Find the Function Rule table[[x,y],[1,15],[2,45],[3,135]]

$\begin{array}{c} x & y \\ 1 & 15 \\ 2 & 45 \\ 3 & 135 \end{array}$

Step 1

Check if the function rule is linear.

To find if the table follows a function rule, check to see if the values follow the linear form $y = a x + b$ .

$y = a x + b$

Build a set of equations from the table such that $y = a x + b$ .

$15 = a (1) + b 45 = a (2) + b 135 = a (3) + b$

Calculate the values of $a$ and $b$ .

Solve for $a$ in $15 = a + b$ .

Rewrite the equation as $a + b = 15$ .

$a + b = 15$

$45 = a (2) + b$

$135 = a (3) + b$

Subtract $b$ from both sides of the equation.

$a = 15 - b$

$45 = a (2) + b$

$135 = a (3) + b$

$a = 15 - b$

$45 = a (2) + b$

$135 = a (3) + b$

Replace all occurrences of $a$ with $15 - b$ in each equation.

Replace all occurrences of $a$ in $45 = a (2) + b$ with $15 - b$ .

$45 = (15 - b) (2) + b$

$a = 15 - b$

$135 = a (3) + b$

Simplify the right side.

Simplify $(15 - b) (2) + b$ .

Simplify each term.

Apply the distributive property.

$45 = 15 \cdot 2 - b \cdot 2 + b$

$a = 15 - b$

$135 = a (3) + b$

Multiply $15$ by $2$ .

$45 = 30 - b \cdot 2 + b$

$a = 15 - b$

$135 = a (3) + b$

Multiply $2$ by $- 1$ .

$45 = 30 - 2 b + b$

$a = 15 - b$

$135 = a (3) + b$

$45 = 30 - 2 b + b$

$a = 15 - b$

$135 = a (3) + b$

Add $- 2 b$ and $b$ .

$45 = 30 - b$

$a = 15 - b$

$135 = a (3) + b$

$45 = 30 - b$

$a = 15 - b$

$135 = a (3) + b$

$45 = 30 - b$

$a = 15 - b$

$135 = a (3) + b$

Replace all occurrences of $a$ in $135 = a (3) + b$ with $15 - b$ .

$135 = (15 - b) (3) + b$

$45 = 30 - b$

$a = 15 - b$

Simplify the right side.

Simplify $(15 - b) (3) + b$ .

Simplify each term.

Apply the distributive property.

$135 = 15 \cdot 3 - b \cdot 3 + b$

$45 = 30 - b$

$a = 15 - b$

Multiply $15$ by $3$ .

$135 = 45 - b \cdot 3 + b$

$45 = 30 - b$

$a = 15 - b$

Multiply $3$ by $- 1$ .

$135 = 45 - 3 b + b$

$45 = 30 - b$

$a = 15 - b$

$135 = 45 - 3 b + b$

$45 = 30 - b$

$a = 15 - b$

Add $- 3 b$ and $b$ .

$135 = 45 - 2 b$

$45 = 30 - b$

$a = 15 - b$

$135 = 45 - 2 b$

$45 = 30 - b$

$a = 15 - b$

$135 = 45 - 2 b$

$45 = 30 - b$

$a = 15 - b$

$135 = 45 - 2 b$

$45 = 30 - b$

$a = 15 - b$

Solve for $b$ in $135 = 45 - 2 b$ .

Rewrite the equation as $45 - 2 b = 135$ .

$45 - 2 b = 135$

$45 = 30 - b$

$a = 15 - b$

Move all terms not containing $b$ to the right side of the equation.

Subtract $45$ from both sides of the equation.

$- 2 b = 135 - 45$

$45 = 30 - b$

$a = 15 - b$

Subtract $45$ from $135$ .

$- 2 b = 90$

$45 = 30 - b$

$a = 15 - b$

$- 2 b = 90$

$45 = 30 - b$

$a = 15 - b$

Divide each term in $- 2 b = 90$ by $- 2$ and simplify.

Divide each term in $- 2 b = 90$ by $- 2$ .

$\frac{- 2 b}{- 2} = \frac{90}{- 2}$

$45 = 30 - b$

$a = 15 - b$

Simplify the left side.

Cancel the common factor of $- 2$ .

Cancel the common factor.

