Find the Excluded Values (2x)/(x-3)+6/(3-x)

$\frac{2 x}{x - 3} + \frac{6}{3 - x}$

Step 1

Set the denominator in $\frac{2 x}{x - 3}$ equal to $0$ to find where the expression is undefined.

$x - 3 = 0$

Step 2

Add $3$ to both sides of the equation.

$x = 3$

Step 3

Set the denominator in $\frac{6}{3 - x}$ equal to $0$ to find where the expression is undefined.

$3 - x = 0$

Step 4

Solve for $x$ .

Subtract $3$ from both sides of the equation.

$- x = - 3$

Divide each term in $- x = - 3$ by $- 1$ and simplify.

Divide each term in $- x = - 3$ by $- 1$ .

$\frac{- x}{- 1} = \frac{- 3}{- 1}$

Simplify the left side.

Dividing two negative values results in a positive value.

$\frac{x}{1} = \frac{- 3}{- 1}$

Divide $x$ by $1$ .

$x = \frac{- 3}{- 1}$

Simplify the right side.

Divide $- 3$ by $- 1$ .

$x = 3$

Step 5