Find the Inverse f(x)=2x+2

$f (x) = 2 x + 2$

Step 1

Write $f (x) = 2 x + 2$ as an equation.

$y = 2 x + 2$

Step 2

Interchange the variables.

$x = 2 y + 2$

Step 3

Solve for $y$ .

Rewrite the equation as $2 y + 2 = x$ .

$2 y + 2 = x$

Subtract $2$ from both sides of the equation.

$2 y = x - 2$

Divide each term in $2 y = x - 2$ by $2$ and simplify.

Divide each term in $2 y = x - 2$ by $2$ .

$\frac{2 y}{2} = \frac{x}{2} + \frac{- 2}{2}$

Simplify the left side.

Cancel the common factor of $2$ .

Cancel the common factor.

$\frac{2 y}{2} = \frac{x}{2} + \frac{- 2}{2}$

Divide $y$ by $1$ .

$y = \frac{x}{2} + \frac{- 2}{2}$

Simplify the right side.

Divide $- 2$ by $2$ .

$y = \frac{x}{2} - 1$

Step 4

Replace $y$ with $f^{- 1} (x)$ to show the final answer.

$f^{- 1} (x) = \frac{x}{2} - 1$

Step 5

Verify if $f^{- 1} (x) = \frac{x}{2} - 1$ is the inverse of $f (x) = 2 x + 2$ .

To verify the inverse, check if $f^{- 1} (f (x)) = x$ and $f (f^{- 1} (x)) = x$ .

Evaluate $f^{- 1} (f (x))$ .

Set up the composite result function.

$f^{- 1} (f (x))$

Evaluate $f^{- 1} (2 x + 2)$ by substituting in the value of $f$ into $f^{- 1}$ .

$f^{- 1} (2 x + 2) = \frac{2 x + 2}{2} - 1$

Cancel the common factor of $2 x + 2$ and $2$ .

Factor $2$ out of $2 x$ .

$f^{- 1} (2 x + 2) = \frac{2 (x) + 2}{2} - 1$

Factor $2$ out of $2$ .

$f^{- 1} (2 x + 2) = \frac{2 (x) + 2 \cdot 1}{2} - 1$

Factor $2$ out of $2 (x) + 2 (1)$ .

$f^{- 1} (2 x + 2) = \frac{2 (x + 1)}{2} - 1$

Cancel the common factors.

Factor $2$ out of $2$ .

$f^{- 1} (2 x + 2) = \frac{2 (x + 1)}{2 (1)} - 1$

Cancel the common factor.

$f^{- 1} (2 x + 2) = \frac{2 (x + 1)}{2 \cdot 1} - 1$

Rewrite the expression.

$f^{- 1} (2 x + 2) = \frac{x + 1}{1} - 1$

Divide $x + 1$ by $1$ .

$f^{- 1} (2 x + 2) = x + 1 - 1$

Combine the opposite terms in $x + 1 - 1$ .

Subtract $1$ from $1$ .

$f^{- 1} (2 x + 2) = x + 0$

Add $x$ and $0$ .

$f^{- 1} (2 x + 2) = x$

Evaluate $f (f^{- 1} (x))$ .

Set up the composite result function.

$f (f^{- 1} (x))$

Evaluate $f (\frac{x}{2} - 1)$ by substituting in the value of $f^{- 1}$ into $f$ .

$f (\frac{x}{2} - 1) = 2 (\frac{x}{2} - 1) + 2$

Simplify each term.

Apply the distributive property.

$f (\frac{x}{2} - 1) = 2 (\frac{x}{2}) + 2 \cdot - 1 + 2$

Cancel the common factor of $2$ .

Cancel the common factor.

$f (\frac{x}{2} - 1) = 2 (\frac{x}{2}) + 2 \cdot - 1 + 2$

Rewrite the expression.

$f (\frac{x}{2} - 1) = x + 2 \cdot - 1 + 2$

Multiply $2$ by $- 1$ .

$f (\frac{x}{2} - 1) = x - 2 + 2$

Combine the opposite terms in $x - 2 + 2$ .

Add $- 2$ and $2$ .

$f (\frac{x}{2} - 1) = x + 0$

Add $x$ and $0$ .

$f (\frac{x}{2} - 1) = x$

Since $f^{- 1} (f (x)) = x$ and $f (f^{- 1} (x)) = x$ , then $f^{- 1} (x) = \frac{x}{2} - 1$ is the inverse of $f (x) = 2 x + 2$ .

$f^{- 1} (x) = \frac{x}{2} - 1$

Find the Inverse f(x)=2x+2

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