Find the Focus (x+4)^2=12(y-2)

${(x + 4)}^{2} = 12 (y - 2)$

Step 1

Rewrite the equation in vertex form.

Isolate $y$ to the left side of the equation.

Rewrite the equation as $12 (y - 2) = {(x + 4)}^{2}$ .

$12 (y - 2) = {(x + 4)}^{2}$

Divide each term in $12 (y - 2) = {(x + 4)}^{2}$ by $12$ and simplify.

Divide each term in $12 (y - 2) = {(x + 4)}^{2}$ by $12$ .

$\frac{12 (y - 2)}{12} = \frac{{(x + 4)}^{2}}{12}$

Simplify the left side.

Cancel the common factor of $12$ .

Cancel the common factor.

$\frac{12 (y - 2)}{12} = \frac{{(x + 4)}^{2}}{12}$

Divide $y - 2$ by $1$ .

$y - 2 = \frac{{(x + 4)}^{2}}{12}$

Add $2$ to both sides of the equation.

$y = \frac{{(x + 4)}^{2}}{12} + 2$

Reorder terms.

$y = \frac{1}{12} \cdot {(x + 4)}^{2} + 2$

Complete the square for $\frac{1}{12} \cdot {(x + 4)}^{2} + 2$ .

Simplify the expression.

Simplify each term.

Rewrite ${(x + 4)}^{2}$ as $(x + 4) (x + 4)$ .

$\frac{1}{12} \cdot ((x + 4) (x + 4)) + 2$

Expand $(x + 4) (x + 4)$ using the FOIL Method.

Apply the distributive property.

$\frac{1}{12} \cdot (x (x + 4) + 4 (x + 4)) + 2$

Apply the distributive property.

$\frac{1}{12} \cdot (x \cdot x + x \cdot 4 + 4 (x + 4)) + 2$

Apply the distributive property.

$\frac{1}{12} \cdot (x \cdot x + x \cdot 4 + 4 x + 4 \cdot 4) + 2$

Simplify and combine like terms.

Simplify each term.

Multiply $x$ by $x$ .

$\frac{1}{12} \cdot (x^{2} + x \cdot 4 + 4 x + 4 \cdot 4) + 2$

Move $4$ to the left of $x$ .

$\frac{1}{12} \cdot (x^{2} + 4 \cdot x + 4 x + 4 \cdot 4) + 2$

Multiply $4$ by $4$ .

$\frac{1}{12} \cdot (x^{2} + 4 x + 4 x + 16) + 2$

Add $4 x$ and $4 x$ .

$\frac{1}{12} \cdot (x^{2} + 8 x + 16) + 2$

Apply the distributive property.

$\frac{1}{12} x^{2} + \frac{1}{12} (8 x) + \frac{1}{12} \cdot 16 + 2$

Simplify.

Combine $\frac{1}{12}$ and $x^{2}$ .

$\frac{x^{2}}{12} + \frac{1}{12} (8 x) + \frac{1}{12} \cdot 16 + 2$

Cancel the common factor of $4$ .

Factor $4$ out of $12$ .

$\frac{x^{2}}{12} + \frac{1}{4 (3)} (8 x) + \frac{1}{12} \cdot 16 + 2$

Factor $4$ out of $8 x$ .

$\frac{x^{2}}{12} + \frac{1}{4 (3)} (4 (2 x)) + \frac{1}{12} \cdot 16 + 2$

Cancel the common factor.

$\frac{x^{2}}{12} + \frac{1}{4 \cdot 3} (4 (2 x)) + \frac{1}{12} \cdot 16 + 2$

Rewrite the expression.

$\frac{x^{2}}{12} + \frac{1}{3} (2 x) + \frac{1}{12} \cdot 16 + 2$

Combine $2$ and $\frac{1}{3}$ .

$\frac{x^{2}}{12} + \frac{2}{3} x + \frac{1}{12} \cdot 16 + 2$

Combine $\frac{2}{3}$ and $x$ .

$\frac{x^{2}}{12} + \frac{2 x}{3} + \frac{1}{12} \cdot 16 + 2$

Cancel the common factor of $4$ .

