Find the Excluded Values (x+3)/(3x+6)*(6x)/(x^2+5x+6)

$\frac{x + 3}{3 x + 6} \cdot \frac{6 x}{x^{2} + 5 x + 6}$

Set the denominator in $\frac{x + 3}{3 x + 6}$ equal to $0$ to find where the expression is undefined.

$3 x + 6 = 0$

Solve for $x$ .

Subtract $6$ from both sides of the equation.

$3 x = - 6$

Divide each term in $3 x = - 6$ by $3$ and simplify.

Divide each term in $3 x = - 6$ by $3$ .

$\frac{3 x}{3} = \frac{- 6}{3}$

Simplify the left side.

Cancel the common factor of $3$ .

Cancel the common factor.

$\frac{3 x}{3} = \frac{- 6}{3}$

Divide $x$ by $1$ .

$x = \frac{- 6}{3}$

Simplify the right side.

Divide $- 6$ by $3$ .

$x = - 2$

Set the denominator in $\frac{6 x}{x^{2} + 5 x + 6}$ equal to $0$ to find where the expression is undefined.

$x^{2} + 5 x + 6 = 0$

Solve for $x$ .

Factor $x^{2} + 5 x + 6$ using the AC method.

Consider the form $x^{2} + b x + c$ . Find a pair of integers whose product is $c$ and whose sum is $b$ . In this case, whose product is $6$ and whose sum is $5$ .

$2, 3$

Write the factored form using these integers.

$(x + 2) (x + 3) = 0$

If any individual factor on the left side of the equation is equal to $0$ , the entire expression will be equal to $0$ .

$x + 2 = 0$

$x + 3 = 0$

Set $x + 2$ equal to $0$ and solve for $x$ .

Set $x + 2$ equal to $0$ .

$x + 2 = 0$

Subtract $2$ from both sides of the equation.

$x = - 2$

Set $x + 3$ equal to $0$ and solve for $x$ .

Set $x + 3$ equal to $0$ .

$x + 3 = 0$

Subtract $3$ from both sides of the equation.

$x = - 3$

The final solution is all the values that make $(x + 2) (x + 3) = 0$ true.

$x = - 2, - 3$

The equation is undefined where the denominator equals $0$ , the argument of a square root is less than $0$ , or the argument of a logarithm is less than or equal to $0$ .

$x = - 3, x = - 2$

Find the Excluded Values (x+3)/(3x+6)*(6x)/(x^2+5x+6)

Related Questions

Support LCMGCF.com by disabling your adblocker.