Find the Inverse (6x-4)/(2-x)

$\frac{6 x - 4}{2 - x}$

Step 1

Interchange the variables.

$x = \frac{6 y - 4}{2 - y}$

Step 2

Solve for $y$ .

Rewrite the equation as $\frac{6 y - 4}{2 - y} = x$ .

$\frac{6 y - 4}{2 - y} = x$

Factor $2$ out of $6 y - 4$ .

Factor $2$ out of $6 y$ .

$\frac{2 (3 y) - 4}{2 - y} = x$

Factor $2$ out of $- 4$ .

$\frac{2 (3 y) + 2 (- 2)}{2 - y} = x$

Factor $2$ out of $2 (3 y) + 2 (- 2)$ .

$\frac{2 (3 y - 2)}{2 - y} = x$

Find the LCD of the terms in the equation.

Finding the LCD of a list of values is the same as finding the LCM of the denominators of those values.

$2 - y, 1$

Remove parentheses.

$2 - y, 1$

The LCM of one and any expression is the expression.

$2 - y$

Multiply each term in $\frac{2 (3 y - 2)}{2 - y} = x$ by $2 - y$ to eliminate the fractions.

Multiply each term in $\frac{2 (3 y - 2)}{2 - y} = x$ by $2 - y$ .

$\frac{2 (3 y - 2)}{2 - y} (2 - y) = x (2 - y)$

Simplify the left side.

Cancel the common factor of $2 - y$ .

Cancel the common factor.

$\frac{2 (3 y - 2)}{2 - y} (2 - y) = x (2 - y)$

Rewrite the expression.

$2 (3 y - 2) = x (2 - y)$

Apply the distributive property.

$2 (3 y) + 2 \cdot - 2 = x (2 - y)$

Multiply.

Multiply $3$ by $2$ .

$6 y + 2 \cdot - 2 = x (2 - y)$

Multiply $2$ by $- 2$ .

$6 y - 4 = x (2 - y)$

Simplify the right side.

Apply the distributive property.

$6 y - 4 = x \cdot 2 + x (- y)$

Reorder.

Move $2$ to the left of $x$ .

$6 y - 4 = 2 \cdot x + x (- y)$

Rewrite using the commutative property of multiplication.

$6 y - 4 = 2 x - x y$

Solve the equation.

Add $x y$ to both sides of the equation.

$6 y - 4 + x y = 2 x$

Add $4$ to both sides of the equation.

$6 y + x y = 2 x + 4$

Factor $y$ out of $6 y + x y$ .

Factor $y$ out of $6 y$ .

$y \cdot 6 + x y = 2 x + 4$

Factor $y$ out of $x y$ .

$y \cdot 6 + y x = 2 x + 4$

Factor $y$ out of $y \cdot 6 + y x$ .

$y (6 + x) = 2 x + 4$

Divide each term in $y (6 + x) = 2 x + 4$ by $6 + x$ and simplify.

Divide each term in $y (6 + x) = 2 x + 4$ by $6 + x$ .

$\frac{y (6 + x)}{6 + x} = \frac{2 x}{6 + x} + \frac{4}{6 + x}$

Simplify the left side.

Cancel the common factor of $6 + x$ .

Cancel the common factor.

$\frac{y (6 + x)}{6 + x} = \frac{2 x}{6 + x} + \frac{4}{6 + x}$

Divide $y$ by $1$ .

$y = \frac{2 x}{6 + x} + \frac{4}{6 + x}$

Simplify the right side.

Combine the numerators over the common denominator.

$y = \frac{2 x + 4}{6 + x}$

Factor $2$ out of $2 x + 4$ .

Factor $2$ out of $2 x$ .

$y = \frac{2 (x) + 4}{6 + x}$

Factor $2$ out of $4$ .

$y = \frac{2 x + 2 \cdot 2}{6 + x}$

Factor $2$ out of $2 x + 2 \cdot 2$ .

$y = \frac{2 (x + 2)}{6 + x}$

Step 3

Replace $y$ with $f^{- 1} (x)$ to show the final answer.