$\frac{- 2 b}{- 2} = \frac{90}{- 2}$

$45 = 30 - b$

$a = 15 - b$

Divide $b$ by $1$ .

$b = \frac{90}{- 2}$

$45 = 30 - b$

$a = 15 - b$

$b = \frac{90}{- 2}$

$45 = 30 - b$

$a = 15 - b$

$b = \frac{90}{- 2}$

$45 = 30 - b$

$a = 15 - b$

Simplify the right side.

Divide $90$ by $- 2$ .

$b = - 45$

$45 = 30 - b$

$a = 15 - b$

$b = - 45$

$45 = 30 - b$

$a = 15 - b$

$b = - 45$

$45 = 30 - b$

$a = 15 - b$

$b = - 45$

$45 = 30 - b$

$a = 15 - b$

Replace all occurrences of $b$ with $- 45$ in each equation.

Replace all occurrences of $b$ in $45 = 30 - b$ with $- 45$ .

$45 = 30 - (- 45)$

$b = - 45$

$a = 15 - b$

Simplify the right side.

Simplify $30 - (- 45)$ .

Multiply $- 1$ by $- 45$ .

$45 = 30 + 45$

$b = - 45$

$a = 15 - b$

Add $30$ and $45$ .

$45 = 75$

$b = - 45$

$a = 15 - b$

$45 = 75$

$b = - 45$

$a = 15 - b$

$45 = 75$

$b = - 45$

$a = 15 - b$

Replace all occurrences of $b$ in $a = 15 - b$ with $- 45$ .

$a = 15 - (- 45)$

$45 = 75$

$b = - 45$

Simplify the right side.

Simplify $15 - (- 45)$ .

Multiply $- 1$ by $- 45$ .

$a = 15 + 45$

$45 = 75$

$b = - 45$

Add $15$ and $45$ .

$a = 60$

$45 = 75$

$b = - 45$

$a = 60$

$45 = 75$

$b = - 45$

$a = 60$

$45 = 75$

$b = - 45$

$a = 60$

$45 = 75$

$b = - 45$

Since $45 = 75$ is not true, there is no solution.

No solution

Since $y \neq y$ for the corresponding $x$ values, the function is not linear.

The function is not linear

Step 2

Check if the function rule is quadratic.

To find if the table follows a function rule, check whether the function rule could follow the form $y = a x^{2} + b x + c$ .

$y = a x^{2} + b x + c$

Build a set of $3$ equations from the table such that $y = a x^{2} + b x + c$ .

Calculate the values of $a$ , $b$ , and $c$ .

Solve for $a$ in $15 = a + b + c$ .

Rewrite the equation as $a + b + c = 15$ .

$a + b + c = 15$

$45 = a \cdot 2^{2} + b (2) + c$

$135 = a \cdot 3^{2} + b (3) + c$

Move all terms not containing $a$ to the right side of the equation.

Subtract $b$ from both sides of the equation.

$a + c = 15 - b$

$45 = a \cdot 2^{2} + b (2) + c$

$135 = a \cdot 3^{2} + b (3) + c$

Subtract $c$ from both sides of the equation.

$a = 15 - b - c$

$45 = a \cdot 2^{2} + b (2) + c$

$135 = a \cdot 3^{2} + b (3) + c$

$a = 15 - b - c$

$45 = a \cdot 2^{2} + b (2) + c$

$135 = a \cdot 3^{2} + b (3) + c$

$a = 15 - b - c$

$45 = a \cdot 2^{2} + b (2) + c$

$135 = a \cdot 3^{2} + b (3) + c$

Replace all occurrences of $a$ with $15 - b - c$ in each equation.

Replace all occurrences of $a$ in $45 = a \cdot 2^{2} + b (2) + c$ with $15 - b - c$ .

$45 = (15 - b - c) \cdot 2^{2} + b (2) + c$

$a = 15 - b - c$

$135 = a \cdot 3^{2} + b (3) + c$

Simplify the right side.

Simplify $(15 - b - c) \cdot 2^{2} + b (2) + c$ .

Simplify each term.

Raise $2$ to the power of $2$ .

$45 = (15 - b - c) \cdot 4 + b (2) + c$

$a = 15 - b - c$

$135 = a \cdot 3^{2} + b (3) + c$

Apply the distributive property.