Factor $4$ out of $12$ .

$\frac{x^{2}}{12} + \frac{2 x}{3} + \frac{1}{4 (3)} \cdot 16 + 2$

Factor $4$ out of $16$ .

$\frac{x^{2}}{12} + \frac{2 x}{3} + \frac{1}{4 \cdot 3} \cdot (4 \cdot 4) + 2$

Cancel the common factor.

$\frac{x^{2}}{12} + \frac{2 x}{3} + \frac{1}{4 \cdot 3} \cdot (4 \cdot 4) + 2$

Rewrite the expression.

$\frac{x^{2}}{12} + \frac{2 x}{3} + \frac{1}{3} \cdot 4 + 2$

Combine $\frac{1}{3}$ and $4$ .

$\frac{x^{2}}{12} + \frac{2 x}{3} + \frac{4}{3} + 2$

To write $2$ as a fraction with a common denominator, multiply by $\frac{3}{3}$ .

$\frac{x^{2}}{12} + \frac{2 x}{3} + \frac{4}{3} + 2 \cdot \frac{3}{3}$

Combine $2$ and $\frac{3}{3}$ .

$\frac{x^{2}}{12} + \frac{2 x}{3} + \frac{4}{3} + \frac{2 \cdot 3}{3}$

Combine the numerators over the common denominator.

$\frac{x^{2}}{12} + \frac{2 x}{3} + \frac{4 + 2 \cdot 3}{3}$

Simplify the numerator.

Multiply $2$ by $3$ .

$\frac{x^{2}}{12} + \frac{2 x}{3} + \frac{4 + 6}{3}$

Add $4$ and $6$ .

$\frac{x^{2}}{12} + \frac{2 x}{3} + \frac{10}{3}$

Use the form $a x^{2} + b x + c$ , to find the values of $a$ , $b$ , and $c$ .

$a = \frac{1}{12}$

$b = \frac{2}{3}$

$c = \frac{10}{3}$

Consider the vertex form of a parabola.

$a {(x + d)}^{2} + e$

Find the value of $d$ using the formula $d = \frac{b}{2 a}$ .

Substitute the values of $a$ and $b$ into the formula $d = \frac{b}{2 a}$ .

$d = \frac{\frac{2}{3}}{2 (\frac{1}{12})}$

Simplify the right side.

Multiply the numerator by the reciprocal of the denominator.

$d = \frac{2}{3} \cdot \frac{1}{2 (\frac{1}{12})}$

Cancel the common factor of $2$ .

Cancel the common factor.

$d = \frac{2}{3} \cdot \frac{1}{2 (\frac{1}{12})}$

Rewrite the expression.

$d = \frac{1}{3} \cdot \frac{1}{\frac{1}{12}}$

Multiply $\frac{1}{3}$ by $\frac{1}{\frac{1}{12}}$ .

$d = \frac{1}{3 (\frac{1}{12})}$

Combine $3$ and $\frac{1}{12}$ .

$d = \frac{1}{\frac{3}{12}}$

Cancel the common factor of $3$ and $12$ .

Factor $3$ out of $3$ .

$d = \frac{1}{\frac{3 (1)}{12}}$

Cancel the common factors.

Factor $3$ out of $12$ .

$d = \frac{1}{\frac{3 \cdot 1}{3 \cdot 4}}$

Cancel the common factor.

$d = \frac{1}{\frac{3 \cdot 1}{3 \cdot 4}}$

Rewrite the expression.

$d = \frac{1}{\frac{1}{4}}$

Multiply the numerator by the reciprocal of the denominator.

$d = 1 \cdot 4$

Multiply $4$ by $1$ .

$d = 4$

Find the value of $e$ using the formula $e = c - \frac{b^{2}}{4 a}$ .

Substitute the values of $c$ , $b$ and $a$ into the formula $e = c - \frac{b^{2}}{4 a}$ .

$e = \frac{10}{3} - \frac{{(\frac{2}{3})}^{2}}{4 (\frac{1}{12})}$

Simplify the right side.

Simplify each term.