$f^{- 1} (x) = \frac{2 (x + 2)}{6 + x}$

Step 4

Verify if $f^{- 1} (x) = \frac{2 (x + 2)}{6 + x}$ is the inverse of $f (x) = \frac{6 x - 4}{2 - x}$ .

To verify the inverse, check if $f^{- 1} (f (x)) = x$ and $f (f^{- 1} (x)) = x$ .

Evaluate $f^{- 1} (f (x))$ .

Set up the composite result function.

$f^{- 1} (f (x))$

Evaluate $f^{- 1} (\frac{6 x - 4}{2 - x})$ by substituting in the value of $f$ into $f^{- 1}$ .

$f^{- 1} (\frac{6 x - 4}{2 - x}) = \frac{2 ((\frac{6 x - 4}{2 - x}) + 2)}{6 + \frac{6 x - 4}{2 - x}}$

Simplify with factoring out.

Remove parentheses.

$f^{- 1} (\frac{6 x - 4}{2 - x}) = \frac{2 ((\frac{6 x - 4}{2 - x}) + 2)}{6 + \frac{6 x - 4}{2 - x}}$

Factor $2$ out of $6 x - 4$ .

Factor $2$ out of $6 x$ .

$f^{- 1} (\frac{6 x - 4}{2 - x}) = \frac{2 (\frac{2 (3 x) - 4}{2 - x} + 2)}{6 + \frac{6 x - 4}{2 - x}}$

Factor $2$ out of $- 4$ .

$f^{- 1} (\frac{6 x - 4}{2 - x}) = \frac{2 (\frac{2 (3 x) + 2 (- 2)}{2 - x} + 2)}{6 + \frac{6 x - 4}{2 - x}}$

Factor $2$ out of $2 (3 x) + 2 (- 2)$ .

$f^{- 1} (\frac{6 x - 4}{2 - x}) = \frac{2 (\frac{2 (3 x - 2)}{2 - x} + 2)}{6 + \frac{6 x - 4}{2 - x}}$

Factor $2$ out of $6 x - 4$ .

Factor $2$ out of $6 x$ .

$f^{- 1} (\frac{6 x - 4}{2 - x}) = \frac{2 (\frac{2 (3 x - 2)}{2 - x} + 2)}{6 + \frac{2 (3 x) - 4}{2 - x}}$

Factor $2$ out of $- 4$ .

$f^{- 1} (\frac{6 x - 4}{2 - x}) = \frac{2 (\frac{2 (3 x - 2)}{2 - x} + 2)}{6 + \frac{2 (3 x) + 2 (- 2)}{2 - x}}$

Factor $2$ out of $2 (3 x) + 2 (- 2)$ .

$f^{- 1} (\frac{6 x - 4}{2 - x}) = \frac{2 (\frac{2 (3 x - 2)}{2 - x} + 2)}{6 + \frac{2 (3 x - 2)}{2 - x}}$

Simplify the numerator.

To write $2$ as a fraction with a common denominator, multiply by $\frac{2 - x}{2 - x}$ .

$f^{- 1} (\frac{6 x - 4}{2 - x}) = \frac{2 (\frac{2 (3 x - 2)}{2 - x} + \frac{2 (2 - x)}{2 - x})}{6 + \frac{2 (3 x - 2)}{2 - x}}$

Combine the numerators over the common denominator.

$f^{- 1} (\frac{6 x - 4}{2 - x}) = \frac{2 (\frac{2 (3 x - 2) + 2 (2 - x)}{2 - x})}{6 + \frac{2 (3 x - 2)}{2 - x}}$

Reorder terms.

$f^{- 1} (\frac{6 x - 4}{2 - x}) = \frac{2 (\frac{2 (3 x - 2) + 2 (2 - x)}{- x + 2})}{6 + \frac{2 (3 x - 2)}{2 - x}}$

Rewrite $\frac{2 (3 x - 2) + 2 (2 - x)}{- x + 2}$ in a factored form.

Factor $2$ out of $2 (3 x - 2) + 2 (2 - x)$ .

