Find the Holes in the Graph f(x)=(2x-7)/(-3x-9)

$f (x) = \frac{2 x - 7}{- 3 x - 9}$

Step 1

Factor $3$ out of $- 3 x - 9$ .

Factor $3$ out of $- 3 x$ .

$f (x) = \frac{2 x - 7}{3 (- x) - 9}$

Factor $3$ out of $- 9$ .

$f (x) = \frac{2 x - 7}{3 (- x) + 3 (- 3)}$

Factor $3$ out of $3 (- x) + 3 (- 3)$ .

$f (x) = \frac{2 x - 7}{3 (- x - 3)}$

Step 2

Since no factors can be removed from the denominator, there are no holes in the graph.

No holes

Step 3