Find the Exact Value f^-1(-1)

$f^{- 1} (- 1)$

Rewrite the expression using the negative exponent rule $b^{- n} = \frac{1}{b^{n}}$ .

$\frac{1}{f} \cdot - 1$

Combine $\frac{1}{f}$ and $- 1$ .

$\frac{- 1}{f}$

Move the negative in front of the fraction.

$- \frac{1}{f}$