$f^{- 1} (\frac{6 x - 4}{2 - x}) = \frac{2 (\frac{2 (3 x - 2 + 2 - x)}{- x + 2})}{6 + \frac{2 (3 x - 2)}{2 - x}}$

Subtract $x$ from $3 x$ .

$f^{- 1} (\frac{6 x - 4}{2 - x}) = \frac{2 (\frac{2 (2 x - 2 + 2)}{- x + 2})}{6 + \frac{2 (3 x - 2)}{2 - x}}$

Add $- 2$ and $2$ .

$f^{- 1} (\frac{6 x - 4}{2 - x}) = \frac{2 (\frac{2 (2 x + 0)}{- x + 2})}{6 + \frac{2 (3 x - 2)}{2 - x}}$

Add $2 x$ and $0$ .

$f^{- 1} (\frac{6 x - 4}{2 - x}) = \frac{2 (\frac{2 \cdot (2 x)}{- x + 2})}{6 + \frac{2 (3 x - 2)}{2 - x}}$

Multiply $2$ by $2$ .

$f^{- 1} (\frac{6 x - 4}{2 - x}) = \frac{2 (\frac{4 x}{- x + 2})}{6 + \frac{2 (3 x - 2)}{2 - x}}$

Simplify the denominator.

To write $6$ as a fraction with a common denominator, multiply by $\frac{2 - x}{2 - x}$ .

$f^{- 1} (\frac{6 x - 4}{2 - x}) = \frac{2 (\frac{4 x}{- x + 2})}{\frac{6 (2 - x)}{2 - x} + \frac{2 (3 x - 2)}{2 - x}}$

Combine the numerators over the common denominator.

$f^{- 1} (\frac{6 x - 4}{2 - x}) = \frac{2 (\frac{4 x}{- x + 2})}{\frac{6 (2 - x) + 2 (3 x - 2)}{2 - x}}$

Reorder terms.

$f^{- 1} (\frac{6 x - 4}{2 - x}) = \frac{2 (\frac{4 x}{- x + 2})}{\frac{6 (2 - x) + 2 (3 x - 2)}{- x + 2}}$

Rewrite $\frac{6 (2 - x) + 2 (3 x - 2)}{- x + 2}$ in a factored form.

Factor $2$ out of $6 (2 - x) + 2 (3 x - 2)$ .

Factor $2$ out of $6 (2 - x)$ .

$f^{- 1} (\frac{6 x - 4}{2 - x}) = \frac{2 (\frac{4 x}{- x + 2})}{\frac{2 (3 (2 - x)) + 2 (3 x - 2)}{- x + 2}}$

Factor $2$ out of $2 (3 (2 - x)) + 2 (3 x - 2)$ .

$f^{- 1} (\frac{6 x - 4}{2 - x}) = \frac{2 (\frac{4 x}{- x + 2})}{\frac{2 (3 (2 - x) + 3 x - 2)}{- x + 2}}$

Apply the distributive property.

$f^{- 1} (\frac{6 x - 4}{2 - x}) = \frac{2 (\frac{4 x}{- x + 2})}{\frac{2 (3 \cdot 2 + 3 (- x) + 3 x - 2)}{- x + 2}}$

Multiply $3$ by $2$ .

$f^{- 1} (\frac{6 x - 4}{2 - x}) = \frac{2 (\frac{4 x}{- x + 2})}{\frac{2 (6 + 3 (- x) + 3 x - 2)}{- x + 2}}$

Multiply $- 1$ by $3$ .

$f^{- 1} (\frac{6 x - 4}{2 - x}) = \frac{2 (\frac{4 x}{- x + 2})}{\frac{2 (6 - 3 x + 3 x - 2)}{- x + 2}}$

Subtract $2$ from $6$ .

$f^{- 1} (\frac{6 x - 4}{2 - x}) = \frac{2 (\frac{4 x}{- x + 2})}{\frac{2 (- 3 x + 3 x + 4)}{- x + 2}}$

Add $- 3 x$ and $3 x$ .

$f^{- 1} (\frac{6 x - 4}{2 - x}) = \frac{2 (\frac{4 x}{- x + 2})}{\frac{2 (0 + 4)}{- x + 2}}$

Add $0$ and $4$ .

