Find the Exact Value cot(-(25pi)/6)

$\cot (- \frac{25 π}{6})$

Add full rotations of $2 π$ until the angle is greater than or equal to $0$ and less than $2 π$ .

$\cot (\frac{11 π}{6})$

Apply the reference angle by finding the angle with equivalent trig values in the first quadrant. Make the expression negative because cotangent is negative in the fourth quadrant.

$- \cot (\frac{π}{6})$

The exact value of $\cot (\frac{π}{6})$ is $\sqrt{3}$ .

$- \sqrt{3}$

The result can be shown in multiple forms.

Exact Form:

$- \sqrt{3}$

Decimal Form:

$- 1.73205080 \dots$

Find the Exact Value cot(-(25pi)/6)

Related Questions

Support LCMGCF.com by disabling your adblocker.