Find the Exact Value 3-5+3(2-1)+4÷2

$3 - 5 + 3 (2 - 1) + 4 \div 2$

Step 1

Find the common denominator.

Write $3$ as a fraction with denominator $1$ .

$\frac{3}{1} - 5 + 3 (2 - 1) + 4 \div 2$

Multiply $\frac{3}{1}$ by $\frac{2}{2}$ .

$\frac{3}{1} \cdot \frac{2}{2} - 5 + 3 (2 - 1) + 4 \div 2$

Multiply $\frac{3}{1}$ by $\frac{2}{2}$ .

$\frac{3 \cdot 2}{2} - 5 + 3 (2 - 1) + 4 \div 2$

Write $- 5$ as a fraction with denominator $1$ .

$\frac{3 \cdot 2}{2} + \frac{- 5}{1} + 3 (2 - 1) + 4 \div 2$

Multiply $\frac{- 5}{1}$ by $\frac{2}{2}$ .

$\frac{3 \cdot 2}{2} + \frac{- 5}{1} \cdot \frac{2}{2} + 3 (2 - 1) + 4 \div 2$

Multiply $\frac{- 5}{1}$ by $\frac{2}{2}$ .

$\frac{3 \cdot 2}{2} + \frac{- 5 \cdot 2}{2} + 3 (2 - 1) + 4 \div 2$

Write $3 (2 - 1)$ as a fraction with denominator $1$ .

$\frac{3 \cdot 2}{2} + \frac{- 5 \cdot 2}{2} + \frac{3 (2 - 1)}{1} + 4 \div 2$

Multiply $\frac{3 (2 - 1)}{1}$ by $\frac{2}{2}$ .

$\frac{3 \cdot 2}{2} + \frac{- 5 \cdot 2}{2} + \frac{3 (2 - 1)}{1} \cdot \frac{2}{2} + 4 \div 2$

Multiply $\frac{3 (2 - 1)}{1}$ by $\frac{2}{2}$ .

$\frac{3 \cdot 2}{2} + \frac{- 5 \cdot 2}{2} + \frac{3 (2 - 1) \cdot 2}{2} + 4 \div 2$

Step 2

Combine the numerators over the common denominator.

$\frac{3 \cdot 2 - 5 \cdot 2 + 3 (2 - 1) \cdot 2 + 4}{2}$

Step 3

Simplify each term.

Multiply $3$ by $2$ .

$\frac{6 - 5 \cdot 2 + 3 (2 - 1) \cdot 2 + 4}{2}$

Multiply $- 5$ by $2$ .

$\frac{6 - 10 + 3 (2 - 1) \cdot 2 + 4}{2}$

Subtract $1$ from $2$ .

$\frac{6 - 10 + 3 \cdot 1 \cdot 2 + 4}{2}$

Multiply $3 \cdot 1 \cdot 2$ .

Multiply $3$ by $1$ .

$\frac{6 - 10 + 3 \cdot 2 + 4}{2}$

Multiply $3$ by $2$ .

$\frac{6 - 10 + 6 + 4}{2}$

Step 4

Simplify the expression.

Subtract $10$ from $6$ .

$\frac{- 4 + 6 + 4}{2}$

Add $- 4$ and $6$ .

$\frac{2 + 4}{2}$

Add $2$ and $4$ .

$\frac{6}{2}$

Divide $6$ by $2$ .

$3$

Find the Exact Value 3-5+3(2-1)+4÷2

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