$f^{- 1} (\frac{6 x - 4}{2 - x}) = \frac{2 (\frac{4 x}{- x + 2})}{\frac{2 \cdot 4}{- x + 2}}$

Multiply $2$ by $4$ .

$f^{- 1} (\frac{6 x - 4}{2 - x}) = \frac{2 (\frac{4 x}{- x + 2})}{\frac{8}{- x + 2}}$

Combine $2$ and $\frac{4 x}{- x + 2}$ .

$f^{- 1} (\frac{6 x - 4}{2 - x}) = \frac{\frac{2 (4 x)}{- x + 2}}{\frac{8}{- x + 2}}$

Multiply $2$ by $4$ .

$f^{- 1} (\frac{6 x - 4}{2 - x}) = \frac{\frac{8 x}{- x + 2}}{\frac{8}{- x + 2}}$

Multiply the numerator by the reciprocal of the denominator.

$f^{- 1} (\frac{6 x - 4}{2 - x}) = \frac{8 x}{- x + 2} \cdot \frac{- x + 2}{8}$

Cancel the common factor of $8$ .

Factor $8$ out of $8 x$ .

$f^{- 1} (\frac{6 x - 4}{2 - x}) = \frac{8 (x)}{- x + 2} \cdot \frac{- x + 2}{8}$

Cancel the common factor.

$f^{- 1} (\frac{6 x - 4}{2 - x}) = \frac{8 x}{- x + 2} \cdot \frac{- x + 2}{8}$

Rewrite the expression.

$f^{- 1} (\frac{6 x - 4}{2 - x}) = \frac{x}{- x + 2} \cdot (- x + 2)$

Multiply $\frac{x}{- x + 2}$ by $- x + 2$ .

$f^{- 1} (\frac{6 x - 4}{2 - x}) = \frac{x (- x + 2)}{- x + 2}$

Cancel the common factor of $- x + 2$ .

Cancel the common factor.

$f^{- 1} (\frac{6 x - 4}{2 - x}) = \frac{x (- x + 2)}{- x + 2}$

Divide $x$ by $1$ .

$f^{- 1} (\frac{6 x - 4}{2 - x}) = x$

Evaluate $f (f^{- 1} (x))$ .

Set up the composite result function.

$f (f^{- 1} (x))$

Evaluate $f (\frac{2 (x + 2)}{6 + x})$ by substituting in the value of $f^{- 1}$ into $f$ .

$f (\frac{2 (x + 2)}{6 + x}) = \frac{6 (\frac{2 (x + 2)}{6 + x}) - 4}{2 - (\frac{2 (x + 2)}{6 + x})}$

Cancel the common factor of $6 (\frac{2 (x + 2)}{6 + x}) - 4$ and $2 - (\frac{2 (x + 2)}{6 + x})$ .

Factor $2$ out of $6 (\frac{2 (x + 2)}{6 + x})$ .

$f (\frac{2 (x + 2)}{6 + x}) = \frac{2 (3 (\frac{2 (x + 2)}{6 + x})) - 4}{2 - (\frac{2 (x + 2)}{6 + x})}$

Factor $2$ out of $- 4$ .

$f (\frac{2 (x + 2)}{6 + x}) = \frac{2 (3 (\frac{2 (x + 2)}{6 + x})) + 2 \cdot - 2}{2 - \frac{2 (x + 2)}{6 + x}}$

Factor $2$ out of $2 (3 \frac{2 (x + 2)}{6 + x}) + 2 (- 2)$ .

$f (\frac{2 (x + 2)}{6 + x}) = \frac{2 (3 (\frac{2 (x + 2)}{6 + x}) - 2)}{2 - (\frac{2 (x + 2)}{6 + x})}$

Cancel the common factors.

Factor $2$ out of $2$ .

$f (\frac{2 (x + 2)}{6 + x}) = \frac{2 (3 (\frac{2 (x + 2)}{6 + x}) - 2)}{2 \cdot 1 - \frac{2 (x + 2)}{6 + x}}$

Factor $2$ out of $- \frac{2 (x + 2)}{6 + x}$ .

