Find the Exact Value 6/(2(1+2))

$\frac{6}{2 (1 + 2)}$

Cancel the common factor of $6$ and $2$ .

Factor $2$ out of $6$ .

$\frac{2 \cdot 3}{2 (1 + 2)}$

Cancel the common factors.

Cancel the common factor.

$\frac{2 \cdot 3}{2 (1 + 2)}$

Rewrite the expression.

$\frac{3}{1 + 2}$

$\frac{3}{1 + 2}$

$\frac{3}{1 + 2}$

Simplify the expression.

Add $1$ and $2$ .

$\frac{3}{3}$

Divide $3$ by $3$ .

$1$

$1$

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