Find the Exact Value tan(-105 degrees )

$\tan (- 105 °)$

Apply the reference angle by finding the angle with equivalent trig values in the first quadrant.

$\tan (75)$

Split $75$ into two angles where the values of the six trigonometric functions are known.

$\tan (30 + 45)$

Apply the sum of angles identity.

$\frac{\tan (30) + \tan (45)}{1 - \tan (30) \tan (45)}$

The exact value of $\tan (30)$ is $\frac{\sqrt{3}}{3}$ .

$\frac{\frac{\sqrt{3}}{3} + \tan (45)}{1 - \tan (30) \tan (45)}$

The exact value of $\tan (45)$ is $1$ .

$\frac{\frac{\sqrt{3}}{3} + 1}{1 - \tan (30) \tan (45)}$

The exact value of $\tan (30)$ is $\frac{\sqrt{3}}{3}$ .

$\frac{\frac{\sqrt{3}}{3} + 1}{1 - \frac{\sqrt{3}}{3} \tan (45)}$

The exact value of $\tan (45)$ is $1$ .

$\frac{\frac{\sqrt{3}}{3} + 1}{1 - \frac{\sqrt{3}}{3} \cdot 1}$

Simplify $\frac{\frac{\sqrt{3}}{3} + 1}{1 - \frac{\sqrt{3}}{3} \cdot 1}$ .

Multiply the numerator and denominator of the complex fraction by $3$ .

Multiply $\frac{\frac{\sqrt{3}}{3} + 1}{1 - \frac{\sqrt{3}}{3} \cdot 1}$ by $\frac{3}{3}$ .

$\frac{3}{3} \cdot \frac{\frac{\sqrt{3}}{3} + 1}{1 - \frac{\sqrt{3}}{3} \cdot 1}$

Combine.

$\frac{3 (\frac{\sqrt{3}}{3} + 1)}{3 (1 - \frac{\sqrt{3}}{3} \cdot 1)}$

Apply the distributive property.

$\frac{3 \frac{\sqrt{3}}{3} + 3 \cdot 1}{3 \cdot 1 + 3 (- \frac{\sqrt{3}}{3} \cdot 1)}$

Cancel the common factor of $3$ .

Cancel the common factor.

$\frac{3 \frac{\sqrt{3}}{3} + 3 \cdot 1}{3 \cdot 1 + 3 (- \frac{\sqrt{3}}{3} \cdot 1)}$

Rewrite the expression.

$\frac{\sqrt{3} + 3 \cdot 1}{3 \cdot 1 + 3 (- \frac{\sqrt{3}}{3} \cdot 1)}$

Multiply $3$ by $1$ .

$\frac{\sqrt{3} + 3}{3 \cdot 1 + 3 (- \frac{\sqrt{3}}{3} \cdot 1)}$

Simplify the denominator.

Multiply $3$ by $1$ .

$\frac{\sqrt{3} + 3}{3 + 3 (- \frac{\sqrt{3}}{3} \cdot 1)}$

Multiply $- 1$ by $1$ .

$\frac{\sqrt{3} + 3}{3 + 3 (- \frac{\sqrt{3}}{3})}$

Cancel the common factor of $3$ .

Move the leading negative in $- \frac{\sqrt{3}}{3}$ into the numerator.

$\frac{\sqrt{3} + 3}{3 + 3 \frac{- \sqrt{3}}{3}}$

Cancel the common factor.

$\frac{\sqrt{3} + 3}{3 + 3 \frac{- \sqrt{3}}{3}}$

Rewrite the expression.

$\frac{\sqrt{3} + 3}{3 - \sqrt{3}}$

Multiply $\frac{\sqrt{3} + 3}{3 - \sqrt{3}}$ by $\frac{3 + \sqrt{3}}{3 + \sqrt{3}}$ .

$\frac{\sqrt{3} + 3}{3 - \sqrt{3}} \cdot \frac{3 + \sqrt{3}}{3 + \sqrt{3}}$

Multiply $\frac{\sqrt{3} + 3}{3 - \sqrt{3}}$ by $\frac{3 + \sqrt{3}}{3 + \sqrt{3}}$ .

$\frac{(\sqrt{3} + 3) (3 + \sqrt{3})}{(3 - \sqrt{3}) (3 + \sqrt{3})}$

Expand the denominator using the FOIL method.

