Find the Holes in the Graph ((x+1)(x-6))/((x-6)(x+3))

$\frac{(x + 1) (x - 6)}{(x - 6) (x + 3)}$

Cancel the common factor of $x - 6$ .

Cancel the common factor.

$\frac{(x + 1) (x - 6)}{(x - 6) (x + 3)}$

Rewrite the expression.

$\frac{x + 1}{x + 3}$

To find the holes in the graph, look at the denominator factors that were cancelled.

$x - 6$

To find the coordinates of the holes, set each factor that was cancelled equal to $0$ , solve, and substitute back in to $\frac{x + 1}{x + 3}$ .

Set $x - 6$ equal to $0$ .

$x - 6 = 0$

Add $6$ to both sides of the equation.

$x = 6$

Substitute $6$ for $x$ in $\frac{x + 1}{x + 3}$ and simplify.

Substitute $6$ for $x$ to find the $y$ coordinate of the hole.

$\frac{6 + 1}{6 + 3}$

Simplify.

Add $6$ and $1$ .

$\frac{7}{6 + 3}$

Add $6$ and $3$ .

$\frac{7}{9}$

The holes in the graph are the points where any of the cancelled factors are equal to $0$ .

$(6, \frac{7}{9})$