Find the Inverse (5x)/(8x-3)

$\frac{5 x}{8 x - 3}$

Step 1

Interchange the variables.

$x = \frac{5 y}{8 y - 3}$

Step 2

Solve for $y$ .

Multiply the equation by $8 y - 3$ .

$(8 y - 3) (x) = (\frac{5 y}{8 y - 3}) (8 y - 3)$

Simplify the left side.

Apply the distributive property.

$8 y x - 3 x = (\frac{5 y}{8 y - 3}) (8 y - 3)$

Simplify the right side.

Cancel the common factor of $8 y - 3$ .

Cancel the common factor.

$8 y x - 3 x = \frac{5 y}{8 y - 3} (8 y - 3)$

Rewrite the expression.

$8 y x - 3 x = 5 y$

Solve for $y$ .

Subtract $5 y$ from both sides of the equation.

$8 y x - 3 x - 5 y = 0$

Add $3 x$ to both sides of the equation.

$8 y x - 5 y = 3 x$

Factor $y$ out of $8 y x - 5 y$ .

Factor $y$ out of $8 y x$ .

$y (8 x) - 5 y = 3 x$

Factor $y$ out of $- 5 y$ .

$y (8 x) + y \cdot - 5 = 3 x$

Factor $y$ out of $y (8 x) + y \cdot - 5$ .

$y (8 x - 5) = 3 x$

Divide each term in $y (8 x - 5) = 3 x$ by $8 x - 5$ and simplify.

Divide each term in $y (8 x - 5) = 3 x$ by $8 x - 5$ .

$\frac{y (8 x - 5)}{8 x - 5} = \frac{3 x}{8 x - 5}$

Simplify the left side.

Cancel the common factor of $8 x - 5$ .

Cancel the common factor.

$\frac{y (8 x - 5)}{8 x - 5} = \frac{3 x}{8 x - 5}$

Divide $y$ by $1$ .

$y = \frac{3 x}{8 x - 5}$

Step 3

Replace $y$ with $f^{- 1} (x)$ to show the final answer.

$f^{- 1} (x) = \frac{3 x}{8 x - 5}$

Step 4

Verify if $f^{- 1} (x) = \frac{3 x}{8 x - 5}$ is the inverse of $f (x) = \frac{5 x}{8 x - 3}$ .

To verify the inverse, check if $f^{- 1} (f (x)) = x$ and $f (f^{- 1} (x)) = x$ .

Evaluate $f^{- 1} (f (x))$ .

Set up the composite result function.

$f^{- 1} (f (x))$

Evaluate $f^{- 1} (\frac{5 x}{8 x - 3})$ by substituting in the value of $f$ into $f^{- 1}$ .

$f^{- 1} (\frac{5 x}{8 x - 3}) = \frac{3 (\frac{5 x}{8 x - 3})}{8 (\frac{5 x}{8 x - 3}) - 5}$

Combine $3$ and $\frac{5 x}{8 x - 3}$ .

$f^{- 1} (\frac{5 x}{8 x - 3}) = \frac{\frac{3 (5 x)}{8 x - 3}}{8 (\frac{5 x}{8 x - 3}) - 5}$

Simplify the denominator.

Multiply $8 \frac{5 x}{8 x - 3}$ .

Combine $8$ and $\frac{5 x}{8 x - 3}$ .

$f^{- 1} (\frac{5 x}{8 x - 3}) = \frac{\frac{3 (5 x)}{8 x - 3}}{\frac{8 (5 x)}{8 x - 3} - 5}$

Multiply $5$ by $8$ .

$f^{- 1} (\frac{5 x}{8 x - 3}) = \frac{\frac{3 (5 x)}{8 x - 3}}{\frac{40 x}{8 x - 3} - 5}$

To write $- 5$ as a fraction with a common denominator, multiply by $\frac{8 x - 3}{8 x - 3}$ .

$f^{- 1} (\frac{5 x}{8 x - 3}) = \frac{\frac{3 (5 x)}{8 x - 3}}{\frac{40 x}{8 x - 3} - 5 \cdot \frac{8 x - 3}{8 x - 3}}$

Combine $- 5$ and $\frac{8 x - 3}{8 x - 3}$ .

$f^{- 1} (\frac{5 x}{8 x - 3}) = \frac{\frac{3 (5 x)}{8 x - 3}}{\frac{40 x}{8 x - 3} + \frac{- 5 (8 x - 3)}{8 x - 3}}$

Combine the numerators over the common denominator.

$f^{- 1} (\frac{5 x}{8 x - 3}) = \frac{\frac{3 (5 x)}{8 x - 3}}{\frac{40 x - 5 (8 x - 3)}{8 x - 3}}$

Rewrite $\frac{40 x - 5 (8 x - 3)}{8 x - 3}$ in a factored form.

Factor $5$ out of $40 x - 5 (8 x - 3)$ .

