Find the Holes in the Graph f(x)=(x^2+2x-3)/x

$f (x) = \frac{x^{2} + 2 x - 3}{x}$

Step 1

Factor $x^{2} + 2 x - 3$ using the AC method.

Consider the form $x^{2} + b x + c$ . Find a pair of integers whose product is $c$ and whose sum is $b$ . In this case, whose product is $- 3$ and whose sum is $2$ .

$- 1, 3$

Write the factored form using these integers.

$f (x) = \frac{(x - 1) (x + 3)}{x}$

Step 2

Since no factors can be removed from the denominator, there are no holes in the graph.

No holes

Step 3

Find the Holes in the Graph f(x)=(x^2+2x-3)/x

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