Find the Integral x square root of 1-x

$x \sqrt{1 - x}$

Step 1

Integrate by parts using the formula $\int u d v = u v - \int v d u$ , where $u = x$ and $d v = \sqrt{1 - x}$ .

$x (- \frac{2}{3} {(1 - x)}^{\frac{3}{2}}) - \int - \frac{2}{3} {(1 - x)}^{\frac{3}{2}} d x$

Step 2

Simplify.

Combine ${(1 - x)}^{\frac{3}{2}}$ and $\frac{2}{3}$ .

$x (- \frac{{(1 - x)}^{\frac{3}{2}} \cdot 2}{3}) - \int - \frac{2}{3} {(1 - x)}^{\frac{3}{2}} d x$

Combine $x$ and $\frac{{(1 - x)}^{\frac{3}{2}} \cdot 2}{3}$ .

$- \frac{x ({(1 - x)}^{\frac{3}{2}} \cdot 2)}{3} - \int - \frac{2}{3} {(1 - x)}^{\frac{3}{2}} d x$

Move $2$ to the left of ${(1 - x)}^{\frac{3}{2}}$ .

$- \frac{x (2 {(1 - x)}^{\frac{3}{2}})}{3} - \int - \frac{2}{3} {(1 - x)}^{\frac{3}{2}} d x$

Step 3

Since $- \frac{2}{3}$ is constant with respect to $x$ , move $- \frac{2}{3}$ out of the integral.

$- \frac{x (2 {(1 - x)}^{\frac{3}{2}})}{3} - (- \frac{2}{3} \int {(1 - x)}^{\frac{3}{2}} d x)$

Step 4

Simplify.

Multiply $- 1$ by $- 1$ .

$- \frac{x (2 {(1 - x)}^{\frac{3}{2}})}{3} + 1 (\frac{2}{3} \int {(1 - x)}^{\frac{3}{2}} d x)$

Multiply $\frac{2}{3}$ by $1$ .

$- \frac{x (2 {(1 - x)}^{\frac{3}{2}})}{3} + \frac{2}{3} \int {(1 - x)}^{\frac{3}{2}} d x$

Step 5

Let $u = 1 - x$ . Then $d u = - d x$ , so $- d u = d x$ . Rewrite using $u$ and $d$ $u$ .

Let $u = 1 - x$ . Find $\frac{d u}{d x}$ .

Differentiate $1 - x$ .

$\frac{d}{d x} [1 - x]$

Differentiate.

By the Sum Rule, the derivative of $1 - x$ with respect to $x$ is $\frac{d}{d x} [1] + \frac{d}{d x} [- x]$ .

$\frac{d}{d x} [1] + \frac{d}{d x} [- x]$

Since $1$ is constant with respect to $x$ , the derivative of $1$ with respect to $x$ is $0$ .

$0 + \frac{d}{d x} [- x]$

Evaluate $\frac{d}{d x} [- x]$ .

Since $- 1$ is constant with respect to $x$ , the derivative of $- x$ with respect to $x$ is $- \frac{d}{d x} [x]$ .

$0 - \frac{d}{d x} [x]$

Differentiate using the Power Rule which states that $\frac{d}{d x} [x^{n}]$ is $n x^{n - 1}$ where $n = 1$ .

$0 - 1 \cdot 1$

Multiply $- 1$ by $1$ .

$0 - 1$

Subtract $1$ from $0$ .

$- 1$

Rewrite the problem using $u$ and $d u$ .

$- \frac{x (2 {(1 - x)}^{\frac{3}{2}})}{3} + \frac{2}{3} \int - u^{\frac{3}{2}} d u$

Step 6

Since $- 1$ is constant with respect to $u$ , move $- 1$ out of the integral.

$- \frac{x (2 {(1 - x)}^{\frac{3}{2}})}{3} + \frac{2}{3} (- \int u^{\frac{3}{2}} d u)$

Step 7

By the Power Rule, the integral of $u^{\frac{3}{2}}$ with respect to $u$ is $\frac{2}{5} u^{\frac{5}{2}}$ .

$- \frac{x (2 {(1 - x)}^{\frac{3}{2}})}{3} + \frac{2}{3} (- (\frac{2}{5} u^{\frac{5}{2}} + C))$

Step 8

Simplify.

Combine $\frac{2}{5}$ and $u^{\frac{5}{2}}$ .

