Find the Exact Value f^-1(8)

$f^{- 1} (8)$

Rewrite the expression using the negative exponent rule $b^{- n} = \frac{1}{b^{n}}$ .

$\frac{1}{f} \cdot 8$

Combine $\frac{1}{f}$ and $8$ .

$\frac{8}{f}$

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