3 \sqrt{3} - \sqrt{3} (- 2 \sqrt{3})}{- 3}$

Multiply $- \sqrt{3} (- 2 \sqrt{3})$ .

Multiply $- 2$ by $- 1$ .

$\frac{- 6 - 4 \sqrt{3} + 3 \sqrt{3} + 2 \sqrt{3} \sqrt{3}}{- 3}$

Raise $\sqrt{3}$ to the power of $1$ .

$\frac{- 6 - 4 \sqrt{3} + 3 \sqrt{3} + 2 ({\sqrt{3}}^{1} \sqrt{3})}{- 3}$

Raise $\sqrt{3}$ to the power of $1$ .

$\frac{- 6 - 4 \sqrt{3} + 3 \sqrt{3} + 2 ({\sqrt{3}}^{1} {\sqrt{3}}^{1})}{- 3}$

Use the power rule $a^{m} a^{n} = a^{m + n}$ to combine exponents.

$\frac{- 6 - 4 \sqrt{3} + 3 \sqrt{3} + 2 {\sqrt{3}}^{1 + 1}}{- 3}$

Add $1$ and $1$ .

$\frac{- 6 - 4 \sqrt{3} + 3 \sqrt{3} + 2 {\sqrt{3}}^{2}}{- 3}$

Rewrite ${\sqrt{3}}^{2}$ as $3$ .

Use $\sqrt[n]{a^{x}} = a^{\frac{x}{n}}$ to rewrite $\sqrt{3}$ as $3^{\frac{1}{2}}$ .

$\frac{- 6 - 4 \sqrt{3} + 3 \sqrt{3} + 2 {(3^{\frac{1}{2}})}^{2}}{- 3}$

Apply the power rule and multiply exponents, ${(a^{m})}^{n} = a^{m n}$ .

$\frac{- 6 - 4 \sqrt{3} + 3 \sqrt{3} + 2 \cdot 3^{\frac{1}{2} \cdot 2}}{- 3}$

Combine $\frac{1}{2}$ and $2$ .

$\frac{- 6 - 4 \sqrt{3} + 3 \sqrt{3} + 2 \cdot 3^{\frac{2}{2}}}{- 3}$

Cancel the common factor of $2$ .

Cancel the common factor.

$\frac{- 6 - 4 \sqrt{3} + 3 \sqrt{3} + 2 \cdot 3^{\frac{2}{2}}}{- 3}$

Rewrite the expression.

$\frac{- 6 - 4 \sqrt{3} + 3 \sqrt{3} + 2 \cdot 3^{1}}{- 3}$

Evaluate the exponent.

$\frac{- 6 - 4 \sqrt{3} + 3 \sqrt{3} + 2 \cdot 3}{- 3}$

Multiply $2$ by $3$ .

$\frac{- 6 - 4 \sqrt{3} + 3 \sqrt{3} + 6}{- 3}$

Add $- 6$ and $6$ .

$\frac{0 - 4 \sqrt{3} + 3 \sqrt{3}}{- 3}$

Subtract $4 \sqrt{3}$ from $0$ .

$\frac{- 4 \sqrt{3} + 3 \sqrt{3}}{- 3}$

Add $- 4 \sqrt{3}$ and $3 \sqrt{3}$ .

$\frac{- \sqrt{3}}{- 3}$

Dividing two negative values results in a positive value.

$\frac{\sqrt{3}}{3}$

The result can be shown in multiple forms.

Exact Form:

$\frac{\sqrt{3}}{3}$

Decimal Form:

$0.57735026 \dots$

Find the Exact Value (2tan(pi/12))/(1-tan(pi/12)^2)

Related Questions

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