$45 = 15 \cdot 4 - b \cdot 4 - c \cdot 4 + b (2) + c$

$a = 15 - b - c$

$135 = a \cdot 3^{2} + b (3) + c$

Simplify.

Multiply $15$ by $4$ .

$45 = 60 - b \cdot 4 - c \cdot 4 + b (2) + c$

$a = 15 - b - c$

$135 = a \cdot 3^{2} + b (3) + c$

Multiply $4$ by $- 1$ .

$45 = 60 - 4 b - c \cdot 4 + b (2) + c$

$a = 15 - b - c$

$135 = a \cdot 3^{2} + b (3) + c$

Multiply $4$ by $- 1$ .

$45 = 60 - 4 b - 4 c + b (2) + c$

$a = 15 - b - c$

$135 = a \cdot 3^{2} + b (3) + c$

$45 = 60 - 4 b - 4 c + b (2) + c$

$a = 15 - b - c$

$135 = a \cdot 3^{2} + b (3) + c$

Move $2$ to the left of $b$ .

$45 = 60 - 4 b - 4 c + 2 b + c$

$a = 15 - b - c$

$135 = a \cdot 3^{2} + b (3) + c$

$45 = 60 - 4 b - 4 c + 2 b + c$

$a = 15 - b - c$

$135 = a \cdot 3^{2} + b (3) + c$

Simplify by adding terms.

Add $- 4 b$ and $2 b$ .

$45 = 60 - 2 b - 4 c + c$

$a = 15 - b - c$

$135 = a \cdot 3^{2} + b (3) + c$

Add $- 4 c$ and $c$ .

$45 = 60 - 2 b - 3 c$

$a = 15 - b - c$

$135 = a \cdot 3^{2} + b (3) + c$

$45 = 60 - 2 b - 3 c$

$a = 15 - b - c$

$135 = a \cdot 3^{2} + b (3) + c$

$45 = 60 - 2 b - 3 c$

$a = 15 - b - c$

$135 = a \cdot 3^{2} + b (3) + c$

$45 = 60 - 2 b - 3 c$

$a = 15 - b - c$

$135 = a \cdot 3^{2} + b (3) + c$

Replace all occurrences of $a$ in $135 = a \cdot 3^{2} + b (3) + c$ with $15 - b - c$ .

$135 = (15 - b - c) \cdot 3^{2} + b (3) + c$

$45 = 60 - 2 b - 3 c$

$a = 15 - b - c$

Simplify the right side.

Simplify $(15 - b - c) \cdot 3^{2} + b (3) + c$ .

Simplify each term.

Raise $3$ to the power of $2$ .

$135 = (15 - b - c) \cdot 9 + b (3) + c$

$45 = 60 - 2 b - 3 c$

$a = 15 - b - c$

Apply the distributive property.

$135 = 15 \cdot 9 - b \cdot 9 - c \cdot 9 + b (3) + c$

$45 = 60 - 2 b - 3 c$

$a = 15 - b - c$

Simplify.

Multiply $15$ by $9$ .

$135 = 135 - b \cdot 9 - c \cdot 9 + b (3) + c$

$45 = 60 - 2 b - 3 c$

$a = 15 - b - c$

Multiply $9$ by $- 1$ .

$135 = 135 - 9 b - c \cdot 9 + b (3) + c$

$45 = 60 - 2 b - 3 c$

$a = 15 - b - c$

Multiply $9$ by $- 1$ .

$135 = 135 - 9 b - 9 c + b (3) + c$

$45 = 60 - 2 b - 3 c$

$a = 15 - b - c$

$135 = 135 - 9 b - 9 c + b (3) + c$

$45 = 60 - 2 b - 3 c$

$a = 15 - b - c$

Move $3$ to the left of $b$ .

$135 = 135 - 9 b - 9 c + 3 b + c$

$45 = 60 - 2 b - 3 c$

$a = 15 - b - c$

$135 = 135 - 9 b - 9 c + 3 b + c$

$45 = 60 - 2 b - 3 c$

$a = 15 - b - c$

Simplify by adding terms.

Add $- 9 b$ and $3 b$ .

$135 = 135 - 6 b - 9 c + c$

$45 = 60 - 2 b - 3 c$

$a = 15 - b - c$

Add $- 9 c$ and $c$ .

