Find the Exact Value 8/(2(2+2))

$\frac{8}{2 (2 + 2)}$

Cancel the common factor of $8$ and $2$ .

Factor $2$ out of $8$ .

$\frac{2 \cdot 4}{2 (2 + 2)}$

Cancel the common factors.

Cancel the common factor.

$\frac{2 \cdot 4}{2 (2 + 2)}$

Rewrite the expression.

$\frac{4}{2 + 2}$

$\frac{4}{2 + 2}$

$\frac{4}{2 + 2}$

Cancel the common factor of $4$ and $2 + 2$ .

Factor $2$ out of $4$ .

$\frac{2 \cdot 2}{2 + 2}$

Cancel the common factors.

Factor $2$ out of $2$ .

$\frac{2 \cdot 2}{2 (1) + 2}$

Factor $2$ out of $2$ .

$\frac{2 \cdot 2}{2 \cdot 1 + 2 \cdot 1}$

Factor $2$ out of $2 \cdot 1 + 2 \cdot 1$ .

$\frac{2 \cdot 2}{2 \cdot (1 + 1)}$

Cancel the common factor.

$\frac{2 \cdot 2}{2 \cdot (1 + 1)}$

Rewrite the expression.

$\frac{2}{1 + 1}$

$\frac{2}{1 + 1}$

$\frac{2}{1 + 1}$

Simplify the expression.

Add $1$ and $1$ .

$\frac{2}{2}$

Divide $2$ by $2$ .

$1$

$1$

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