Find the First Term a_n=2(3)^(n-1)

$a_{n} = 2 {(3)}^{n - 1}$

Substitute in the value of $n$ to find the $n$ th term.

$a_{1} = 2 {(3)}^{(1) - 1}$

Subtract $1$ from $1$ .

$a_{1} = 2 \cdot 3^{0}$

Anything raised to $0$ is $1$ .

$a_{1} = 2 \cdot 1$

Multiply $2$ by $1$ .

$a_{1} = 2$