Find the Excluded Values (x^2-8x+16)/(3x-12)

$\frac{x^{2} - 8 x + 16}{3 x - 12}$

Set the denominator in $\frac{x^{2} - 8 x + 16}{3 x - 12}$ equal to $0$ to find where the expression is undefined.

$3 x - 12 = 0$

Solve for $x$ .

Add $12$ to both sides of the equation.

$3 x = 12$

Divide each term in $3 x = 12$ by $3$ and simplify.

Divide each term in $3 x = 12$ by $3$ .

$\frac{3 x}{3} = \frac{12}{3}$

Simplify the left side.

Cancel the common factor of $3$ .

Cancel the common factor.

$\frac{3 x}{3} = \frac{12}{3}$

Divide $x$ by $1$ .

$x = \frac{12}{3}$

Simplify the right side.

Divide $12$ by $3$ .

$x = 4$