Find the Expanded Form (x+4)^2+y^2=22

${(x + 4)}^{2} + y^{2} = 22$

Simplify the left side ${(x + 4)}^{2} + y^{2}$ .

Simplify each term.

Rewrite ${(x + 4)}^{2}$ as $(x + 4) (x + 4)$ .

$(x + 4) (x + 4) + y^{2} = 22$

Expand $(x + 4) (x + 4)$ using the FOIL Method.

Apply the distributive property.

$x (x + 4) + 4 (x + 4) + y^{2} = 22$

Apply the distributive property.

$x \cdot x + x \cdot 4 + 4 (x + 4) + y^{2} = 22$

Apply the distributive property.

$x \cdot x + x \cdot 4 + 4 x + 4 \cdot 4 + y^{2} = 22$

Simplify and combine like terms.

Simplify each term.

Multiply $x$ by $x$ .

$x^{2} + x \cdot 4 + 4 x + 4 \cdot 4 + y^{2} = 22$

Move $4$ to the left of $x$ .

$x^{2} + 4 \cdot x + 4 x + 4 \cdot 4 + y^{2} = 22$

Multiply $4$ by $4$ .

$x^{2} + 4 x + 4 x + 16 + y^{2} = 22$

Add $4 x$ and $4 x$ .

$x^{2} + 8 x + 16 + y^{2} = 22$

Reorder.

Move $16$ .

$x^{2} + 8 x + y^{2} + 16 = 22$

Move $8 x$ .

$x^{2} + y^{2} + 8 x + 16 = 22$

Subtract $22$ from both sides of the equation.

$x^{2} + y^{2} + 8 x + 16 - 22 = 0$

Subtract $22$ from $16$ .

$x^{2} + y^{2} + 8 x - 6 = 0$