Find the Function f(x)=4x-7

$f (x) = 4 x - 7$

The function $F (x)$ can be found by evaluating the indefinite integral of the derivative $f (x)$ .

$F (x) = \int f (x) d x$

Split the single integral into multiple integrals.

$\int 4 x d x + \int - 7 d x$

Since $4$ is constant with respect to $x$ , move $4$ out of the integral.

$4 \int x d x + \int - 7 d x$

By the Power Rule, the integral of $x$ with respect to $x$ is $\frac{1}{2} x^{2}$ .

$4 (\frac{1}{2} x^{2} + C) + \int - 7 d x$

Apply the constant rule.

$4 (\frac{1}{2} x^{2} + C) - 7 x + C$

Simplify.

Combine $\frac{1}{2}$ and $x^{2}$ .

$4 (\frac{x^{2}}{2} + C) - 7 x + C$

Simplify.

$2 x^{2} - 7 x + C$

The function $F$ if derived from the integral of the derivative of the function. This is valid by the fundamental theorem of calculus.

$F (x) = 2 x^{2} - 7 x + C$