Find the Holes in the Graph f(x)=(x^2-3x-4)/(-3x)

$f (x) = \frac{x^{2} - 3 x - 4}{- 3 x}$

Factor $x^{2} - 3 x - 4$ using the AC method.

Consider the form $x^{2} + b x + c$ . Find a pair of integers whose product is $c$ and whose sum is $b$ . In this case, whose product is $- 4$ and whose sum is $- 3$ .

$- 4, 1$

Write the factored form using these integers.

$f (x) = \frac{(x - 4) (x + 1)}{- 3 x}$

Move the negative in front of the fraction.

$f (x) = - \frac{(x - 4) (x + 1)}{(3) x}$

Multiply $3$ by $x$ .

$f (x) = - \frac{(x - 4) (x + 1)}{3 x}$

Since no factors can be removed from the denominator, there are no holes in the graph.

No holes

Find the Holes in the Graph f(x)=(x^2-3x-4)/(-3x)

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