Find the Holes in the Graph f(x)=x/(x^2-4)

$f (x) = \frac{x}{x^{2} - 4}$

Factor $x^{2} - 4$ .

Rewrite $4$ as $2^{2}$ .

$f (x) = \frac{x}{x^{2} - 2^{2}}$

Since both terms are perfect squares, factor using the difference of squares formula, $a^{2} - b^{2} = (a + b) (a - b)$ where $a = x$ and $b = 2$ .

$f (x) = \frac{x}{(x + 2) (x - 2)}$

Since no factors can be removed from the denominator, there are no holes in the graph.

No holes