$f (\frac{2 (x + 2)}{6 + x}) = \frac{2 (3 (\frac{2 (x + 2)}{6 + x}) - 2)}{2 \cdot 1 + 2 (- \frac{x + 2}{6 + x})}$

Factor $2$ out of $2 \cdot 1 + 2 (- \frac{x + 2}{6 + x})$ .

$f (\frac{2 (x + 2)}{6 + x}) = \frac{2 (3 (\frac{2 (x + 2)}{6 + x}) - 2)}{2 \cdot (1 - \frac{x + 2}{6 + x})}$

Cancel the common factor.

$f (\frac{2 (x + 2)}{6 + x}) = \frac{2 (3 (\frac{2 (x + 2)}{6 + x}) - 2)}{2 \cdot (1 - \frac{x + 2}{6 + x})}$

Rewrite the expression.

$f (\frac{2 (x + 2)}{6 + x}) = \frac{3 (\frac{2 (x + 2)}{6 + x}) - 2}{1 - \frac{x + 2}{6 + x}}$

Multiply the numerator and denominator of the complex fraction by $6 + x$ .

Multiply $\frac{3 \frac{2 (x + 2)}{6 + x} - 2}{1 - \frac{x + 2}{6 + x}}$ by $\frac{6 + x}{6 + x}$ .

$f (\frac{2 (x + 2)}{6 + x}) = \frac{6 + x}{6 + x} \cdot \frac{3 (\frac{2 (x + 2)}{6 + x}) - 2}{1 - \frac{x + 2}{6 + x}}$

Combine.

$f (\frac{2 (x + 2)}{6 + x}) = \frac{(6 + x) (3 (\frac{2 (x + 2)}{6 + x}) - 2)}{(6 + x) (1 - \frac{x + 2}{6 + x})}$

Apply the distributive property.

$f (\frac{2 (x + 2)}{6 + x}) = \frac{(6 + x) (3 (\frac{2 (x + 2)}{6 + x})) + (6 + x) \cdot - 2}{(6 + x) \cdot 1 + (6 + x) (- \frac{x + 2}{6 + x})}$

Cancel the common factor of $6 + x$ .

Move the leading negative in $- \frac{x + 2}{6 + x}$ into the numerator.

$f (\frac{2 (x + 2)}{6 + x}) = \frac{(6 + x) (3 (\frac{2 (x + 2)}{6 + x})) + (6 + x) \cdot - 2}{(6 + x) \cdot 1 + (6 + x) (\frac{- (x + 2)}{6 + x})}$

Cancel the common factor.

$f (\frac{2 (x + 2)}{6 + x}) = \frac{(6 + x) (3 (\frac{2 (x + 2)}{6 + x})) + (6 + x) \cdot - 2}{(6 + x) \cdot 1 + (6 + x) (\frac{- (x + 2)}{6 + x})}$

Rewrite the expression.

$f (\frac{2 (x + 2)}{6 + x}) = \frac{(6 + x) (3 (\frac{2 (x + 2)}{6 + x})) + (6 + x) \cdot - 2}{(6 + x) \cdot 1 - (x + 2)}$

Simplify the numerator.

Factor $6 + x$ out of $(6 + x) \cdot 3 \frac{2 (x + 2)}{6 + x} + (6 + x) \cdot - 2$ .

Factor $6 + x$ out of $(6 + x) \cdot 3 \frac{2 (x + 2)}{6 + x}$ .

$f (\frac{2 (x + 2)}{6 + x}) = \frac{(6 + x) (3 (\frac{2 (x + 2)}{6 + x})) + (6 + x) \cdot - 2}{(6 + x) \cdot 1 - (x + 2)}$

Factor $6 + x$ out of $(6 + x) \cdot - 2$ .

$f (\frac{2 (x + 2)}{6 + x}) = \frac{(6 + x) (3 (\frac{2 (x + 2)}{6 + x})) + (6 + x) (- 2)}{(6 + x) \cdot 1 - (x + 2)}$

Factor $6 + x$ out of $(6 + x) (3 \frac{2 (x + 2)}{6 + x}) + (6 + x) (- 2)$ .