$135 = 135 - 6 b - 8 c$

$45 = 60 - 2 b - 3 c$

$a = 15 - b - c$

$135 = 135 - 6 b - 8 c$

$45 = 60 - 2 b - 3 c$

$a = 15 - b - c$

$135 = 135 - 6 b - 8 c$

$45 = 60 - 2 b - 3 c$

$a = 15 - b - c$

$135 = 135 - 6 b - 8 c$

$45 = 60 - 2 b - 3 c$

$a = 15 - b - c$

$135 = 135 - 6 b - 8 c$

$45 = 60 - 2 b - 3 c$

$a = 15 - b - c$

Solve for $b$ in $135 = 135 - 6 b - 8 c$ .

Rewrite the equation as $135 - 6 b - 8 c = 135$ .

$135 - 6 b - 8 c = 135$

$45 = 60 - 2 b - 3 c$

$a = 15 - b - c$

Move all terms not containing $b$ to the right side of the equation.

Subtract $135$ from both sides of the equation.

$- 6 b - 8 c = 135 - 135$

$45 = 60 - 2 b - 3 c$

$a = 15 - b - c$

Add $8 c$ to both sides of the equation.

$- 6 b = 135 - 135 + 8 c$

$45 = 60 - 2 b - 3 c$

$a = 15 - b - c$

Subtract $135$ from $135$ .

$- 6 b = 0 + 8 c$

$45 = 60 - 2 b - 3 c$

$a = 15 - b - c$

Add $0$ and $8 c$ .

$- 6 b = 8 c$

$45 = 60 - 2 b - 3 c$

$a = 15 - b - c$

$- 6 b = 8 c$

$45 = 60 - 2 b - 3 c$

$a = 15 - b - c$

Divide each term in $- 6 b = 8 c$ by $- 6$ and simplify.

Divide each term in $- 6 b = 8 c$ by $- 6$ .

$\frac{- 6 b}{- 6} = \frac{8 c}{- 6}$

$45 = 60 - 2 b - 3 c$

$a = 15 - b - c$

Simplify the left side.

Cancel the common factor of $- 6$ .

Cancel the common factor.

$\frac{- 6 b}{- 6} = \frac{8 c}{- 6}$

$45 = 60 - 2 b - 3 c$

$a = 15 - b - c$

Divide $b$ by $1$ .

$b = \frac{8 c}{- 6}$

$45 = 60 - 2 b - 3 c$

$a = 15 - b - c$

$b = \frac{8 c}{- 6}$

$45 = 60 - 2 b - 3 c$

$a = 15 - b - c$

$b = \frac{8 c}{- 6}$

$45 = 60 - 2 b - 3 c$

$a = 15 - b - c$

Simplify the right side.

Cancel the common factor of $8$ and $- 6$ .

Factor $2$ out of $8 c$ .

$b = \frac{2 (4 c)}{- 6}$

$45 = 60 - 2 b - 3 c$

$a = 15 - b - c$

Cancel the common factors.

Factor $2$ out of $- 6$ .

$b = \frac{2 (4 c)}{2 (- 3)}$

$45 = 60 - 2 b - 3 c$

$a = 15 - b - c$

Cancel the common factor.

$b = \frac{2 (4 c)}{2 \cdot - 3}$

$45 = 60 - 2 b - 3 c$

$a = 15 - b - c$

Rewrite the expression.

$b = \frac{4 c}{- 3}$

$45 = 60 - 2 b - 3 c$

$a = 15 - b - c$

$b = \frac{4 c}{- 3}$

$45 = 60 - 2 b - 3 c$

$a = 15 - b - c$

$b = \frac{4 c}{- 3}$

$45 = 60 - 2 b - 3 c$

$a = 15 - b - c$

Move the negative in front of the fraction.

$b = - \frac{4 c}{3}$

$45 = 60 - 2 b - 3 c$

$a = 15 - b - c$

$b = - \frac{4 c}{3}$

$45 = 60 - 2 b - 3 c$

$a = 15 - b - c$

$b = - \frac{4 c}{3}$

$45 = 60 - 2 b - 3 c$

$a = 15 - b - c$

$b = - \frac{4 c}{3}$

$45 = 60 - 2 b - 3 c$

$a = 15 - b - c$

Replace all occurrences of $b$ with $- \frac{4 c}{3}$ in each equation.

