Find the Holes in the Graph y=(x-1)/(x^2+6x+8)

$y = \frac{x - 1}{x^{2} + 6 x + 8}$

Step 1

Factor $x^{2} + 6 x + 8$ using the AC method.

Consider the form $x^{2} + b x + c$ . Find a pair of integers whose product is $c$ and whose sum is $b$ . In this case, whose product is $8$ and whose sum is $6$ .

$2, 4$

Write the factored form using these integers.

$y = \frac{x - 1}{(x + 2) (x + 4)}$

Step 2

Since no factors can be removed from the denominator, there are no holes in the graph.

No holes

Step 3

Find the Holes in the Graph y=(x-1)/(x^2+6x+8)

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