Find the Expanded Form (x- square root of 4)^2-(y+3 square root of 2)^2-4=0

${(x - \sqrt{4})}^{2} - {(y + 3 \sqrt{2})}^{2} - 4 = 0$

Step 1

Simplify each term.

Rewrite $4$ as $2^{2}$ .

${(x - \sqrt{2^{2}})}^{2} - {(y + 3 \sqrt{2})}^{2} - 4 = 0$

Pull terms out from under the radical, assuming positive real numbers.

${(x - 1 \cdot 2)}^{2} - {(y + 3 \sqrt{2})}^{2} - 4 = 0$

Multiply $- 1$ by $2$ .

${(x - 2)}^{2} - {(y + 3 \sqrt{2})}^{2} - 4 = 0$

Rewrite ${(x - 2)}^{2}$ as $(x - 2) (x - 2)$ .

$(x - 2) (x - 2) - {(y + 3 \sqrt{2})}^{2} - 4 = 0$

Expand $(x - 2) (x - 2)$ using the FOIL Method.

Apply the distributive property.

$x (x - 2) - 2 (x - 2) - {(y + 3 \sqrt{2})}^{2} - 4 = 0$

Apply the distributive property.

$x \cdot x + x \cdot - 2 - 2 (x - 2) - {(y + 3 \sqrt{2})}^{2} - 4 = 0$

Apply the distributive property.

$x \cdot x + x \cdot - 2 - 2 x - 2 \cdot - 2 - {(y + 3 \sqrt{2})}^{2} - 4 = 0$

Simplify and combine like terms.

Simplify each term.

Multiply $x$ by $x$ .

$x^{2} + x \cdot - 2 - 2 x - 2 \cdot - 2 - {(y + 3 \sqrt{2})}^{2} - 4 = 0$

Move $- 2$ to the left of $x$ .

$x^{2} - 2 \cdot x - 2 x - 2 \cdot - 2 - {(y + 3 \sqrt{2})}^{2} - 4 = 0$

Multiply $- 2$ by $- 2$ .

$x^{2} - 2 x - 2 x + 4 - {(y + 3 \sqrt{2})}^{2} - 4 = 0$

Subtract $2 x$ from $- 2 x$ .

$x^{2} - 4 x + 4 - {(y + 3 \sqrt{2})}^{2} - 4 = 0$

Rewrite ${(y + 3 \sqrt{2})}^{2}$ as $(y + 3 \sqrt{2}) (y + 3 \sqrt{2})$ .

$x^{2} - 4 x + 4 - ((y + 3 \sqrt{2}) (y + 3 \sqrt{2})) - 4 = 0$

Expand $(y + 3 \sqrt{2}) (y + 3 \sqrt{2})$ using the FOIL Method.

Apply the distributive property.

$x^{2} - 4 x + 4 - (y (y + 3 \sqrt{2}) + 3 \sqrt{2} (y + 3 \sqrt{2})) - 4 = 0$

Apply the distributive property.

$x^{2} - 4 x + 4 - (y \cdot y + y (3 \sqrt{2}) + 3 \sqrt{2} (y + 3 \sqrt{2})) - 4 = 0$

Apply the distributive property.

$x^{2} - 4 x + 4 - (y \cdot y + y (3 \sqrt{2}) + 3 \sqrt{2} y + 3 \sqrt{2} (3 \sqrt{2})) - 4 = 0$

Simplify and combine like terms.

Simplify each term.

Multiply $y$ by $y$ .

$x^{2} - 4 x + 4 - (y^{2} + y (3 \sqrt{2}) + 3 \sqrt{2} y + 3 \sqrt{2} (3 \sqrt{2})) - 4 = 0$

Move $3$ to the left of $y$ .

$x^{2} - 4 x + 4 - (y^{2} + 3 \cdot (y \sqrt{2}) + 3 \sqrt{2} y + 3 \sqrt{2} (3 \sqrt{2})) - 4 = 0$

Multiply $3 \sqrt{2} (3 \sqrt{2})$ .

Multiply $3$ by $3$ .

$x^{2} - 4 x + 4 - (y^{2} + 3 y \sqrt{2} + 3 \sqrt{2} y + 9 \sqrt{2} \sqrt{2}) - 4 = 0$

Raise $\sqrt{2}$ to the power of $1$ .

$x^{2} - 4 x + 4 - (y^{2} + 3 y \sqrt{2} + 3 \sqrt{2} y + 9 (\sqrt{2} \sqrt{2})) - 4 = 0$

Raise $\sqrt{2}$ to the power of $1$ .