Replace all occurrences of $b$ in $45 = 60 - 2 b - 3 c$ with $- \frac{4 c}{3}$ .

$45 = 60 - 2 (- \frac{4 c}{3}) - 3 c$

$b = - \frac{4 c}{3}$

$a = 15 - b - c$

Simplify the right side.

Simplify $60 - 2 (- \frac{4 c}{3}) - 3 c$ .

Multiply $- 2 (- \frac{4 c}{3})$ .

Multiply $- 1$ by $- 2$ .

$45 = 60 + 2 (\frac{4 c}{3}) - 3 c$

$b = - \frac{4 c}{3}$

$a = 15 - b - c$

Combine $2$ and $\frac{4 c}{3}$ .

$45 = 60 + \frac{2 (4 c)}{3} - 3 c$

$b = - \frac{4 c}{3}$

$a = 15 - b - c$

Multiply $4$ by $2$ .

$45 = 60 + \frac{8 c}{3} - 3 c$

$b = - \frac{4 c}{3}$

$a = 15 - b - c$

$45 = 60 + \frac{8 c}{3} - 3 c$

$b = - \frac{4 c}{3}$

$a = 15 - b - c$

To write $- 3 c$ as a fraction with a common denominator, multiply by $\frac{3}{3}$ .

$45 = 60 + \frac{8 c}{3} - 3 c \cdot \frac{3}{3}$

$b = - \frac{4 c}{3}$

$a = 15 - b - c$

Simplify terms.

Combine $- 3 c$ and $\frac{3}{3}$ .

$45 = 60 + \frac{8 c}{3} + \frac{- 3 c \cdot 3}{3}$

$b = - \frac{4 c}{3}$

$a = 15 - b - c$

Combine the numerators over the common denominator.

$45 = 60 + \frac{8 c - 3 c \cdot 3}{3}$

$b = - \frac{4 c}{3}$

$a = 15 - b - c$

$45 = 60 + \frac{8 c - 3 c \cdot 3}{3}$

$b = - \frac{4 c}{3}$

$a = 15 - b - c$

Simplify each term.

Simplify the numerator.

Factor $c$ out of $8 c - 3 c \cdot 3$ .

Factor $c$ out of $8 c$ .

$45 = 60 + \frac{c \cdot 8 - 3 c \cdot 3}{3}$

$b = - \frac{4 c}{3}$

$a = 15 - b - c$

Factor $c$ out of $- 3 c \cdot 3$ .

$45 = 60 + \frac{c \cdot 8 + c (- 3 \cdot 3)}{3}$

$b = - \frac{4 c}{3}$

$a = 15 - b - c$

Factor $c$ out of $c \cdot 8 + c (- 3 \cdot 3)$ .

$45 = 60 + \frac{c (8 - 3 \cdot 3)}{3}$

$b = - \frac{4 c}{3}$

$a = 15 - b - c$

$45 = 60 + \frac{c (8 - 3 \cdot 3)}{3}$

$b = - \frac{4 c}{3}$

$a = 15 - b - c$

Multiply $- 3$ by $3$ .

$45 = 60 + \frac{c (8 - 9)}{3}$

$b = - \frac{4 c}{3}$

$a = 15 - b - c$

Subtract $9$ from $8$ .

$45 = 60 + \frac{c \cdot - 1}{3}$

$b = - \frac{4 c}{3}$

$a = 15 - b - c$

$45 = 60 + \frac{c \cdot - 1}{3}$

$b = - \frac{4 c}{3}$

$a = 15 - b - c$

Move $- 1$ to the left of $c$ .

$45 = 60 + \frac{- 1 \cdot c}{3}$

$b = - \frac{4 c}{3}$

$a = 15 - b - c$

Move the negative in front of the fraction.

$45 = 60 - \frac{c}{3}$

$b = - \frac{4 c}{3}$

$a = 15 - b - c$

$45 = 60 - \frac{c}{3}$

$b = - \frac{4 c}{3}$

$a = 15 - b - c$

$45 = 60 - \frac{c}{3}$

$b = - \frac{4 c}{3}$

$a = 15 - b - c$

$45 = 60 - \frac{c}{3}$

$b = - \frac{4 c}{3}$

$a = 15 - b - c$

Replace all occurrences of $b$ in $a = 15 - b - c$ with $- \frac{4 c}{3}$ .

