Find the Foci 5x^2-4y^2+80=0

$5 x^{2} - 4 y^{2} + 80 = 0$

Find the standard form of the hyperbola.

Subtract $80$ from both sides of the equation.

$5 x^{2} - 4 y^{2} = - 80$

Flip the sign on each term of the equation so the term on the right side is positive.

$- 5 x^{2} + 4 y^{2} = 80$

Divide each term by $80$ to make the right side equal to one.

$- \frac{5 x^{2}}{80} + \frac{4 y^{2}}{80} = \frac{80}{80}$

Simplify each term in the equation in order to set the right side equal to $1$ . The standard form of an ellipse or hyperbola requires the right side of the equation be $1$ .

$\frac{y^{2}}{20} - \frac{x^{2}}{16} = 1$

This is the form of a hyperbola. Use this form to determine the values used to find vertices and asymptotes of the hyperbola.

$\frac{{(y - k)}^{2}}{a^{2}} - \frac{{(x - h)}^{2}}{b^{2}} = 1$

Match the values in this hyperbola to those of the standard form. The variable $h$ represents the x-offset from the origin, $k$ represents the y-offset from origin, $a$ .

$a = 2 \sqrt{5}$

$b = 4$

$k = 0$

$h = 0$

Find $c$ , the distance from the center to a focus.

Find the distance from the center to a focus of the hyperbola by using the following formula.

$\sqrt{a^{2} + b^{2}}$

Substitute the values of $a$ and $b$ in the formula.

$\sqrt{{(2 \sqrt{5})}^{2} + {(4)}^{2}}$

Simplify.

Simplify the expression.

Apply the product rule to $2 \sqrt{5}$ .

$\sqrt{2^{2} {\sqrt{5}}^{2} + {(4)}^{2}}$

Raise $2$ to the power of $2$ .

$\sqrt{4 {\sqrt{5}}^{2} + {(4)}^{2}}$

Rewrite ${\sqrt{5}}^{2}$ as $5$ .

Use $\sqrt[n]{a^{x}} = a^{\frac{x}{n}}$ to rewrite $\sqrt{5}$ as $5^{\frac{1}{2}}$ .

$\sqrt{4 {(5^{\frac{1}{2}})}^{2} + {(4)}^{2}}$

Apply the power rule and multiply exponents, ${(a^{m})}^{n} = a^{m n}$ .

$\sqrt{4 \cdot 5^{\frac{1}{2} \cdot 2} + {(4)}^{2}}$

Combine $\frac{1}{2}$ and $2$ .

$\sqrt{4 \cdot 5^{\frac{2}{2}} + {(4)}^{2}}$

Cancel the common factor of $2$ .

Cancel the common factor.

$\sqrt{4 \cdot 5^{\frac{2}{2}} + {(4)}^{2}}$

Rewrite the expression.

$\sqrt{4 \cdot 5^{1} + {(4)}^{2}}$

Evaluate the exponent.

$\sqrt{4 \cdot 5 + {(4)}^{2}}$

Simplify the expression.

Multiply $4$ by $5$ .

$\sqrt{20 + {(4)}^{2}}$

Raise $4$ to the power of $2$ .

$\sqrt{20 + 16}$

Add $20$ and $16$ .

$\sqrt{36}$

Rewrite $36$ as $6^{2}$ .

$\sqrt{6^{2}}$

Pull terms out from under the radical, assuming positive real numbers.

$6$

Find the foci.

The first focus of a hyperbola can be found by adding $c$ to $k$ .

$(h, k + c)$

Substitute the known values of $h$ , $c$ , and $k$ into the formula and simplify.

$(0, 6)$

The second focus of a hyperbola can be found by subtracting $c$ from $k$ .

$(h, k - c)$

Substitute the known values of $h$ , $c$ , and $k$ into the formula and simplify.

$(0, - 6)$

The foci of a hyperbola follow the form of $(h, k \pm \sqrt{a^{2} + b^{2}})$ . Hyperbolas have two foci.

$(0, 6), (0, - 6)$

Find the Foci 5x^2-4y^2+80=0

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