Find the Holes in the Graph f(x)=(x-8)/(3x-6)

$f (x) = \frac{x - 8}{3 x - 6}$

Step 1

Factor $3$ out of $3 x - 6$ .

Factor $3$ out of $3 x$ .

$f (x) = \frac{x - 8}{3 (x) - 6}$

Factor $3$ out of $- 6$ .

$f (x) = \frac{x - 8}{3 x + 3 \cdot - 2}$

Factor $3$ out of $3 x + 3 \cdot - 2$ .

$f (x) = \frac{x - 8}{3 (x - 2)}$

Step 2

Since no factors can be removed from the denominator, there are no holes in the graph.

No holes

Step 3