Find the Excluded Values (x^2-25)/(3-x)*(x-3)/(x+5)

$\frac{x^{2} - 25}{3 - x} \cdot \frac{x - 3}{x + 5}$

Set the denominator in $\frac{x^{2} - 25}{3 - x}$ equal to $0$ to find where the expression is undefined.

$3 - x = 0$

Solve for $x$ .

Subtract $3$ from both sides of the equation.

$- x = - 3$

Divide each term in $- x = - 3$ by $- 1$ and simplify.

Divide each term in $- x = - 3$ by $- 1$ .

$\frac{- x}{- 1} = \frac{- 3}{- 1}$

Simplify the left side.

Dividing two negative values results in a positive value.

$\frac{x}{1} = \frac{- 3}{- 1}$

Divide $x$ by $1$ .

$x = \frac{- 3}{- 1}$

Simplify the right side.

Divide $- 3$ by $- 1$ .

$x = 3$

Set the denominator in $\frac{x - 3}{x + 5}$ equal to $0$ to find where the expression is undefined.

$x + 5 = 0$

Subtract $5$ from both sides of the equation.

$x = - 5$

The equation is undefined where the denominator equals $0$ , the argument of a square root is less than $0$ , or the argument of a logarithm is less than or equal to $0$ .

$x = - 5, x = 3$

Find the Excluded Values (x^2-25)/(3-x)*(x-3)/(x+5)

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