$f (\frac{2 (x + 2)}{6 + x}) = \frac{(6 + x) (3 (\frac{2 (x + 2)}{6 + x}) - 2)}{(6 + x) \cdot 1 - (x + 2)}$

Multiply $3 \frac{2 (x + 2)}{6 + x}$ .

Combine $3$ and $\frac{2 (x + 2)}{6 + x}$ .

$f (\frac{2 (x + 2)}{6 + x}) = \frac{(6 + x) (\frac{3 (2 (x + 2))}{6 + x} - 2)}{(6 + x) \cdot 1 - (x + 2)}$

Multiply $2$ by $3$ .

$f (\frac{2 (x + 2)}{6 + x}) = \frac{(6 + x) (\frac{6 (x + 2)}{6 + x} - 2)}{(6 + x) \cdot 1 - (x + 2)}$

To write $- 2$ as a fraction with a common denominator, multiply by $\frac{6 + x}{6 + x}$ .

$f (\frac{2 (x + 2)}{6 + x}) = \frac{(6 + x) (\frac{6 (x + 2)}{6 + x} - 2 \cdot \frac{6 + x}{6 + x})}{(6 + x) \cdot 1 - (x + 2)}$

Combine $- 2$ and $\frac{6 + x}{6 + x}$ .

$f (\frac{2 (x + 2)}{6 + x}) = \frac{(6 + x) (\frac{6 (x + 2)}{6 + x} + \frac{- 2 (6 + x)}{6 + x})}{(6 + x) \cdot 1 - (x + 2)}$

Combine the numerators over the common denominator.

$f (\frac{2 (x + 2)}{6 + x}) = \frac{(6 + x) (\frac{6 (x + 2) - 2 (6 + x)}{6 + x})}{(6 + x) \cdot 1 - (x + 2)}$

Reorder terms.

$f (\frac{2 (x + 2)}{6 + x}) = \frac{(6 + x) (\frac{6 (x + 2) - 2 (6 + x)}{x + 6})}{(6 + x) \cdot 1 - (x + 2)}$

Rewrite $\frac{6 (x + 2) - 2 (6 + x)}{x + 6}$ in a factored form.

Factor $2$ out of $6 (x + 2) - 2 (6 + x)$ .

Factor $2$ out of $6 (x + 2)$ .

$f (\frac{2 (x + 2)}{6 + x}) = \frac{(6 + x) (\frac{2 (3 (x + 2)) - 2 (6 + x)}{x + 6})}{(6 + x) \cdot 1 - (x + 2)}$

Factor $2$ out of $- 2 (6 + x)$ .

$f (\frac{2 (x + 2)}{6 + x}) = \frac{(6 + x) (\frac{2 (3 (x + 2)) + 2 (- (6 + x))}{x + 6})}{(6 + x) \cdot 1 - (x + 2)}$

Factor $2$ out of $2 (3 (x + 2)) + 2 (- (6 + x))$ .

$f (\frac{2 (x + 2)}{6 + x}) = \frac{(6 + x) (\frac{2 (3 (x + 2) - (6 + x))}{x + 6})}{(6 + x) \cdot 1 - (x + 2)}$

Apply the distributive property.

$f (\frac{2 (x + 2)}{6 + x}) = \frac{(6 + x) (\frac{2 (3 x + 3 \cdot 2 - (6 + x))}{x + 6})}{(6 + x) \cdot 1 - (x + 2)}$

Multiply $3$ by $2$ .

$f (\frac{2 (x + 2)}{6 + x}) = \frac{(6 + x) (\frac{2 (3 x + 6 - (6 + x))}{x + 6})}{(6 + x) \cdot 1 - (x + 2)}$

Apply the distributive property.

$f (\frac{2 (x + 2)}{6 + x}) = \frac{(6 + x) (\frac{2 (3 x + 6 - 1 \cdot 6 - x)}{x + 6})}{(6 + x) \cdot 1 - (x + 2)}$

Multiply $- 1$ by $6$ .