$\frac{(\sqrt{3} + 3) (3 + \sqrt{3})}{9 + 3 \sqrt{3} - 3 \sqrt{3} - {\sqrt{3}}^{2}}$

Simplify.

$\frac{(\sqrt{3} + 3) (3 + \sqrt{3})}{6}$

Simplify the numerator.

Reorder terms.

$\frac{(3 + \sqrt{3}) (3 + \sqrt{3})}{6}$

Raise $3 + \sqrt{3}$ to the power of $1$ .

$\frac{{(3 + \sqrt{3})}^{1} (3 + \sqrt{3})}{6}$

Raise $3 + \sqrt{3}$ to the power of $1$ .

$\frac{{(3 + \sqrt{3})}^{1} {(3 + \sqrt{3})}^{1}}{6}$

Use the power rule $a^{m} a^{n} = a^{m + n}$ to combine exponents.

$\frac{{(3 + \sqrt{3})}^{1 + 1}}{6}$

Add $1$ and $1$ .

$\frac{{(3 + \sqrt{3})}^{2}}{6}$

Rewrite ${(3 + \sqrt{3})}^{2}$ as $(3 + \sqrt{3}) (3 + \sqrt{3})$ .

$\frac{(3 + \sqrt{3}) (3 + \sqrt{3})}{6}$

Expand $(3 + \sqrt{3}) (3 + \sqrt{3})$ using the FOIL Method.

Apply the distributive property.

$\frac{3 (3 + \sqrt{3}) + \sqrt{3} (3 + \sqrt{3})}{6}$

Apply the distributive property.

$\frac{3 \cdot 3 + 3 \sqrt{3} + \sqrt{3} (3 + \sqrt{3})}{6}$

Apply the distributive property.

$\frac{3 \cdot 3 + 3 \sqrt{3} + \sqrt{3} \cdot 3 + \sqrt{3} \sqrt{3}}{6}$

Simplify and combine like terms.

Simplify each term.

Multiply $3$ by $3$ .

$\frac{9 + 3 \sqrt{3} + \sqrt{3} \cdot 3 + \sqrt{3} \sqrt{3}}{6}$

Move $3$ to the left of $\sqrt{3}$ .

$\frac{9 + 3 \sqrt{3} + 3 \cdot \sqrt{3} + \sqrt{3} \sqrt{3}}{6}$

Combine using the product rule for radicals.

$\frac{9 + 3 \sqrt{3} + 3 \sqrt{3} + \sqrt{3 \cdot 3}}{6}$

Multiply $3$ by $3$ .

$\frac{9 + 3 \sqrt{3} + 3 \sqrt{3} + \sqrt{9}}{6}$

Rewrite $9$ as $3^{2}$ .

$\frac{9 + 3 \sqrt{3} + 3 \sqrt{3} + \sqrt{3^{2}}}{6}$

Pull terms out from under the radical, assuming positive real numbers.

$\frac{9 + 3 \sqrt{3} + 3 \sqrt{3} + 3}{6}$

Add $9$ and $3$ .

$\frac{12 + 3 \sqrt{3} + 3 \sqrt{3}}{6}$

Add $3 \sqrt{3}$ and $3 \sqrt{3}$ .

$\frac{12 + 6 \sqrt{3}}{6}$

Cancel the common factor of $12 + 6 \sqrt{3}$ and $6$ .

Factor $6$ out of $12$ .

$\frac{6 \cdot 2 + 6 \sqrt{3}}{6}$

Factor $6$ out of $6 \sqrt{3}$ .

$\frac{6 \cdot 2 + 6 (\sqrt{3})}{6}$

Factor $6$ out of $6 (2) + 6 (\sqrt{3})$ .

$\frac{6 (2 + \sqrt{3})}{6}$

Cancel the common factors.

Factor $6$ out of $6$ .

$\frac{6 (2 + \sqrt{3})}{6 (1)}$

Cancel the common factor.

$\frac{6 (2 + \sqrt{3})}{6 \cdot 1}$

Rewrite the expression.

$\frac{2 + \sqrt{3}}{1}$

Divide $2 + \sqrt{3}$ by $1$ .

$2 + \sqrt{3}$

The result can be shown in multiple forms.

Exact Form:

$2 + \sqrt{3}$

Decimal Form:

$3.73205080 \dots$

Find the Exact Value tan(-105 degrees )

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