Factor $5$ out of $40 x$ .

$f^{- 1} (\frac{5 x}{8 x - 3}) = \frac{\frac{3 (5 x)}{8 x - 3}}{\frac{5 (8 x) - 5 (8 x - 3)}{8 x - 3}}$

Factor $5$ out of $- 5 (8 x - 3)$ .

$f^{- 1} (\frac{5 x}{8 x - 3}) = \frac{\frac{3 (5 x)}{8 x - 3}}{\frac{5 (8 x) + 5 (- (8 x - 3))}{8 x - 3}}$

Factor $5$ out of $5 (8 x) + 5 (- (8 x - 3))$ .

$f^{- 1} (\frac{5 x}{8 x - 3}) = \frac{\frac{3 (5 x)}{8 x - 3}}{\frac{5 (8 x - (8 x - 3))}{8 x - 3}}$

Apply the distributive property.

$f^{- 1} (\frac{5 x}{8 x - 3}) = \frac{\frac{3 (5 x)}{8 x - 3}}{\frac{5 (8 x - (8 x) + 3)}{8 x - 3}}$

Multiply $8$ by $- 1$ .

$f^{- 1} (\frac{5 x}{8 x - 3}) = \frac{\frac{3 (5 x)}{8 x - 3}}{\frac{5 (8 x - 8 x + 3)}{8 x - 3}}$

Multiply $- 1$ by $- 3$ .

$f^{- 1} (\frac{5 x}{8 x - 3}) = \frac{\frac{3 (5 x)}{8 x - 3}}{\frac{5 (8 x - 8 x + 3)}{8 x - 3}}$

Subtract $8 x$ from $8 x$ .

$f^{- 1} (\frac{5 x}{8 x - 3}) = \frac{\frac{3 (5 x)}{8 x - 3}}{\frac{5 (0 + 3)}{8 x - 3}}$

Add $0$ and $3$ .

$f^{- 1} (\frac{5 x}{8 x - 3}) = \frac{\frac{3 (5 x)}{8 x - 3}}{\frac{5 \cdot 3}{8 x - 3}}$

Multiply $5$ by $3$ .

$f^{- 1} (\frac{5 x}{8 x - 3}) = \frac{\frac{3 (5 x)}{8 x - 3}}{\frac{15}{8 x - 3}}$

Multiply $3$ by $5$ .

$f^{- 1} (\frac{5 x}{8 x - 3}) = \frac{\frac{15 x}{8 x - 3}}{\frac{15}{8 x - 3}}$

Multiply the numerator by the reciprocal of the denominator.

$f^{- 1} (\frac{5 x}{8 x - 3}) = \frac{15 x}{8 x - 3} \cdot \frac{8 x - 3}{15}$

Cancel the common factor of $15$ .

Factor $15$ out of $15 x$ .

$f^{- 1} (\frac{5 x}{8 x - 3}) = \frac{15 (x)}{8 x - 3} \cdot \frac{8 x - 3}{15}$

Cancel the common factor.

$f^{- 1} (\frac{5 x}{8 x - 3}) = \frac{15 x}{8 x - 3} \cdot \frac{8 x - 3}{15}$

Rewrite the expression.

$f^{- 1} (\frac{5 x}{8 x - 3}) = \frac{x}{8 x - 3} \cdot (8 x - 3)$

Cancel the common factor of $8 x - 3$ .

Cancel the common factor.

$f^{- 1} (\frac{5 x}{8 x - 3}) = \frac{x}{8 x - 3} \cdot (8 x - 3)$

Rewrite the expression.

$f^{- 1} (\frac{5 x}{8 x - 3}) = x$

Evaluate $f (f^{- 1} (x))$ .

Set up the composite result function.

$f (f^{- 1} (x))$

Evaluate $f (\frac{3 x}{8 x - 5})$ by substituting in the value of $f^{- 1}$ into $f$ .

$f (\frac{3 x}{8 x - 5}) = \frac{5 (\frac{3 x}{8 x - 5})}{8 (\frac{3 x}{8 x - 5}) - 3}$

Combine $5$ and $\frac{3 x}{8 x - 5}$ .

$f (\frac{3 x}{8 x - 5}) = \frac{\frac{5 (3 x)}{8 x - 5}}{8 (\frac{3 x}{8 x - 5}) - 3}$

Simplify the denominator.

Multiply $8 \frac{3 x}{8 x - 5}$ .

Combine $8$ and $\frac{3 x}{8 x - 5}$ .

$f (\frac{3 x}{8 x - 5}) = \frac{\frac{5 (3 x)}{8 x - 5}}{\frac{8 (3 x)}{8 x - 5} - 3}$

Multiply $3$ by $8$ .

$f (\frac{3 x}{8 x - 5}) = \frac{\frac{5 (3 x)}{8 x - 5}}{\frac{24 x}{8 x - 5} - 3}$

To write $- 3$ as a fraction with a common denominator, multiply by $\frac{8 x - 5}{8 x - 5}$ .