$a = 15 - (- \frac{4 c}{3}) - c$

$45 = 60 - \frac{c}{3}$

$b = - \frac{4 c}{3}$

Simplify the right side.

Simplify $15 - (- \frac{4 c}{3}) - c$ .

Multiply $- (- \frac{4 c}{3})$ .

Multiply $- 1$ by $- 1$ .

$a = 15 + 1 (\frac{4 c}{3}) - c$

$45 = 60 - \frac{c}{3}$

$b = - \frac{4 c}{3}$

Multiply $\frac{4 c}{3}$ by $1$ .

$a = 15 + \frac{4 c}{3} - c$

$45 = 60 - \frac{c}{3}$

$b = - \frac{4 c}{3}$

$a = 15 + \frac{4 c}{3} - c$

$45 = 60 - \frac{c}{3}$

$b = - \frac{4 c}{3}$

To write $- c$ as a fraction with a common denominator, multiply by $\frac{3}{3}$ .

$a = 15 + \frac{4 c}{3} - c \cdot \frac{3}{3}$

$45 = 60 - \frac{c}{3}$

$b = - \frac{4 c}{3}$

Simplify terms.

Combine $- c$ and $\frac{3}{3}$ .

$a = 15 + \frac{4 c}{3} + \frac{- c \cdot 3}{3}$

$45 = 60 - \frac{c}{3}$

$b = - \frac{4 c}{3}$

Combine the numerators over the common denominator.

$a = 15 + \frac{4 c - c \cdot 3}{3}$

$45 = 60 - \frac{c}{3}$

$b = - \frac{4 c}{3}$

$a = 15 + \frac{4 c - c \cdot 3}{3}$

$45 = 60 - \frac{c}{3}$

$b = - \frac{4 c}{3}$

Simplify each term.

Simplify the numerator.

Factor $c$ out of $4 c - c \cdot 3$ .

Factor $c$ out of $4 c$ .

$a = 15 + \frac{c \cdot 4 - c \cdot 3}{3}$

$45 = 60 - \frac{c}{3}$

$b = - \frac{4 c}{3}$

Factor $c$ out of $- c \cdot 3$ .

$a = 15 + \frac{c \cdot 4 + c (- 1 \cdot 3)}{3}$

$45 = 60 - \frac{c}{3}$

$b = - \frac{4 c}{3}$

Factor $c$ out of $c \cdot 4 + c (- 1 \cdot 3)$ .

$a = 15 + \frac{c (4 - 1 \cdot 3)}{3}$

$45 = 60 - \frac{c}{3}$

$b = - \frac{4 c}{3}$

$a = 15 + \frac{c (4 - 1 \cdot 3)}{3}$

$45 = 60 - \frac{c}{3}$

$b = - \frac{4 c}{3}$

Multiply $- 1$ by $3$ .

$a = 15 + \frac{c (4 - 3)}{3}$

$45 = 60 - \frac{c}{3}$

$b = - \frac{4 c}{3}$

Subtract $3$ from $4$ .

$a = 15 + \frac{c \cdot 1}{3}$

$45 = 60 - \frac{c}{3}$

$b = - \frac{4 c}{3}$

$a = 15 + \frac{c \cdot 1}{3}$

$45 = 60 - \frac{c}{3}$

$b = - \frac{4 c}{3}$

Multiply $c$ by $1$ .

$a = 15 + \frac{c}{3}$

$45 = 60 - \frac{c}{3}$

$b = - \frac{4 c}{3}$

$a = 15 + \frac{c}{3}$

$45 = 60 - \frac{c}{3}$

$b = - \frac{4 c}{3}$

$a = 15 + \frac{c}{3}$

$45 = 60 - \frac{c}{3}$

$b = - \frac{4 c}{3}$

$a = 15 + \frac{c}{3}$

$45 = 60 - \frac{c}{3}$

$b = - \frac{4 c}{3}$

$a = 15 + \frac{c}{3}$

$45 = 60 - \frac{c}{3}$

$b = - \frac{4 c}{3}$

Solve for $c$ in $45 = 60 - \frac{c}{3}$ .

Rewrite the equation as $60 - \frac{c}{3} = 45$ .