Simplify the numerator.

Apply the product rule to $\frac{2}{3}$ .

$e = \frac{10}{3} - \frac{\frac{2^{2}}{3^{2}}}{4 (\frac{1}{12})}$

Raise $2$ to the power of $2$ .

$e = \frac{10}{3} - \frac{\frac{4}{3^{2}}}{4 (\frac{1}{12})}$

Raise $3$ to the power of $2$ .

$e = \frac{10}{3} - \frac{\frac{4}{9}}{4 (\frac{1}{12})}$

Combine $4$ and $\frac{1}{12}$ .

$e = \frac{10}{3} - \frac{\frac{4}{9}}{\frac{4}{12}}$

Cancel the common factor of $4$ and $12$ .

Factor $4$ out of $4$ .

$e = \frac{10}{3} - \frac{\frac{4}{9}}{\frac{4 (1)}{12}}$

Cancel the common factors.

Factor $4$ out of $12$ .

$e = \frac{10}{3} - \frac{\frac{4}{9}}{\frac{4 \cdot 1}{4 \cdot 3}}$

Cancel the common factor.

$e = \frac{10}{3} - \frac{\frac{4}{9}}{\frac{4 \cdot 1}{4 \cdot 3}}$

Rewrite the expression.

$e = \frac{10}{3} - \frac{\frac{4}{9}}{\frac{1}{3}}$

Multiply the numerator by the reciprocal of the denominator.

$e = \frac{10}{3} - (\frac{4}{9} \cdot 3)$

Cancel the common factor of $3$ .

Factor $3$ out of $9$ .

$e = \frac{10}{3} - (\frac{4}{3 (3)} \cdot 3)$

Cancel the common factor.

$e = \frac{10}{3} - (\frac{4}{3 \cdot 3} \cdot 3)$

Rewrite the expression.

$e = \frac{10}{3} - \frac{4}{3}$

Combine the numerators over the common denominator.

$e = \frac{10 - 4}{3}$

Subtract $4$ from $10$ .

$e = \frac{6}{3}$

Divide $6$ by $3$ .

$e = 2$

Substitute the values of $a$ , $d$ , and $e$ into the vertex form $\frac{1}{12} {(x + 4)}^{2} + 2$ .

$\frac{1}{12} {(x + 4)}^{2} + 2$

Set $y$ equal to the new right side.

$y = \frac{1}{12} \cdot {(x + 4)}^{2} + 2$

Step 2

Use the vertex form, $y = a {(x - h)}^{2} + k$ , to determine the values of $a$ , $h$ , and $k$ .

$a = \frac{1}{12}$

$h = - 4$

$k = 2$

Step 3

Find the vertex $(h, k)$ .

$(- 4, 2)$

Step 4

Find $p$ , the distance from the vertex to the focus.

Find the distance from the vertex to a focus of the parabola by using the following formula.

$\frac{1}{4 a}$

Substitute the value of $a$ into the formula.

$\frac{1}{4 \cdot \frac{1}{12}}$

Simplify.

Combine $4$ and $\frac{1}{12}$ .

$\frac{1}{\frac{4}{12}}$

Cancel the common factor of $4$ and $12$ .

Factor $4$ out of $4$ .

$\frac{1}{\frac{4 (1)}{12}}$

Cancel the common factors.

Factor $4$ out of $12$ .

$\frac{1}{\frac{4 \cdot 1}{4 \cdot 3}}$

Cancel the common factor.

$\frac{1}{\frac{4 \cdot 1}{4 \cdot 3}}$

Rewrite the expression.

$\frac{1}{\frac{1}{3}}$

Multiply the numerator by the reciprocal of the denominator.

$1 \cdot 3$

Multiply $3$ by $1$ .

$3$

Step 5

Find the focus.

The focus of a parabola can be found by adding $p$ to the y-coordinate $k$ if the parabola opens up or down.

$(h, k + p)$

Substitute the known values of $h$ , $p$ , and $k$ into the formula and simplify.

$(- 4, 5)$

Step 6

Find the Focus (x+4)^2=12(y-2)

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