Find the Holes in the Graph f(x)=(-4x-4)/(3x-2)

$f (x) = \frac{- 4 x - 4}{3 x - 2}$

Factor $4$ out of $- 4 x - 4$ .

Factor $4$ out of $- 4 x$ .

$f (x) = \frac{4 (- x) - 4}{3 x - 2}$

Factor $4$ out of $- 4$ .

$f (x) = \frac{4 (- x) + 4 (- 1)}{3 x - 2}$

Factor $4$ out of $4 (- x) + 4 (- 1)$ .

$f (x) = \frac{4 (- x - 1)}{3 x - 2}$

Since no factors can be removed from the denominator, there are no holes in the graph.

No holes