$x^{2} - 4 x + 4 - (y^{2} + 3 y \sqrt{2} + 3 \sqrt{2} y + 9 (\sqrt{2} \sqrt{2})) - 4 = 0$

Use the power rule $a^{m} a^{n} = a^{m + n}$ to combine exponents.

$x^{2} - 4 x + 4 - (y^{2} + 3 y \sqrt{2} + 3 \sqrt{2} y + 9 {\sqrt{2}}^{1 + 1}) - 4 = 0$

Add $1$ and $1$ .

$x^{2} - 4 x + 4 - (y^{2} + 3 y \sqrt{2} + 3 \sqrt{2} y + 9 {\sqrt{2}}^{2}) - 4 = 0$

Rewrite ${\sqrt{2}}^{2}$ as $2$ .

Use $\sqrt[n]{a^{x}} = a^{\frac{x}{n}}$ to rewrite $\sqrt{2}$ as $2^{\frac{1}{2}}$ .

$x^{2} - 4 x + 4 - (y^{2} + 3 y \sqrt{2} + 3 \sqrt{2} y + 9 {(2^{\frac{1}{2}})}^{2}) - 4 = 0$

Apply the power rule and multiply exponents, ${(a^{m})}^{n} = a^{m n}$ .

$x^{2} - 4 x + 4 - (y^{2} + 3 y \sqrt{2} + 3 \sqrt{2} y + 9 \cdot 2^{\frac{1}{2} \cdot 2}) - 4 = 0$

Combine $\frac{1}{2}$ and $2$ .

$x^{2} - 4 x + 4 - (y^{2} + 3 y \sqrt{2} + 3 \sqrt{2} y + 9 \cdot 2^{\frac{2}{2}}) - 4 = 0$

Cancel the common factor of $2$ .

Cancel the common factor.

$x^{2} - 4 x + 4 - (y^{2} + 3 y \sqrt{2} + 3 \sqrt{2} y + 9 \cdot 2^{\frac{2}{2}}) - 4 = 0$

Rewrite the expression.

$x^{2} - 4 x + 4 - (y^{2} + 3 y \sqrt{2} + 3 \sqrt{2} y + 9 \cdot 2) - 4 = 0$

Evaluate the exponent.

$x^{2} - 4 x + 4 - (y^{2} + 3 y \sqrt{2} + 3 \sqrt{2} y + 9 \cdot 2) - 4 = 0$

Multiply $9$ by $2$ .

$x^{2} - 4 x + 4 - (y^{2} + 3 y \sqrt{2} + 3 \sqrt{2} y + 18) - 4 = 0$

Reorder the factors of $3 \sqrt{2} y$ .

$x^{2} - 4 x + 4 - (y^{2} + 3 y \sqrt{2} + 3 y \sqrt{2} + 18) - 4 = 0$

Add $3 y \sqrt{2}$ and $3 y \sqrt{2}$ .

$x^{2} - 4 x + 4 - (y^{2} + 6 y \sqrt{2} + 18) - 4 = 0$

Apply the distributive property.

$x^{2} - 4 x + 4 - y^{2} - (6 y \sqrt{2}) - 1 \cdot 18 - 4 = 0$

Simplify.

Multiply $6$ by $- 1$ .

$x^{2} - 4 x + 4 - y^{2} - 6 (y \sqrt{2}) - 1 \cdot 18 - 4 = 0$

Multiply $- 1$ by $18$ .

$x^{2} - 4 x + 4 - y^{2} - 6 (y \sqrt{2}) - 18 - 4 = 0$

$x^{2} - 4 x + 4 - y^{2} - 6 y \sqrt{2} - 18 - 4 = 0$

Step 2

Simplify by adding terms.

Combine the opposite terms in $x^{2} - 4 x + 4 - y^{2} - 6 y \sqrt{2} - 18 - 4$ .

Subtract $4$ from $4$ .

$x^{2} - 4 x - y^{2} - 6 y \sqrt{2} - 18 + 0 = 0$

Add $x^{2} - 4 x - y^{2} - 6 y \sqrt{2} - 18$ and $0$ .

$x^{2} - 4 x - y^{2} - 6 y \sqrt{2} - 18 = 0$

Move $- 4 x$ .

$x^{2} - y^{2} - 4 x - 6 y \sqrt{2} - 18 = 0$

Find the Expanded Form (x- square root of 4)^2-(y+3 square root of 2)^2-4=0

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