Find the Exact Value limit as x approaches 0 of (sin(x))/x

$lim_{x \to 0} \frac{\sin (x)}{x}$

Evaluate the limit of the numerator and the limit of the denominator.

Take the limit of the numerator and the limit of the denominator.

$\frac{lim_{x \to 0} \sin (x)}{lim_{x \to 0} x}$

Evaluate the limit of the numerator.

Move the limit inside the trig function because sine is continuous.

$\frac{\sin (lim_{x \to 0} x)}{lim_{x \to 0} x}$

Evaluate the limit of $x$ by plugging in $0$ for $x$ .

$\frac{\sin (0)}{lim_{x \to 0} x}$

The exact value of $\sin (0)$ is $0$ .

$\frac{0}{lim_{x \to 0} x}$

Evaluate the limit of $x$ by plugging in $0$ for $x$ .

$\frac{0}{0}$

The expression contains a division by $0$ . The expression is undefined.

Undefined

$\frac{0}{0}$

Since $\frac{0}{0}$ is of indeterminate form, apply L\'Hospital\'s Rule. L\'Hospital\'s Rule states that the limit of a quotient of functions is equal to the limit of the quotient of their derivatives.

$lim_{x \to 0} \frac{\sin (x)}{x} = lim_{x \to 0} \frac{\frac{d}{d x} [\sin (x)]}{\frac{d}{d x} [x]}$

Find the derivative of the numerator and denominator.

Differentiate the numerator and denominator.

$lim_{x \to 0} \frac{\frac{d}{d x} [\sin (x)]}{\frac{d}{d x} [x]}$

The derivative of $\sin (x)$ with respect to $x$ is $\cos (x)$ .

$lim_{x \to 0} \frac{\cos (x)}{\frac{d}{d x} [x]}$

Differentiate using the Power Rule which states that $\frac{d}{d x} [x^{n}]$ is $n x^{n - 1}$ where $n = 1$ .

$lim_{x \to 0} \frac{\cos (x)}{1}$

Evaluate the limit.

Divide $\cos (x)$ by $1$ .

$lim_{x \to 0} \cos (x)$

Move the limit inside the trig function because cosine is continuous.

$\cos (lim_{x \to 0} x)$

Evaluate the limit of $x$ by plugging in $0$ for $x$ .

$\cos (0)$

The exact value of $\cos (0)$ is $1$ .

$1$

Find the Exact Value limit as x approaches 0 of (sin(x))/x

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