Find the Holes in the Graph f(x)=(3x^2+6x)/(2x^2)

$f (x) = \frac{3 x^{2} + 6 x}{2 x^{2}}$

Factor $3 x$ out of $3 x^{2} + 6 x$ .

Factor $3 x$ out of $3 x^{2}$ .

$f (x) = \frac{3 x (x) + 6 x}{2 x^{2}}$

Factor $3 x$ out of $6 x$ .

$f (x) = \frac{3 x (x) + 3 x (2)}{2 x^{2}}$

Factor $3 x$ out of $3 x (x) + 3 x (2)$ .

$f (x) = \frac{3 x (x + 2)}{2 x^{2}}$

Cancel the common factor of $x$ and $x^{2}$ .

Factor $x$ out of $3 x (x + 2)$ .

$f (x) = \frac{x (3 (x + 2))}{2 x^{2}}$

Cancel the common factors.

Factor $x$ out of $2 x^{2}$ .

$f (x) = \frac{x (3 (x + 2))}{x (2 x)}$

Cancel the common factor.

$f (x) = \frac{x (3 (x + 2))}{x (2 x)}$

Rewrite the expression.

$f (x) = \frac{3 (x + 2)}{2 x}$

Since no factors can be removed from the denominator, there are no holes in the graph.

No holes