Find the Holes in the Graph (3x+12)/(-4x-2)

$\frac{3 x + 12}{- 4 x - 2}$

Step 1

Factor $3$ out of $3 x + 12$ .

Factor $3$ out of $3 x$ .

$\frac{3 (x) + 12}{- 4 x - 2}$

Factor $3$ out of $12$ .

$\frac{3 x + 3 \cdot 4}{- 4 x - 2}$

Factor $3$ out of $3 x + 3 \cdot 4$ .

$\frac{3 (x + 4)}{- 4 x - 2}$

Step 2

Factor $2$ out of $- 4 x - 2$ .

Factor $2$ out of $- 4 x$ .

$\frac{3 (x + 4)}{2 (- 2 x) - 2}$

Factor $2$ out of $- 2$ .

$\frac{3 (x + 4)}{2 (- 2 x) + 2 (- 1)}$

Factor $2$ out of $2 (- 2 x) + 2 (- 1)$ .

$\frac{3 (x + 4)}{2 (- 2 x - 1)}$

Step 3

Since no factors can be removed from the denominator, there are no holes in the graph.

No holes

Step 4