$- \frac{x (2 {(1 - x)}^{\frac{3}{2}})}{3} + \frac{2}{3} (- (\frac{2 u^{\frac{5}{2}}}{5} + C))$

Rewrite $- \frac{x (2 {(1 - x)}^{\frac{3}{2}})}{3} + \frac{2}{3} (- (\frac{2 u^{\frac{5}{2}}}{5} + C))$ as $- \frac{2}{3} x {(1 - x)}^{\frac{3}{2}} + \frac{2}{3} (- \frac{2}{5} u^{\frac{5}{2}}) + C$ .

$- \frac{2}{3} x {(1 - x)}^{\frac{3}{2}} + \frac{2}{3} (- \frac{2}{5} u^{\frac{5}{2}}) + C$

Simplify.

Combine $x$ and $\frac{2}{3}$ .

$- \frac{x \cdot 2}{3} {(1 - x)}^{\frac{3}{2}} + \frac{2}{3} (- \frac{2}{5} u^{\frac{5}{2}}) + C$

Combine ${(1 - x)}^{\frac{3}{2}}$ and $\frac{x \cdot 2}{3}$ .

$- \frac{{(1 - x)}^{\frac{3}{2}} (x \cdot 2)}{3} + \frac{2}{3} (- \frac{2}{5} u^{\frac{5}{2}}) + C$

Move $2$ to the left of $x$ .

$- \frac{{(1 - x)}^{\frac{3}{2}} (2 \cdot x)}{3} + \frac{2}{3} (- \frac{2}{5} u^{\frac{5}{2}}) + C$

Move $2$ to the left of ${(1 - x)}^{\frac{3}{2}}$ .

$- \frac{2 \cdot {(1 - x)}^{\frac{3}{2}} x}{3} + \frac{2}{3} (- \frac{2}{5} u^{\frac{5}{2}}) + C$

Combine $u^{\frac{5}{2}}$ and $\frac{2}{5}$ .

$- \frac{2 {(1 - x)}^{\frac{3}{2}} x}{3} + \frac{2}{3} (- \frac{u^{\frac{5}{2}} \cdot 2}{5}) + C$

Multiply $\frac{2}{3}$ by $\frac{u^{\frac{5}{2}} \cdot 2}{5}$ .

$- \frac{2 {(1 - x)}^{\frac{3}{2}} x}{3} - \frac{2 (u^{\frac{5}{2}} \cdot 2)}{3 \cdot 5} + C$

Multiply $2$ by $2$ .

$- \frac{2 {(1 - x)}^{\frac{3}{2}} x}{3} - \frac{4 u^{\frac{5}{2}}}{3 \cdot 5} + C$

Multiply $3$ by $5$ .

$- \frac{2 {(1 - x)}^{\frac{3}{2}} x}{3} - \frac{4 u^{\frac{5}{2}}}{15} + C$

To write $- \frac{2 {(1 - x)}^{\frac{3}{2}} x}{3}$ as a fraction with a common denominator, multiply by $\frac{5}{5}$ .

$- \frac{2 {(1 - x)}^{\frac{3}{2}} x}{3} \cdot \frac{5}{5} - \frac{4 u^{\frac{5}{2}}}{15} + C$

Write each expression with a common denominator of $15$ , by multiplying each by an appropriate factor of $1$ .

Multiply $\frac{2 {(1 - x)}^{\frac{3}{2}} x}{3}$ by $\frac{5}{5}$ .

$- \frac{2 {(1 - x)}^{\frac{3}{2}} x \cdot 5}{3 \cdot 5} - \frac{4 u^{\frac{5}{2}}}{15} + C$

Multiply $3$ by $5$ .

$- \frac{2 {(1 - x)}^{\frac{3}{2}} x \cdot 5}{15} - \frac{4 u^{\frac{5}{2}}}{15} + C$

Combine the numerators over the common denominator.

$\frac{- 2 {(1 - x)}^{\frac{3}{2}} x \cdot 5 - 4 u^{\frac{5}{2}}}{15} + C$

Multiply $5$ by $- 2$ .

$\frac{- 10 {(1 - x)}^{\frac{3}{2}} x - 4 u^{\frac{5}{2}}}{15} + C$

Step 9

Replace all occurrences of $u$ with $1 - x$ .

$\frac{- 10 {(1 - x)}^{\frac{3}{2}} x - 4 {(1 - x)}^{\frac{5}{2}}}{15} + C$

Step 10

Reorder terms.

$\frac{1}{15} (- 10 {(1 - x)}^{\frac{3}{2}} x - 4 {(1 - x)}^{\frac{5}{2}}) + C$

Find the Integral x square root of 1-x

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