Find the Inverse f(x)=18 root of x

$f (x) = \sqrt[18]{x}$

Step 1

Write $f (x) = \sqrt[18]{x}$ as an equation.

$y = \sqrt[18]{x}$

Step 2

Interchange the variables.

$x = \sqrt[18]{y}$

Step 3

Solve for $y$ .

Rewrite the equation as $\sqrt[18]{y} = x$ .

$\sqrt[18]{y} = x$

To remove the radical on the left side of the equation, raise both sides of the equation to the power of $18$ .

${\sqrt[18]{y}}^{18} = x^{18}$

Simplify each side of the equation.

Use $\sqrt[n]{a^{x}} = a^{\frac{x}{n}}$ to rewrite $\sqrt[18]{y}$ as $y^{\frac{1}{18}}$ .

${(y^{\frac{1}{18}})}^{18} = x^{18}$

Simplify the left side.

Simplify ${(y^{\frac{1}{18}})}^{18}$ .

Multiply the exponents in ${(y^{\frac{1}{18}})}^{18}$ .

Apply the power rule and multiply exponents, ${(a^{m})}^{n} = a^{m n}$ .

$y^{\frac{1}{18} \cdot 18} = x^{18}$

Cancel the common factor of $18$ .

Cancel the common factor.

$y^{\frac{1}{18} \cdot 18} = x^{18}$

Rewrite the expression.

$y^{1} = x^{18}$

Simplify.

$y = x^{18}$

Step 4

Replace $y$ with $f^{- 1} (x)$ to show the final answer.

$f^{- 1} (x) = x^{18}$

Step 5

Verify if $f^{- 1} (x) = x^{18}$ is the inverse of $f (x) = \sqrt[18]{x}$ .

To verify the inverse, check if $f^{- 1} (f (x)) = x$ and $f (f^{- 1} (x)) = x$ .

Evaluate $f^{- 1} (f (x))$ .

Set up the composite result function.

$f^{- 1} (f (x))$

Evaluate $f^{- 1} (\sqrt[18]{x})$ by substituting in the value of $f$ into $f^{- 1}$ .

$f^{- 1} (\sqrt[18]{x}) = {(\sqrt[18]{x})}^{18}$

Rewrite ${\sqrt[18]{x}}^{18}$ as $x$ .

Use $\sqrt[n]{a^{x}} = a^{\frac{x}{n}}$ to rewrite $\sqrt[18]{x}$ as $x^{\frac{1}{18}}$ .

$f^{- 1} (\sqrt[18]{x}) = {(x^{\frac{1}{18}})}^{18}$

Apply the power rule and multiply exponents, ${(a^{m})}^{n} = a^{m n}$ .

$f^{- 1} (\sqrt[18]{x}) = x^{\frac{1}{18} \cdot 18}$

Combine $\frac{1}{18}$ and $18$ .

$f^{- 1} (\sqrt[18]{x}) = x^{\frac{18}{18}}$

Cancel the common factor of $18$ .

Cancel the common factor.

$f^{- 1} (\sqrt[18]{x}) = x^{\frac{18}{18}}$

Rewrite the expression.

$f^{- 1} (\sqrt[18]{x}) = x$

Simplify.

$f^{- 1} (\sqrt[18]{x}) = x$

Evaluate $f (f^{- 1} (x))$ .

Set up the composite result function.

$f (f^{- 1} (x))$

Evaluate $f (x^{18})$ by substituting in the value of $f^{- 1}$ into $f$ .

$f (x^{18}) = \sqrt[18]{x^{18}}$

Remove parentheses.

$f (x^{18}) = \sqrt[18]{x^{18}}$

Pull terms out from under the radical, assuming positive real numbers.

$f (x^{18}) = x$

Since $f^{- 1} (f (x)) = x$ and $f (f^{- 1} (x)) = x$ , then $f^{- 1} (x) = x^{18}$ is the inverse of $f (x) = \sqrt[18]{x}$ .

$f^{- 1} (x) = x^{18}$

Find the Inverse f(x)=18 root of x

Related Questions

Support LCMGCF.com by disabling your adblocker.