Find the Exact Value (6^2+60)/(2^3)

$\frac{(6^{2} + 60)}{2^{3}}$

Step 1

Simplify the numerator.

Raise $6$ to the power of $2$ .

$\frac{36 + 60}{2^{3}}$

Add $36$ and $60$ .

$\frac{96}{2^{3}}$

Step 2

Simplify the expression.

Raise $2$ to the power of $3$ .

$\frac{96}{8}$

Divide $96$ by $8$ .

$12$