Find the Exact Value tan(13 degrees )-(sin(13 degrees ))/(cos(13 degrees ))

$\tan (13 °) - \frac{\sin (13 °)}{\cos (13 °)}$

Step 1

Rewrite $\tan (13 °)$ in terms of sines and cosines.

$\frac{\sin (13 °)}{\cos (13 °)} - \frac{\sin (13 °)}{\cos (13 °)}$

Step 2

Combine the numerators over the common denominator.

$\frac{\sin (13 °) - \sin (13 °)}{\cos (13 °)}$

Step 3

Subtract $\sin (13 °)$ from $\sin (13 °)$ .

$\frac{0}{\cos (13 °)}$

Step 4

Divide $0$ by $\cos (13 °)$ .

$0$