$f (\frac{3 x}{8 x - 5}) = \frac{\frac{5 (3 x)}{8 x - 5}}{\frac{24 x}{8 x - 5} - 3 \cdot \frac{8 x - 5}{8 x - 5}}$

Combine $- 3$ and $\frac{8 x - 5}{8 x - 5}$ .

$f (\frac{3 x}{8 x - 5}) = \frac{\frac{5 (3 x)}{8 x - 5}}{\frac{24 x}{8 x - 5} + \frac{- 3 (8 x - 5)}{8 x - 5}}$

Combine the numerators over the common denominator.

$f (\frac{3 x}{8 x - 5}) = \frac{\frac{5 (3 x)}{8 x - 5}}{\frac{24 x - 3 (8 x - 5)}{8 x - 5}}$

Rewrite $\frac{24 x - 3 (8 x - 5)}{8 x - 5}$ in a factored form.

Factor $3$ out of $24 x - 3 (8 x - 5)$ .

Factor $3$ out of $24 x$ .

$f (\frac{3 x}{8 x - 5}) = \frac{\frac{5 (3 x)}{8 x - 5}}{\frac{3 (8 x) - 3 (8 x - 5)}{8 x - 5}}$

Factor $3$ out of $- 3 (8 x - 5)$ .

$f (\frac{3 x}{8 x - 5}) = \frac{\frac{5 (3 x)}{8 x - 5}}{\frac{3 (8 x) + 3 (- (8 x - 5))}{8 x - 5}}$

Factor $3$ out of $3 (8 x) + 3 (- (8 x - 5))$ .

$f (\frac{3 x}{8 x - 5}) = \frac{\frac{5 (3 x)}{8 x - 5}}{\frac{3 (8 x - (8 x - 5))}{8 x - 5}}$

Apply the distributive property.

$f (\frac{3 x}{8 x - 5}) = \frac{\frac{5 (3 x)}{8 x - 5}}{\frac{3 (8 x - (8 x) + 5)}{8 x - 5}}$

Multiply $8$ by $- 1$ .

$f (\frac{3 x}{8 x - 5}) = \frac{\frac{5 (3 x)}{8 x - 5}}{\frac{3 (8 x - 8 x + 5)}{8 x - 5}}$

Multiply $- 1$ by $- 5$ .

$f (\frac{3 x}{8 x - 5}) = \frac{\frac{5 (3 x)}{8 x - 5}}{\frac{3 (8 x - 8 x + 5)}{8 x - 5}}$

Subtract $8 x$ from $8 x$ .

$f (\frac{3 x}{8 x - 5}) = \frac{\frac{5 (3 x)}{8 x - 5}}{\frac{3 (0 + 5)}{8 x - 5}}$

Add $0$ and $5$ .

$f (\frac{3 x}{8 x - 5}) = \frac{\frac{5 (3 x)}{8 x - 5}}{\frac{3 \cdot 5}{8 x - 5}}$

Multiply $3$ by $5$ .

$f (\frac{3 x}{8 x - 5}) = \frac{\frac{5 (3 x)}{8 x - 5}}{\frac{15}{8 x - 5}}$

Multiply $5$ by $3$ .

$f (\frac{3 x}{8 x - 5}) = \frac{\frac{15 x}{8 x - 5}}{\frac{15}{8 x - 5}}$

Multiply the numerator by the reciprocal of the denominator.

$f (\frac{3 x}{8 x - 5}) = \frac{15 x}{8 x - 5} \cdot \frac{8 x - 5}{15}$

Cancel the common factor of $15$ .

Factor $15$ out of $15 x$ .

$f (\frac{3 x}{8 x - 5}) = \frac{15 (x)}{8 x - 5} \cdot \frac{8 x - 5}{15}$

Cancel the common factor.

$f (\frac{3 x}{8 x - 5}) = \frac{15 x}{8 x - 5} \cdot \frac{8 x - 5}{15}$

Rewrite the expression.

$f (\frac{3 x}{8 x - 5}) = \frac{x}{8 x - 5} \cdot (8 x - 5)$

Cancel the common factor of $8 x - 5$ .

Cancel the common factor.

$f (\frac{3 x}{8 x - 5}) = \frac{x}{8 x - 5} \cdot (8 x - 5)$

Rewrite the expression.

$f (\frac{3 x}{8 x - 5}) = x$

Since $f^{- 1} (f (x)) = x$ and $f (f^{- 1} (x)) = x$ , then $f^{- 1} (x) = \frac{3 x}{8 x - 5}$ is the inverse of $f (x) = \frac{5 x}{8 x - 3}$ .

$f^{- 1} (x) = \frac{3 x}{8 x - 5}$

Find the Inverse (5x)/(8x-3)

Related Questions

Support LCMGCF.com by disabling your adblocker.