Find the Inverse |x|

$| x |$

Interchange the variables.

$x = | y |$

Solve for $y$ .

Rewrite the equation as $| y | = x$ .

$| y | = x$

Remove the absolute value term. This creates a $\pm$ on the right side of the equation because $| x | = \pm x$ .

$y = \pm x$

The complete solution is the result of both the positive and negative portions of the solution.

First, use the positive value of the $\pm$ to find the first solution.

$y = x$

Next, use the negative value of the $\pm$ to find the second solution.

$y = - x$

The complete solution is the result of both the positive and negative portions of the solution.

$y = x$

$y = - x$

$y = x$

$y = - x$

$y = x$

$y = - x$

Replace $y$ with $f^{- 1} (x)$ to show the final answer.

$f^{- 1} (x) = x, - x$

Verify if $f^{- 1} (x) = x, - x$ is the inverse of $f (x) = | x |$ .

The domain of the inverse is the range of the original function and vice versa. Find the domain and the range of $f (x) = | x |$ and $f^{- 1} (x) = x, - x$ and compare them.

Find the range of $f (x) = | x |$ .

The range is the set of all valid $y$ values. Use the graph to find the range.

Interval Notation:

$[0, \infty)$

Find the domain of $x$ .

The domain of the expression is all real numbers except where the expression is undefined. In this case, there is no real number that makes the expression undefined.

$(- \infty, \infty)$

Since the domain of $f^{- 1} (x) = x, - x$ is not equal to the range of $f (x) = | x |$ , then $f^{- 1} (x) = x, - x$ is not an inverse of $f (x) = | x |$ .

There is no inverse

Find the Inverse |x|

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