Find the Holes in the Graph f(x)=(x+5)/(3x-12)

$f (x) = \frac{x + 5}{3 x - 12}$

Step 1

Factor $3$ out of $3 x - 12$ .

Factor $3$ out of $3 x$ .

$f (x) = \frac{x + 5}{3 (x) - 12}$

Factor $3$ out of $- 12$ .

$f (x) = \frac{x + 5}{3 x + 3 \cdot - 4}$

Factor $3$ out of $3 x + 3 \cdot - 4$ .

$f (x) = \frac{x + 5}{3 (x - 4)}$

Step 2

Since no factors can be removed from the denominator, there are no holes in the graph.

No holes

Step 3