Find the Holes in the Graph f(x)=(x^2+2x)/(-4x+8)

$f (x) = \frac{x^{2} + 2 x}{- 4 x + 8}$

Factor $x$ out of $x^{2} + 2 x$ .

Factor $x$ out of $x^{2}$ .

$f (x) = \frac{x \cdot x + 2 x}{- 4 x + 8}$

Factor $x$ out of $2 x$ .

$f (x) = \frac{x \cdot x + x \cdot 2}{- 4 x + 8}$

Factor $x$ out of $x \cdot x + x \cdot 2$ .

$f (x) = \frac{x (x + 2)}{- 4 x + 8}$

Factor $4$ out of $- 4 x + 8$ .

Factor $4$ out of $- 4 x$ .

$f (x) = \frac{x (x + 2)}{4 (- x) + 8}$

Factor $4$ out of $8$ .

$f (x) = \frac{x (x + 2)}{4 (- x) + 4 (2)}$

Factor $4$ out of $4 (- x) + 4 (2)$ .

$f (x) = \frac{x (x + 2)}{4 (- x + 2)}$

Since no factors can be removed from the denominator, there are no holes in the graph.

No holes