Find the Exact Value (8^2-48)/(2^3)

$\frac{(8^{2} - 48)}{2^{3}}$

Step 1

Simplify the numerator.

Raise $8$ to the power of $2$ .

$\frac{64 - 48}{2^{3}}$

Subtract $48$ from $64$ .

$\frac{16}{2^{3}}$

Step 2

Simplify the expression.

Raise $2$ to the power of $3$ .

$\frac{16}{8}$

Divide $16$ by $8$ .

$2$