Find the Inverse f(x)=x-2

$f (x) = x - 2$

Step 1

Write $f (x) = x - 2$ as an equation.

$y = x - 2$

Step 2

Interchange the variables.

$x = y - 2$

Step 3

Solve for $y$ .

Rewrite the equation as $y - 2 = x$ .

$y - 2 = x$

Add $2$ to both sides of the equation.

$y = x + 2$

Step 4

Replace $y$ with $f^{- 1} (x)$ to show the final answer.

$f^{- 1} (x) = x + 2$

Step 5

Verify if $f^{- 1} (x) = x + 2$ is the inverse of $f (x) = x - 2$ .

To verify the inverse, check if $f^{- 1} (f (x)) = x$ and $f (f^{- 1} (x)) = x$ .

Evaluate $f^{- 1} (f (x))$ .

Set up the composite result function.

$f^{- 1} (f (x))$

Evaluate $f^{- 1} (x - 2)$ by substituting in the value of $f$ into $f^{- 1}$ .

$f^{- 1} (x - 2) = (x - 2) + 2$

Combine the opposite terms in $(x - 2) + 2$ .

Add $- 2$ and $2$ .

$f^{- 1} (x - 2) = x + 0$

Add $x$ and $0$ .

$f^{- 1} (x - 2) = x$

Evaluate $f (f^{- 1} (x))$ .

Set up the composite result function.

$f (f^{- 1} (x))$

Evaluate $f (x + 2)$ by substituting in the value of $f^{- 1}$ into $f$ .

$f (x + 2) = (x + 2) - 2$

Combine the opposite terms in $(x + 2) - 2$ .

Subtract $2$ from $2$ .

$f (x + 2) = x + 0$

Add $x$ and $0$ .

$f (x + 2) = x$

Since $f^{- 1} (f (x)) = x$ and $f (f^{- 1} (x)) = x$ , then $f^{- 1} (x) = x + 2$ is the inverse of $f (x) = x - 2$ .

$f^{- 1} (x) = x + 2$