$f (\frac{2 (x + 2)}{6 + x}) = \frac{(6 + x) (\frac{2 (3 x + 6 - 6 - x)}{x + 6})}{(6 + x) \cdot 1 - (x + 2)}$

Subtract $x$ from $3 x$ .

$f (\frac{2 (x + 2)}{6 + x}) = \frac{(6 + x) (\frac{2 (2 x + 6 - 6)}{x + 6})}{(6 + x) \cdot 1 - (x + 2)}$

Subtract $6$ from $6$ .

$f (\frac{2 (x + 2)}{6 + x}) = \frac{(6 + x) (\frac{2 (2 x + 0)}{x + 6})}{(6 + x) \cdot 1 - (x + 2)}$

Add $2 x$ and $0$ .

$f (\frac{2 (x + 2)}{6 + x}) = \frac{(6 + x) (\frac{2 \cdot (2 x)}{x + 6})}{(6 + x) \cdot 1 - (x + 2)}$

Multiply $2$ by $2$ .

$f (\frac{2 (x + 2)}{6 + x}) = \frac{(6 + x) (\frac{4 x}{x + 6})}{(6 + x) \cdot 1 - (x + 2)}$

Simplify the denominator.

Multiply $6 + x$ by $1$ .

$f (\frac{2 (x + 2)}{6 + x}) = \frac{(6 + x) (\frac{4 x}{x + 6})}{6 + x - (x + 2)}$

Apply the distributive property.

$f (\frac{2 (x + 2)}{6 + x}) = \frac{(6 + x) (\frac{4 x}{x + 6})}{6 + x - x - 1 \cdot 2}$

Multiply $- 1$ by $2$ .

$f (\frac{2 (x + 2)}{6 + x}) = \frac{(6 + x) (\frac{4 x}{x + 6})}{6 + x - x - 2}$

Subtract $2$ from $6$ .

$f (\frac{2 (x + 2)}{6 + x}) = \frac{(6 + x) (\frac{4 x}{x + 6})}{x - x + 4}$

Subtract $x$ from $x$ .

$f (\frac{2 (x + 2)}{6 + x}) = \frac{(6 + x) (\frac{4 x}{x + 6})}{0 + 4}$

Add $0$ and $4$ .

$f (\frac{2 (x + 2)}{6 + x}) = \frac{(6 + x) (\frac{4 x}{x + 6})}{4}$

Simplify terms.

Factor $\frac{4 x}{x + 6}$ out of $\frac{(6 + x) \frac{4 x}{x + 6}}{4}$ .

$f (\frac{2 (x + 2)}{6 + x}) = \frac{4 x}{x + 6} \cdot \frac{6 + x}{4}$

Cancel the common factor of $4$ .

Factor $4$ out of $4 x$ .

$f (\frac{2 (x + 2)}{6 + x}) = \frac{4 (x)}{x + 6} \cdot \frac{6 + x}{4}$

Cancel the common factor.

$f (\frac{2 (x + 2)}{6 + x}) = \frac{4 x}{x + 6} \cdot \frac{6 + x}{4}$

Rewrite the expression.

$f (\frac{2 (x + 2)}{6 + x}) = \frac{x}{x + 6} \cdot (6 + x)$

Multiply $\frac{x}{x + 6}$ by $6 + x$ .

$f (\frac{2 (x + 2)}{6 + x}) = \frac{x (6 + x)}{x + 6}$

Cancel the common factor of $6 + x$ and $x + 6$ .

Reorder terms.

$f (\frac{2 (x + 2)}{6 + x}) = \frac{x (x + 6)}{x + 6}$

Cancel the common factor.

$f (\frac{2 (x + 2)}{6 + x}) = \frac{x (x + 6)}{x + 6}$

Divide $x$ by $1$ .

$f (\frac{2 (x + 2)}{6 + x}) = x$

Since $f^{- 1} (f (x)) = x$ and $f (f^{- 1} (x)) = x$ , then $f^{- 1} (x) = \frac{2 (x + 2)}{6 + x}$ is the inverse of $f (x) = \frac{6 x - 4}{2 - x}$ .

$f^{- 1} (x) = \frac{2 (x + 2)}{6 + x}$

Find the Inverse (6x-4)/(2-x)

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