$60 - \frac{c}{3} = 45$

$a = 15 + \frac{c}{3}$

$b = - \frac{4 c}{3}$

Move all terms not containing $c$ to the right side of the equation.

Subtract $60$ from both sides of the equation.

$- \frac{c}{3} = 45 - 60$

$a = 15 + \frac{c}{3}$

$b = - \frac{4 c}{3}$

Subtract $60$ from $45$ .

$- \frac{c}{3} = - 15$

$a = 15 + \frac{c}{3}$

$b = - \frac{4 c}{3}$

$- \frac{c}{3} = - 15$

$a = 15 + \frac{c}{3}$

$b = - \frac{4 c}{3}$

Multiply both sides of the equation by $- 3$ .

$- 3 (- \frac{c}{3}) = - 3 \cdot - 15$

$a = 15 + \frac{c}{3}$

$b = - \frac{4 c}{3}$

Simplify both sides of the equation.

Simplify the left side.

Simplify $- 3 (- \frac{c}{3})$ .

Cancel the common factor of $3$ .

Move the leading negative in $- \frac{c}{3}$ into the numerator.

$- 3 \frac{- c}{3} = - 3 \cdot - 15$

$a = 15 + \frac{c}{3}$

$b = - \frac{4 c}{3}$

Factor $3$ out of $- 3$ .

$3 (- 1) (\frac{- c}{3}) = - 3 \cdot - 15$

$a = 15 + \frac{c}{3}$

$b = - \frac{4 c}{3}$

Cancel the common factor.

$3 \cdot (- 1 \frac{- c}{3}) = - 3 \cdot - 15$

$a = 15 + \frac{c}{3}$

$b = - \frac{4 c}{3}$

Rewrite the expression.

$c = - 3 \cdot - 15$

$a = 15 + \frac{c}{3}$

$b = - \frac{4 c}{3}$

$c = - 3 \cdot - 15$

$a = 15 + \frac{c}{3}$

$b = - \frac{4 c}{3}$

Multiply.

Multiply $- 1$ by $- 1$ .

$1 c = - 3 \cdot - 15$

$a = 15 + \frac{c}{3}$

$b = - \frac{4 c}{3}$

Multiply $c$ by $1$ .

$c = - 3 \cdot - 15$

$a = 15 + \frac{c}{3}$

$b = - \frac{4 c}{3}$

$c = - 3 \cdot - 15$

$a = 15 + \frac{c}{3}$

$b = - \frac{4 c}{3}$

$c = - 3 \cdot - 15$

$a = 15 + \frac{c}{3}$

$b = - \frac{4 c}{3}$

$c = - 3 \cdot - 15$

$a = 15 + \frac{c}{3}$

$b = - \frac{4 c}{3}$

Simplify the right side.

Multiply $- 3$ by $- 15$ .

$c = 45$

$a = 15 + \frac{c}{3}$

$b = - \frac{4 c}{3}$

$c = 45$

$a = 15 + \frac{c}{3}$

$b = - \frac{4 c}{3}$

$c = 45$

$a = 15 + \frac{c}{3}$

$b = - \frac{4 c}{3}$

$c = 45$

$a = 15 + \frac{c}{3}$

$b = - \frac{4 c}{3}$

Replace all occurrences of $c$ with $45$ in each equation.

Replace all occurrences of $c$ in $a = 15 + \frac{c}{3}$ with $45$ .

$a = 15 + \frac{45}{3}$

$c = 45$

$b = - \frac{4 c}{3}$

Simplify the right side.

Simplify $15 + \frac{45}{3}$ .

Divide $45$ by $3$ .

$a = 15 + 15$

$c = 45$

$b = - \frac{4 c}{3}$

Add $15$ and $15$ .

$a = 30$

$c = 45$

$b = - \frac{4 c}{3}$

$a = 30$

$c = 45$

$b = - \frac{4 c}{3}$

$a = 30$

$c = 45$

$b = - \frac{4 c}{3}$

Replace all occurrences of $c$ in $b = - \frac{4 c}{3}$ with $45$ .

$b = - \frac{4 (45)}{3}$

$a = 30$

$c = 45$

Simplify the right side.

Simplify $- \frac{4 (45)}{3}$ .

Cancel the common factor of $45$ and $3$ .

