Find the First Term a_n=11/8+1/2n

$a_{n} = \frac{11}{8} + \frac{1}{2} n$

Step 1

Substitute in the value of $n$ to find the $n$ th term.

$a_{1} = \frac{11}{8} + \frac{1}{2} \cdot (1)$

Step 2

Multiply $\frac{1}{2}$ by $1$ .

$a_{1} = \frac{11}{8} + \frac{1}{2}$

Step 3

To write $\frac{1}{2}$ as a fraction with a common denominator, multiply by $\frac{4}{4}$ .

$a_{1} = \frac{11}{8} + \frac{1}{2} \cdot \frac{4}{4}$

Step 4

Write each expression with a common denominator of $8$ , by multiplying each by an appropriate factor of $1$ .

Multiply $\frac{1}{2}$ by $\frac{4}{4}$ .

$a_{1} = \frac{11}{8} + \frac{4}{2 \cdot 4}$

Multiply $2$ by $4$ .

$a_{1} = \frac{11}{8} + \frac{4}{8}$

Step 5

Combine the numerators over the common denominator.

$a_{1} = \frac{11 + 4}{8}$

Step 6

Add $11$ and $4$ .

$a_{1} = \frac{15}{8}$