Find the First Term a_n=2*(1/4)^(n-1)

$a_{n} = 2 \cdot {(\frac{1}{4})}^{n - 1}$

Step 1

Substitute in the value of $n$ to find the $n$ th term.

$a_{1} = 2 \cdot {(\frac{1}{4})}^{(1) - 1}$

Step 2

Simplify the expression.

Subtract $1$ from $1$ .

$a_{1} = 2 \cdot {(\frac{1}{4})}^{0}$

Apply the product rule to $\frac{1}{4}$ .

$a_{1} = 2 \cdot \frac{1^{0}}{4^{0}}$

Anything raised to $0$ is $1$ .

$a_{1} = 2 \cdot \frac{1}{4^{0}}$

Anything raised to $0$ is $1$ .

$a_{1} = 2 \cdot \frac{1}{1}$

Step 3

Cancel the common factor of $1$ .

Cancel the common factor.

$a_{1} = 2 \cdot \frac{1}{1}$

Rewrite the expression.

$a_{1} = 2 \cdot 1$

Step 4

Multiply $2$ by $1$ .

$a_{1} = 2$