Factor $3$ out of $4 (45)$ .

$b = - \frac{3 (4 \cdot (15))}{3}$

$a = 30$

$c = 45$

Cancel the common factors.

Factor $3$ out of $3$ .

$b = - \frac{3 (4 \cdot (15))}{3 (1)}$

$a = 30$

$c = 45$

Cancel the common factor.

$b = - \frac{3 (4 \cdot (15))}{3 \cdot 1}$

$a = 30$

$c = 45$

Rewrite the expression.

$b = - \frac{4 \cdot (15)}{1}$

$a = 30$

$c = 45$

Divide $4 \cdot (15)$ by $1$ .

$b = - (4 \cdot (15))$

$a = 30$

$c = 45$

$b = - (4 \cdot (15))$

$a = 30$

$c = 45$

$b = - (4 \cdot (15))$

$a = 30$

$c = 45$

Multiply $- (4 \cdot (15))$ .

Multiply $4$ by $15$ .

$b = - 1 \cdot 60$

$a = 30$

$c = 45$

Multiply $- 1$ by $60$ .

$b = - 60$

$a = 30$

$c = 45$

$b = - 60$

$a = 30$

$c = 45$

$b = - 60$

$a = 30$

$c = 45$

$b = - 60$

$a = 30$

$c = 45$

$b = - 60$

$a = 30$

$c = 45$

List all of the solutions.

$b = - 60, a = 30, c = 45$

Calculate the value of $y$ using each $x$ value in the table and compare this value to the given $y$ value in the table.

Calculate the value of $y$ such that $y = a x^{2} + b$ when $a = 30$ , $b = - 60$ , $c = 45$ , and $x = 1$ .

Simplify each term.

One to any power is one.

$y = 30 \cdot 1 + (- 60) \cdot (1) + 45$

Multiply $30$ by $1$ .

$y = 30 + (- 60) \cdot (1) + 45$

Multiply $- 60$ by $1$ .

$y = 30 - 60 + 45$

Simplify by adding and subtracting.

Subtract $60$ from $30$ .

$y = - 30 + 45$

Add $- 30$ and $45$ .

$y = 15$

If the table has a quadratic function rule, $y = y$ for the corresponding $x$ value, $x = 1$ . This check passes since $y = 15$ and $y = 15$ .

$15 = 15$

Calculate the value of $y$ such that $y = a x^{2} + b$ when $a = 30$ , $b = - 60$ , $c = 45$ , and $x = 2$ .

Simplify each term.

Raise $2$ to the power of $2$ .

$y = 30 \cdot 4 + (- 60) \cdot (2) + 45$

Multiply $30$ by $4$ .

$y = 120 + (- 60) \cdot (2) + 45$

Multiply $- 60$ by $2$ .

$y = 120 - 120 + 45$

Simplify by adding and subtracting.

Subtract $120$ from $120$ .

$y = 0 + 45$

Add $0$ and $45$ .

$y = 45$

If the table has a quadratic function rule, $y = y$ for the corresponding $x$ value, $x = 2$ . This check passes since $y = 45$ and $y = 45$ .

$45 = 45$

Calculate the value of $y$ such that $y = a x^{2} + b$ when $a = 30$ , $b = - 60$ , $c = 45$ , and $x = 3$ .

Simplify each term.

Raise $3$ to the power of $2$ .

$y = 30 \cdot 9 + (- 60) \cdot (3) + 45$

Multiply $30$ by $9$ .

$y = 270 + (- 60) \cdot (3) + 45$

Multiply $- 60$ by $3$ .

$y = 270 - 180 + 45$

Simplify by adding and subtracting.

Subtract $180$ from $270$ .

$y = 90 + 45$

Add $90$ and $45$ .

$y = 135$

If the table has a quadratic function rule, $y = y$ for the corresponding $x$ value, $x = 3$ . This check passes since $y = 135$ and $y = 135$ .

$135 = 135$

Since $y = y$ for the corresponding $x$ values, the function is quadratic.

The function is quadratic

Step 3

Since all $y = y$ , the function is quadratic and follows the form $y = 30 x^{2} - 60 x + 45$ .

$y = 30 x^{2} - 60 x + 45$

Find the Function Rule table[[x,y],[1,15],[2,45],[3,135]]

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