Find the Exact Value ( square root of 64+ square root of 16)+(8^2-6)(-4)(2)

$(\sqrt{64} + \sqrt{16}) + (8^{2} - 6) (- 4) (2)$

Simplify each term.

Rewrite $64$ as $8^{2}$ .

$\sqrt{8^{2}} + \sqrt{16} + (8^{2} - 6) (- 4) (2)$

Pull terms out from under the radical, assuming positive real numbers.

$8 + \sqrt{16} + (8^{2} - 6) (- 4) (2)$

Rewrite $16$ as $4^{2}$ .

$8 + \sqrt{4^{2}} + (8^{2} - 6) (- 4) (2)$

Pull terms out from under the radical, assuming positive real numbers.

$8 + 4 + (8^{2} - 6) (- 4) (2)$

Raise $8$ to the power of $2$ .

$8 + 4 + (64 - 6) \cdot - 4 \cdot 2$

Subtract $6$ from $64$ .

$8 + 4 + 58 \cdot - 4 \cdot 2$

Multiply $58$ by $- 4$ .

$8 + 4 - 232 \cdot 2$

Multiply $- 232$ by $2$ .

$8 + 4 - 464$

Simplify by adding and subtracting.

Add $8$ and $4$ .

$12 - 464$

Subtract $464$ from $12$ .

$- 452$